如何从这个时间差列中删除 “0-0 0″?

huangapple go评论58阅读模式
英文:

How do I remove the "0-0 0" from this time difference column?

问题

以下是翻译好的部分,代码部分不翻译:

"sample output" 翻译成中文:
样本输出:

"01:56:26 267 ENTER null" 翻译成中文:
01:56:26 267 输入 空

"04:20:24 267 DELETE 0-0 0 2:23:58" 翻译成中文:
04:20:24 267 删除 0-0 0 2:23:58

"01:57:00 268 ENTER null" 翻译成中文:
01:57:00 268 输入 空

"03:31:57 268 DELETE 0-0 0 1:34:57" 翻译成中文:
03:31:57 268 删除 0-0 0 1:34:57

英文:

I have a data set that pulls the difference of time between each entered and deleted order. However with this code I get an output that reads 0-0 0 and the time difference. I would like to remove the 0-0 0 if possible.

SELECT CAST(Left(time, 8) AS time) AS time, 
       coalesce(buyer_order_id, SELLER_ORDER_ID) AS order_id,
       CAST(left(time, 8) AS time) - lag(CAST(Left(time, 8) AS time), 1) 
        OVER (partition by coalesce(buyer_order_id, SELLER_ORDER_ID) order by time) AS time_difference
FROM orders.sheet1 
WHERE message_type = "ENTER" OR message_Type = "DELETE" 
order by order_id

sample output:

time     order_id  message_type time_difference
01:56:26 267       ENTER        null
04:20:24 267       DELETE       0-0 0 2:23:58	
01:57:00 268       ENTER        null
03:31:57 268       DELETE       0-0 0 1:34:57

tried many variations of replace and right functions but have been unsuccessful since the output is a time one and not a string.

答案1

得分: 0

在BigQuery中执行以下操作:

TIME(TIMESTAMP_SUB(CAST(TIME(TIMESTAMP(left(time, 8))) AS TIMESTAMP), TIMESTAMP_SUB(CAST(TIME(TIMESTAMP(left(time, 8))) AS TIMESTAMP), 1, 'SECOND')))

如果是SQL Server,可以使用CONVERT函数(选择14或114):

CONVERT(TIME, DATEADD(SECOND, DATEDIFF(SECOND, '00:00:00', CAST(TIME FROM (CAST(left(time, 8) AS time))) - LAG(CAST(TIME FROM (CAST(LEFT(time, 8) AS time))), 1, '00:00:00'), 114), '00:00:00'), 114)

更多详细信息请参阅此处:

https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql?view=sql-server-ver16

英文:

In bigquery do this:

TIME(CAST(left(time, 8) AS time) - lag(CAST(Left(time, 8))

You can use convert if this is SQL server (you want 14 or 114)

CONVERT(time, CAST(left(time, 8) AS time) - lag(CAST(Left(time, 8), 114)

More details documented here:

https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql?view=sql-server-ver16

答案2

得分: 0

你愿意尝试以下内容吗?

```sql
SELECT *,
       TIME (
         EXTRACT(HOUR FROM time_difference),
         EXTRACT(MINUTE FROM time_difference),
         EXTRACT(SECOND FROM time_difference)
       ) AS time_diff
  FROM (
    SELECT CAST(LEFT(time, 8) AS TIME) AS time, 
          COALESCE(buyer_order_id, SELLER_ORDER_ID) AS order_id,
          CAST(LEFT(time, 8) AS TIME) - LAG(CAST(LEFT(time, 8) AS TIME), 1) 
            OVER (PARTITION BY COALESCE(buyer_order_id, SELLER_ORDER_ID) ORDER BY time) AS time_difference
    FROM orders.sheet1 
  WHERE message_type = "ENTER" OR message_type = "DELETE" 
) ORDER BY order_id;

<details>
<summary>英文:</summary>

Would you try below ?

