如何从SPSS文件中的数据框中使用标签替换值?

huangapple go评论111阅读模式
英文:

How to replace values by labels in data.frames from spss files?

问题

我必须读取一个.sav文件
我使用了haven

library(haven)
dataset <- read_sav("datafile.sav")

在控制台中,我可以看到标签:

如何从SPSS文件中的数据框中使用标签替换值?

dput(head(voyages$portdep))
structure(c(50422, 50299, 50299, 50299, NA, NA), label = "Port of departure", labels = c(Alicante = 10101, 
Barcelona = 10102, Bilbao = 10103, Cadiz = 10104, Figuera = 10105, 
Gibraltar = 10106, `La Coruña` = 10107, Santander = 10110, Seville = 10111, 
`San Lucar` = 10112, Vigo = 10113, `Spain, port unspecified` = 10199, 
Lagos = 10202, Lisbon = 10203, Oporto = 10204, `Ilho do Fayal` = 10205, 
Setubal = 10206, `Portugal, port unspecified` = 10299, `Great Britain, port unspecified` = 10399, 
Barmouth = 10401, Bideford = 10402, Birkenhead = 10403, Bristol = 10404, 
Brixham = 10405, Broadstairs = 10406, Cawsand = 10407, Chepstow = 10408, 
Chester = 10409, Colchester = 10410, Cowes = 10411, Dartmouth = 10412, 
Deptford = 10413, Dover = 10414, Exeter = 10415, Folkstone = 10416, 
Frodsham = 10417, Gainsborough = 10418, Greenwich = 10419, Guernsey = 10420, 
Harwich = 10421, Hull = 10422, Ilfracombe = 10423, Ipswich = 10424, 
`Isle of Man` = 10425, `Isle of Wight` = 10426, Jersey = 10427, 
Kendal = 10428, `King's Lynn` = 10429, Lancaster = 10430, Lindale = 10431, 
Liverpool = 10432, London = 10433, Lyme = 10434, Maryport = 10436, 
`Milford Haven` = 10437, `New Shoreham` = 10438, `Newcastle upon Tyne` = 10439, 
Newnham = 10440, `North Shields` = 10441, Norwich = 10443, Padstowe = 10444, 
Parkgate = 10445, `Piel of Foulney` = 10446, Plymouth = 10447, 
Poole = 10448, Portsery = 10449, Portsmouth = 10450, Poulton = 10451, 
Preston = 10452, Ramsgate = 10453, Ravenglass = 10454, `River Thames` = 10455, 
Rochester = 10456, Rotherhithe = 10457, Rye = 10458, Scarborough = 10459, 
Sheerness = 10460, Shields = 10461, Shoreham = 10462, Sidmouth = 10463, 
Southampton = 10464, Stockton = 10466, Stockwithe = 10467, Sunderland = 10468, 
Teignmouth = 10469, Topsham = 10470, Torbay = 10471, Wales = 10472, 
)

在HTML表格中,我只有值:

如何从SPSS文件中的数据框中使用标签替换值?

如何在来自SPSS文件的数据框中用标签替换值以在HTML表格中显示?

使用sjlabelled包,我可以获取任何列的标签:

library(sjlabelled)
get_labels(voyages$portdep)

1] "Alicante" "Barcelona" "Bilbao" "Cadiz"
[5] "Figuera" "Gibraltar" "La Coruña" "Santander"
[9] "Seville" "San Lucar" "Vigo" "Spain, port unspecified"
[13] "Lagos" "Lisbon" "Oporto" "Ilho do Fayal"
[17] "Setubal" "Portugal, port unspecified" "Great Britain, port unspecified" "Barmouth"
[21] "Bideford" "Birkenhead" "Bristol" "Brixham"
[25] "Broadstairs" "Cawsand" "Chepstow" "Chester"
[29] "Colchester" "Cowes" "Dartmouth" "Deptford"
[33] "Dover" "Exeter" "Folkstone" "Frodsham"
[37] "Gainsborough" "Greenwich" "Guernsey" "Harwich"
[41] "Hull" "Ilfracombe" "Ipswich" "Isle of Man"
[45] "Isle of Wight" "Jersey" "Kendal" "King's Lynn"

我尝试过:

对于单个列:

dataset2 <- dataset %>% mutate(portdep = get_labels(portdep))

错误:列 portdep 必须是长度为36002(行数)或一个,而不是847

对于整个数据框:

dataset2 <- dataset %>% mutate_all(funs(get_labels(.)))

