如何在MySQL中获取三列的总和?

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英文:

How to get the sum of the three column in MySQL?

问题

问题是如何将单一输出值作为三个不同列值的总和,这三个列值分别是请假总数、病假总数和其他假期总数。以下是获取这个总和的单一查询示例:

SELECT 
    SUM(casual_leave_days) AS casual_leave,
    SUM(vaction_leave_days) AS vaction_leave,
    SUM(other_leave_days) AS other_leave
FROM leaveapplydata
WHERE emp_id = '".$_POST["emp_id"]."' AND
    (casual_holiday_start LIKE '".$passyear."%' OR
    vaction_holiday_start LIKE '".$passyear."%' OR
    other_holiday_start LIKE '".$passyear."%');

这个查询将返回在指定年份($passyear)中的员工的请假总数、病假总数和其他假期总数。请注意,你需要将 $_POST["emp_id"] 替换为你的实际变量值,以匹配特定员工的ID。

英文:

My problem is how to get the single output value as three different column value sum as total sum of the all the column

leave count of casual leave

SELECT SUM(casual_leave_days) AS casual_leave  
                FROM leaveapplydata
                WHERE emp_id = '".$_POST["emp_id"]."' AND casual_holiday_start
                LIKE '$passyear%'

leave count of vaction leave

SELECT SUM(vaction_leave_days) AS vaction_leave 
                FROM leaveapplydata
                WHERE emp_id = '".$_POST["emp_id"]."' AND vaction_holiday_start
                LIKE '$passyear%'

leave count of other leave

SELECT SUM(other_leave_days) AS other_leave 
                FROM leaveapplydata
                WHERE emp_id = '".$_POST["emp_id"]."' AND other_holiday_start
                LIKE '$passyear%'

now i want get total holiday count in pass year using single query.how do i do it?
table structure

tbl_id	emp_id	casual_leave_days	casual_holiday_start	casual_holiday_end	vaction_leave_days	vaction_holiday_start	vaction_holiday_end	other_leave_days	other_holiday_start	other_holiday_end	leave_reason	applicant_sign	actor_sign	supervior_sign	head_sign	
1	23	9	2019-12-23	2019-12-27	0	0000-00-00	0000-00-00	0	0000-00-00	0000-00-00	Private	1	1	1	1	
2	23	2	2019-12-24	2019-12-26	0	0000-00-00	0000-00-00	0	0000-00-00	0000-00-00	Private	1	1	1	1	
3	23	0	0000-00-00	0000-00-00	2	2019-12-28	2019-12-30	0	0000-00-00	0000-00-00	Sickness	1	1	1	1	
4	23	1	2019-12-29	2019-12-30	1	2019-12-30	2019-12-31	0	0000-00-00	0000-00-00	Private	1	1	1	1	
5	25	1	2019-12-30	2019-12-31	0	0000-00-00	0000-00-00	0	0000-00-00	0000-00-00	Other	1	1	1	1	
6	30	1	2020-01-01	2020-01-02	0	0000-00-00	0000-00-00	0	0000-00-00	0000-00-00	Private	1	1	1	1	
7	30	5	2019-11-04	2019-11-11	0	0000-00-00	0000-00-00	0	0000-00-00	0000-00-00	Private	1	1	1	1	
8	23	1	2020-01-02	2020-01-03	0	0000-00-00	0000-00-00	0	0000-00-00	0000-00-00	Sickness	1	1	1	1	

答案1

得分: 1

Summing is commutative, so you could add the three fields and then sum them:

SELECT SUM(casual_leave_days + vacation_leave_days + other_leave_days) AS total_leave  
FROM leaveapplydata
-- WHERE some condition
英文:

Summing is commutative, so you could add the three fields and then sum them:

SELECT SUM(casual_leave_days + vacation_leave_days + other_leave_days) AS total_leave  
FROM leaveapplydata
-- WHERE some condition

答案2

得分: 0

你可以这样做,

SELECT (casual_leave + vaction_leave + other_leave_days) AS total_leave
FROM (
SELECT SUM(casual_leave_days) AS casual_leave,
SUM(vaction_leave_days) AS vaction_leave,
SUM(other_leave_days) AS other_leave
FROM leaveapplydata
WHERE emp_id = '$_POST["emp_id"]' AND (casual_holiday_start LIKE '$passyear%'
OR vaction_holiday_start LIKE '$passyear%'
OR other_holiday_start ))

英文:

You can do it like this ,

SELECT (casual_leave  + vaction_leave + other_leave_days  ) AS total_leave 
FROM (
SELECT SUM(casual_leave_days) AS casual_leave , 
       SUM(vaction_leave_days) AS vaction_leave , 
       SUM(other_leave_days) AS other_leave
FROM leaveapplydata
WHERE emp_id = '".$_POST["emp_id"]."' AND  (casual_holiday_start LIKE '$passyear%'
OR vaction_holiday_start LIKE '$passyear%'
OR other_holiday_start ) ) 

huangapple
  • 本文由 发表于 2020年1月6日 15:10:02
  • 转载请务必保留本文链接:https://go.coder-hub.com/59608011.html
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