将JSON顶层数组解组为字符串到字符串的映射。

huangapple
go评论128阅读模式
英文:

Unmarshaling JSON top level array into map of string to string

问题

我正在尝试解析以下类型的JSON数组：

  1. [
  2.     {"abc's": "n;05881364"},
  3.     {"abcoulomb": "n;13658345"},
  4.     {"abcs": "n;05881364"}
  5. ]

解析成map[string]string。这个问题 https://stackoverflow.com/questions/25465566/golang-parse-json-array-into-data-structure 几乎回答了我的问题，但我的是一个真正的map，而不是一个map的数组。解析成[]map[string]string是可以的，但现在我得到的是一个map[string]string的map，而不是一个简单的map的string。

英文:

I'm trying to unmarshal a JSON array of the following type:

  1. [
  2. {"abc's": "n;05881364"},
  3. {"abcoulomb": "n;13658345"},
  4. {"abcs": "n;05881364"}
  5. ]

into a map[string]string. This question https://stackoverflow.com/questions/25465566/golang-parse-json-array-into-data-structure almost answered my problem, but mine is a truly map, not an array of maps. Unmarshaling into a []map[string]string worked but I now get a map of map[string]string, not a simple map of string as it should be

答案1

得分: 7

使用json包无法直接完成此操作；您需要自己进行转换。这很简单：

  1. package main
  3. import (
  4. 	"encoding/json"
  5. 	"fmt"
  6. )
  8. func main() {
  9. 	data := []byte(`
  10.         [
  11.         {"abc's": "n;05881364"},
  12.         {"abcoulomb": "n;13658345"},
  13.         {"abcs": "n;05881364"}
  14.         ]
  15.     `)
  17. 	var mapSlice []map[string]string
  18. 	if err := json.Unmarshal(data, &mapSlice); err != nil {
  19. 		panic(err)
  20. 	}
  21. 	resultingMap := map[string]string{}
  22. 	for _, m := range mapSlice {
  23. 		for k, v := range m {
  24. 			resultingMap[k] = v
  25. 		}
  26. 	}
  27. 	fmt.Println(resultingMap)
  28. }

输出结果：

  1. map[abc's:n;05881364 abcoulomb:n;13658345 abcs:n;05881364]
英文:

There is no way to do it directly with the json package; you have to do the conversion yourself. This is simple:

  1. package main
  3. import (
  4. 	"encoding/json"
  5. 	"fmt"
  6. )
  8. func main() {
  9. 	data := []byte(`
  10.         [
  11.         {"abc's": "n;05881364"},
  12.         {"abcoulomb": "n;13658345"},
  13.         {"abcs": "n;05881364"}
  14.         ]
  15.     `)
  17. 	var mapSlice []map[string]string
  18. 	if err := json.Unmarshal(data, &mapSlice); err != nil {
  19. 		panic(err)
  20. 	}
  21. 	resultingMap := map[string]string{}
  22. 	for _, m := range mapSlice {
  23. 		for k, v := range m {
  24. 			resultingMap[k] = v
  25. 		}
  26. 	}
  27. 	fmt.Println(resultingMap)
  28. }

Output

  1. map[abc's:n;05881364 abcoulomb:n;13658345 abcs:n;05881364]

答案2

得分: 3

一个与Alex的答案（虽然非常相似）类似的替代方法是定义自己的类型，并附带一个UnmarshalJSON函数。

  1. package main
  3. import (
  4. 	"encoding/json"
  5. 	"fmt"
  6. )
  8. type myMapping map[string]string
  10. func (mm myMapping) UnmarshalJSON(b []byte) error {
  11. 	var temp []map[string]string
  12. 	if err := json.Unmarshal(b, &temp); err != nil {
  13. 		return err
  14. 	}
  15. 	for _, m := range temp {
  16. 		for k, v := range m {
  17. 			mm[k] = v
  18. 		}
  19. 	}
  20. 	return nil
  21. }
  23. func main() {
  24. 	data := []byte(`
  25. 		[
  26. 			{"abc's": "n;05881364"},
  27. 			{"abcoulomb": "n;13658345"},
  28. 			{"abcs": "n;05881364"}
  29. 		]`)
  31. 	resultingMap := myMapping{}
  32. 	if err := json.Unmarshal(data, &resultingMap); err != nil {
  33. 		panic(err)
  34. 	}
  35. 	fmt.Println(resultingMap)
  36. }

Playground

英文:

An alternative (though very similar) to Alex's answer is to define your own type along with an UnmarshalJSON function.

  1. package main
  3. import (
  4. 	"encoding/json"
  5. 	"fmt"
  6. )
  8. type myMapping map[string]string
  10. func (mm myMapping) UnmarshalJSON(b []byte) error {
  11. 	var temp []map[string]string
  12. 	if err := json.Unmarshal(b, &temp); err != nil {
  13. 		return err
  14. 	}
  15. 	for _, m := range temp {
  16. 		for k, v := range m {
  17. 			mm[k] = v
  18. 		}
  19. 	}
  20. 	return nil
  21. }
  23. func main() {
  24. 	data := []byte(`
  25.         	[
  26.         		{"abc's": "n;05881364"},
  27.         		{"abcoulomb": "n;13658345"},
  28.         		{"abcs": "n;05881364"}
  29.         	]`)
  31. 	resultingMap := myMapping{}
  32. 	if err := json.Unmarshal(data, &resultingMap); err != nil {
  33. 		panic(err)
  34. 	}
  35. 	fmt.Println(resultingMap)
  36. }

Playground

huangapple
  • 本文由 发表于 2017年2月17日 12:45:34
  • 转载请务必保留本文链接：https://go.coder-hub.com/42289591.html
  • arrays
  • go
  • json
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