在第一列上出现相同的错误:

列 xxx 必须是长度为36002(行数)或一个,而不是2

英文:

I have to read a sav file
I use the package haven

library(haven)
dataset&lt;- read_sav(&quot;datafile.sav&quot;)

In the console I can see the labels :

如何从SPSS文件中的数据框中使用标签替换值?

		dput(head(voyages$portdep))
structure(c(50422, 50299, 50299, 50299, NA, NA), label = &quot;Port of departure&quot;, labels = c(Alicante = 10101, 
Barcelona = 10102, Bilbao = 10103, Cadiz = 10104, Figuera = 10105, 
Gibraltar = 10106, `La Coru&#241;a` = 10107, Santander = 10110, Seville = 10111, 
`San Lucar` = 10112, Vigo = 10113, `Spain, port unspecified` = 10199, 
Lagos = 10202, Lisbon = 10203, Oporto = 10204, `Ilho do Fayal` = 10205, 
Setubal = 10206, `Portugal, port unspecified` = 10299, `Great Britain, port unspecified` = 10399, 
Barmouth = 10401, Bideford = 10402, Birkenhead = 10403, Bristol = 10404, 
Brixham = 10405, Broadstairs = 10406, Cawsand = 10407, Chepstow = 10408, 
Chester = 10409, Colchester = 10410, Cowes = 10411, Dartmouth = 10412, 
Deptford = 10413, Dover = 10414, Exeter = 10415, Folkstone = 10416, 
Frodsham = 10417, Gainsborough = 10418, Greenwich = 10419, Guernsey = 10420, 
Harwich = 10421, Hull = 10422, Ilfracombe = 10423, Ipswich = 10424, 
`Isle of Man` = 10425, `Isle of Wight` = 10426, Jersey = 10427, 
Kendal = 10428, `King&#39;s Lynn` = 10429, Lancaster = 10430, Lindale = 10431, 
Liverpool = 10432, London = 10433, Lyme = 10434, Maryport = 10436, 
`Milford Haven` = 10437, `New Shoreham` = 10438, `Newcastle upon Tyne` = 10439, 
Newnham = 10440, `North Shields` = 10441, Norwich = 10443, Padstowe = 10444, 
Parkgate = 10445, `Piel of Foulney` = 10446, Plymouth = 10447, 
Poole = 10448, Portsery = 10449, Portsmouth = 10450, Poulton = 10451, 
Preston = 10452, Ramsgate = 10453, Ravenglass = 10454, `River Thames` = 10455, 
Rochester = 10456, Rotherhithe = 10457, Rye = 10458, Scarborough = 10459, 
Sheerness = 10460, Shields = 10461, Shoreham = 10462, Sidmouth = 10463, 
Southampton = 10464, Stockton = 10466, Stockwithe = 10467, Sunderland = 10468, 
Teignmouth = 10469, Topsham = 10470, Torbay = 10471, Wales = 10472, 

In html table, I have only the values :

如何从SPSS文件中的数据框中使用标签替换值?

How to replace values by labels in data.frames from spss files ?for displaying in html table ?

using sjlabelled package, I can get labels of any column :

library(sjlabelled)
get_labels(voyages$portdep)

1] "Alicante" "Barcelona" "Bilbao" "Cadiz"
[5] "Figuera" "Gibraltar" "La Coruña" "Santander"
[9] "Seville" "San Lucar" "Vigo" "Spain, port unspecified"
[13] "Lagos" "Lisbon" "Oporto" "Ilho do Fayal"
[17] "Setubal" "Portugal, port unspecified" "Great Britain, port unspecified" "Barmouth"
[21] "Bideford" "Birkenhead" "Bristol" "Brixham"
[25] "Broadstairs" "Cawsand" "Chepstow" "Chester"
[29] "Colchester" "Cowes" "Dartmouth" "Deptford"
[33] "Dover" "Exeter" "Folkstone" "Frodsham"
[37] "Gainsborough" "Greenwich" "Guernsey" "Harwich"
[41] "Hull" "Ilfracombe" "Ipswich" "Isle of Man"
[45] "Isle of Wight" "Jersey" "Kendal" "King's Lynn"

I tried :

On a single column :

  dataset2 &lt;- dataset %&gt;% mutate(portdep = get_labels(portdep))

> Erreur : Column portdep must be length 36002 (the number of rows) or
> one, not 847

On all the dataframe :

  dataset2 &lt;-  dataset %&gt;% mutate_all(funs(get_labels(.)))

With the same error on first column :

> Column xxx must be length 36002 (the number of rows) or one, not 2

答案1

得分: 5

我认为你可以使用 haven::as_factor 来获取你正在寻找的内容。

这个工作吗?

library(haven)
library(dplyr)

dataset %>%
  mutate_all(as_factor) %>%
  head() %>%
  View()
英文:

I think you can get what you're looking for by using haven::as_factor.

