英文:
Stack variables in go?
问题
以下是代码的中文翻译：
package mainimport ("fmt""os")func main() {var l = test(4)test(5)fmt.Fprintf(os.Stdout, "%d\n", *l)}func test(v int) *int {var p = vreturn &p}
在C语言中，等效的代码会打印出5，因为第一个栈帧中的变量p会被第二个栈帧中的相同变量p覆盖。我反汇编了这段代码，但对其意义并不能理解太多。
#include <stdio.h>int* test(int v);int main() {int* p = test(4);test(5);printf("%d\n", *p);}int* test(int v) {int p = v;return &p;}
有人能给我一个关于Go语言内存管理工作原理的基本概述吗？函数变量是否存放在堆上？
英文:
package mainimport ("fmt""os")func main() {var l = test(4)test(5)fmt.Fprintf(os.Stdout, "%d\n", *l)}func test(v int) *int {var p = vreturn &p}
In C, the equivalent code would print 5 because the the variable p in the first stack frame would be overwritten by the same variable p in the second stack frame. I disassembled the code but am not able to make too much sense of it.
#include <stdio.h>int* test(int v);int main() {int* p = test(4);test(5);printf("%d\n", *p);}int* test(int v) {int p = v;return &p;}
Can somebody give me a basic synopsis of how memory management works in Go? Do function variables go on the heap?
答案1
得分: 1
这是一段关于逃逸分析的内容。逃逸分析在官方文档中并不完善，但你可以参考这个链接：http://blog.rocana.com/golang-escape-analysis
你可以使用以下命令对你的代码进行逃逸分析（假设你的文件名是main.go）：
go run -gcflags '-m -l' main.go
英文:
It is somewhat strange that we don't have good official documentation on escape analysis (or maybe even if it's there I haven't found it yet!) but here's something I found useful : http://blog.rocana.com/golang-escape-analysis
You can use something like this to do an escape analysis for your code (assuming your filename is main.go):
go run -gcflags '-m -l' main.go
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