英文:
how can i add this two python scripts together?
问题
# 这是我的Python脚本,看起来像这样:
New_folder = "C:\Songs"
arr_txt = [x for x in os.listdir(New_folder) if x.endswith(".mp3")]
testfile = [New_folder]
for i in range(len(testfile)):
for x in testfile:
print(*arr_txt, sep="\n")
print()
# 我想要添加的第二部分是一个字母转换器,其脚本如下:
from unidecode import unidecode
s = "" # 这里的脚本 <---
s = unidecode(s)
print(s)
# 所以我希望第二部分与第一个脚本连接起来,第一个脚本的任何结果都传递到第二个脚本,以便进行转换
英文:
so i have this python script which looks like this:
New_folder = "C:\Songs"
arr_txt = [x for x in os.listdir(New_folder) if x.endswith(".mp3")]
testfile = [New_folder]
for i in range(len(testfile)):
for x in testfile:
print(*arr_txt, sep="\n")
print()
which reads all the names of the files in my directory.
and the second part i want to add is a letter converter which it's script looks like:
from unidecode import unidecode
s = "" #the script in there <---
s = unidecode(s)
print(s)
so I want the second part to connect with the first script and whatever result is coming out of the first script to go into the second script so that it gets converted
答案1
得分: 1
你可以在Python中使用函数。
在一个文件中,让我们称之为 extract.py
,你应该指定其他脚本要使用的预定义方法,例如:
# extract.py
def get_file_names():
New_folder = "C:\Songs"
arr_txt = [x for x in os.listdir(New_folder) if x.endswith(".mp3")]
return arr_txt # 这对调用者来处理提取的值非常重要
然后在另一个文件中,比如说 process.py
,你可以从 extract.py
中调用你想要使用的方法。这可以通过 import
来实现:
# process.py
from extract import get_file_names
from unidecode import unidecode
s = get_file_names()
for file_name in s:
print(unidecode(file_name))
这个解决方案应该适用于使用最新的Python解释器。请注意,在Python 2.x 中,import
的工作方式略有不同。
英文:
You can utilise functions in Python.
In one file, let's call this extract.py
, you should specify the pre-defined method for other scripts to use, e.g.
# extract.py
def get_file_names():
New_folder = "C:\Songs"
arr_txt = [x for x in os.listdir(New_folder) if x.endswith(".mp3")]
return arr_txt # this is important for caller to process the extracted value
And then in another file, let's say process.py
, you call the method you want to use from extract.py
. This can be done using import
# process.py
from extract import get_file_names
from unidecode import unidecode
s = get_file_names()
for file_name in s:
print(unidecode(filename))
This solution should work for using the latest Python interpreter. Please do note that import
works slightly different in Python 2.x.
答案2
得分: 0
以下是翻译好的代码部分:
from unidecode import unidecode
def playmusic():
New_folder = "C:\Songs"
arr_txt = [x for x in os.listdir(New_folder) if x.endswith(".mp3")]
testfile = [New_folder]
for i in range(len(testfile)):
for x in testfile:
print(*arr_txt, sep="\n")
print()
playmusic()
s = ""
s = unidecode(s)
print(s)
英文:
Something like below
from unidecode import unidecode
def playmusic():
New_folder = "C:\Songs"
arr_txt = [x for x in os.listdir(New_folder) if x.endswith(".mp3")]
testfile = [New_folder]
for i in range(len(testfile)):
for x in testfile:
print(*arr_txt, sep="\n")
print()
playmusic()
s = ""
s = unidecode(s)
print(s)
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