Does this work?

library(haven)
library(dplyr)

dataset %&gt;% 
  mutate_all(as_factor) %&gt;%
  head() %&gt;%
  View()

答案2

得分: 2

不使用 haven 包,你可以尝试使用 foreign。我使用了自己的数据 try.sav,其中包括一个名为 gender 的变量:

library(haven)
df_haven<- read_sav("try.sav")
class(df_haven$gender)
#> [1] "haven_labelled"
table(df_haven$gender)
#> 
#>    1    2 
#> 1972 2417
df_haven$gender
#> <Labelled double>: Gender
#>    [1] 2 2 2 1 2 2 2 2 2 2 2 2 2 1 2 2 2 2 2 1 2 2 2 2 2 2 1 1 1 1 2 2 2 2 2 2 2
#>   [38] 2 2 2 1 2 2 1 2 2 2 2 2 2 2 2 1 2 2 2 2 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
#>   [75] 2 2 1 1 2 2 1 2 1 2 1 1 2 1 2 1 1 2 2 2 2 2 1 1 2 2 1 2 1 2 2 2 1 1 2 2 1
#> ...
#> Labels:
#>  value  label
#>      1   male
#>      2 female

library(foreign)
df_foreign<- read.spss("try.sav", to.data.frame = TRUE) 
#> re-encoding from UTF-8
class(df_foreign$gender)
#> [1] "factor"
table(df_foreign$gender)
#> 
#>   male female 
#>   1972   2417
df_foreign$gender
#>    [1] female female female male   female female female female female female
#>   [11] female female female male   female female female female female male  
#>   [21] female female female female female female male   male   male   male  
#>   [31] female female female female female female female female female female
#>   [41] male   female female male   female female female female female female
#>   [51] female female male   female female female female male   female female
#>   [61] female female female female female female female female female female
#>   [71] female female female female female female male   male   female female
#>   [81] male   female male   female male   male   female male   female male  
#>   [91] male   female female female female female male   male   female female
#> ...
#> Levels: male female

2020-01-06 由 reprex package (v0.3.0) 创建

英文:

Instead of using haven package, you could try foreign. I used my own data try.sav including a variable gender:

library(haven)
df_haven&lt;- read_sav(&quot;try.sav&quot;)
class(df_haven$gender)
#&gt; [1] &quot;haven_labelled&quot;
table(df_haven$gender)
#&gt; 
#&gt;    1    2 
#&gt; 1972 2417
df_haven$gender
#&gt; &lt;Labelled double&gt;: Gender
#&gt;    [1] 2 2 2 1 2 2 2 2 2 2 2 2 2 1 2 2 2 2 2 1 2 2 2 2 2 2 1 1 1 1 2 2 2 2 2 2 2
#&gt;   [38] 2 2 2 1 2 2 1 2 2 2 2 2 2 2 2 1 2 2 2 2 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
#&gt;   [75] 2 2 1 1 2 2 1 2 1 2 1 1 2 1 2 1 1 2 2 2 2 2 1 1 2 2 1 2 1 2 2 2 1 1 2 2 1
#&gt; ...
#&gt; Labels:
#&gt;  value  label
#&gt;      1   male
#&gt;      2 female

library(foreign)
df_foreign&lt;- read.spss(&quot;try.sav&quot;, to.data.frame = TRUE) 
#&gt; re-encoding from UTF-8
class(df_foreign$gender)
#&gt; [1] &quot;factor&quot;
table(df_foreign$gender)
#&gt; 
#&gt;   male female 
#&gt;   1972   2417
df_foreign$gender
#&gt;    [1] female female female male   female female female female female female
#&gt;   [11] female female female male   female female female female female male  
#&gt;   [21] female female female female female female male   male   male   male  
#&gt;   [31] female female female female female female female female female female
#&gt;   [41] male   female female male   female female female female female female
#&gt;   [51] female female male   female female female female male   female female
#&gt;   [61] female female female female female female female female female female
#&gt;   [71] female female female female female female male   male   female female
#&gt;   [81] male   female male   female male   male   female male   female male  
#&gt;   [91] male   female female female female female male   male   female female
....
#&gt; Levels: male female

<sup>Created on 2020-01-06 by the reprex package (v0.3.0)</sup>

答案3

得分: 1

你也可以使用 haven 包中的 as_factor() 函数。

library(haven)
as_factor(df_foreign$gender)
英文:

You could also use as_factor() from haven package.

library(haven)
as_factor(df_foreign$gender)

That should work! Good luck!

huangapple
  • 本文由 发表于 2020年1月6日 17:39:26
  • 转载请务必保留本文链接:https://go.coder-hub.com/59609733.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定