英文:
R: Print A Value from A Column Based on the Corresponding Row of Another Column
问题
在R中，我想打印（作为标量）列Z的最小值对应的列Y的值。例如，由于列Z中的最小值为1.928718，我将选择列Y中相应的行值，即5。以下是代码示例：
df <- read.table(text =
"X Y Z
a 2 3.258206
b 6 2.825460
c 5 1.928718
d 3 3.656937
e 3 2.060350",
header = TRUE)
min_Z_row <- df[which.min(df$Z), "Y"]
min_Z_row 中的值将是5。
英文:
I have this data frame df in R in which I want to print (as a scalar) a value of column Y based on the corresponding row that is the minimum value of column Z. For example, since 1.928718 is the minimum in column Z I will pick the corresponding row value in column Y which is 5.
df <- read.table(text =
"X Y Z
a 2 3.258206
b 6 2.825460
c 5 1.928718
d 3 3.656937
e 3 2.060350",
header = TRUE)
答案1
得分: 0
使用 slice_min
library(dplyr)
df %>%
slice_min(Z) %>%
pull(Y)
[1] 5
英文:
Using slice_min
library(dplyr)
df %>%
slice_min(Z) %>%
pull(Y)
[1] 5
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