```sql
SELECT *,
       TIME (
         EXTRACT(HOUR FROM time_difference),
         EXTRACT(MINUTE FROM time_difference),
         EXTRACT(SECOND FROM time_difference)
       ) AS time_diff
  FROM (
    SELECT CAST(Left(time, 8) AS time) AS time, 
          coalesce(buyer_order_id, SELLER_ORDER_ID) AS order_id,
          CAST(left(time, 8) AS time) - lag(CAST(Left(time, 8) AS time), 1) 
            OVER (partition by coalesce(buyer_order_id, SELLER_ORDER_ID) order by time) AS time_difference
    FROM orders.sheet1 
  WHERE message_type = &quot;ENTER&quot; OR message_Type = &quot;DELETE&quot; 
) order by order_id;

答案3

得分: 0

你可能想重新考虑time_difference列的类型。BigQuery有TIME_DIFF()函数,返回INT64。以下是一个示例:

WITH
  -- 样本数据
  tmp AS (
  SELECT
    t,
    oid,
    msg_type
  FROM
    UNNEST( ["01:56:26", "04:20:24", "01:57:00", "03:31:57"]) t
  WITH
  OFFSET
    o1
  LEFT JOIN
    UNNEST([267, 267, 268, 268]) oid
  WITH
  OFFSET
    o2
  ON
    o1 = o2
  LEFT JOIN
    UNNEST(["ENTER", "DELETE", "ENTER", "DELETE"]) msg_type
  WITH
  OFFSET
    o3
  ON
    o2 = o3 ),

  -- 计算滞后
  lags AS (
  SELECT
    CAST(LEFT(t, 8) AS time) AS time,
    oid,
    msg_type,
    LAG(CAST(LEFT(t, 8) AS time), 1) OVER (PARTITION BY oid ORDER BY t) AS time_lag
  FROM
    tmp
  WHERE
    msg_type = "ENTER"
    OR msg_type = "DELETE"
  ORDER BY
    oid)

-- 时间差异(以秒为单位)
SELECT
  time,
  oid AS order_id,
  msg_type AS message_type,
  TIME_DIFF(time, time_lag, SECOND) AS time_difference_seconds
FROM lags;
[1]: https://cloud.google.com/bigquery/docs/reference/standard-sql/functions-and-operators#time_diff
英文:

You might want to reconsider the type of the time_difference column. BigQuery has the TIME_DIFF() function which returns an INT64.
Here's an example:

WITH
  -- sample data
  tmp AS (
  SELECT
    t,
    oid,
    msg_type
  FROM
    UNNEST( [&quot;01:56:26&quot;, &quot;04:20:24&quot;, &quot;01:57:00&quot;, &quot;03:31:57&quot;]) t
  WITH
  OFFSET
    o1
  LEFT JOIN
    UNNEST([267, 267, 268, 268]) oid
  WITH
  OFFSET
    o2
  ON
    o1 = o2
  LEFT JOIN
    UNNEST([&quot;ENTER&quot;, &quot;DELETE&quot;, &quot;ENTER&quot;, &quot;DELETE&quot;]) msg_type
  WITH
  OFFSET
    o3
  ON
    o2 = o3 ),

  -- calculate the lag
  lags AS (
  SELECT
    CAST(LEFT(t, 8) AS time) AS time,
    oid,
    msg_type,
    LAG(CAST(LEFT(t, 8) AS time), 1) OVER (PARTITION BY oid ORDER BY t) AS time_lag
  FROM
    tmp
  WHERE
    msg_type = &quot;ENTER&quot;
    OR msg_type = &quot;DELETE&quot;
  ORDER BY
    oid)

-- time difference in seconds
SELECT
  time,
  oid AS order_id,
  msg_type AS message_type,
  TIME_DIFF(time, time_lag, SECOND) AS time_difference_seconds
FROM lags;

huangapple
  • 本文由 发表于 2023年2月16日 05:07:36
  • 转载请务必保留本文链接:https://go.coder-hub.com/75465442.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定