编写一个深度为d的嵌套迭代器。

huangapple go评论98阅读模式
英文:

Writing a nested iterator of depth d

问题

如何实现一个带有深度参数的嵌套迭代器。当深度为1时,它就是一个简单的迭代器,类似于简单的for循环。

func Iter(depth int) chan string {
    ch := make(chan string)
    go func() {
        if depth == 1 {
            for i := 1; i < 60; i++ {
                ch <- fmt.Sprintf("%d", i)
            }
        } else {
            subIter := Iter(depth - 1)
            for i := 1; i < 60; i++ {
                for sub := range subIter {
                    ch <- fmt.Sprintf("%s,%d", sub, i)
                }
                subIter = Iter(depth - 1)
            }
        }
        close(ch)
    }()
    return ch
}

输出为1,2,3...59

当深度为2时,输出为"1,1" "1,2" ... "1,59" "2,1" ... "59,59"

当深度为3时,输出为"1,1,1" ... "59,59,59"

这样可以避免使用嵌套的for循环。

英文:

How to realize a nested iterator that takes a depth argument. A simple iterator would be when depth = 1. it is a simple iterator which runs like a simple for loop.

func Iter () chan int {
    ch := make(chan int);
    go func () {
        for i := 1; i &lt; 60; i++ {
            ch &lt;- i
        }
        close(ch)
    } ();
    return ch
}

Output is 1,2,3...59

For depth = 2 Output would be &quot;1,1&quot; &quot;1,2&quot; ... &quot;1,59&quot; &quot;2,1&quot; ... &quot;59,59&quot;

For depth = 3 Output would be &quot;1,1,1&quot; ... &quot;59,59,59"

I want to avoid a nested for loop. What is the solution here ?

答案1

得分: 2

我不知道是否可以避免嵌套循环,但是一种解决方案是使用管道的流水线。例如:

const ITER_N = 60

// ----------------

func _goFunc1(out chan string) {
    for i := 1; i < ITER_N; i++ {
        out <- fmt.Sprintf("%d", i)
    }
    close(out)
}

func _goFuncN(in chan string, out chan string) {
    for j := range in {
        for i := 1; i < ITER_N; i++ {
            out <- fmt.Sprintf("%s,%d", j, i)
        }
    }
    close(out)
}

// ----------------

// 创建流水线
func IterDepth(d int) chan string {
    c1 := make(chan string)
    go _goFunc1(c1)

    var c2 chan string
    for ; d > 1; d-- {
        c2 = make(chan string)
        go _goFuncN(c1, c2)
        c1 = c2
    }
    return c1
}


func main() {
    c := IterDepth(2)

    for i := range c {
        fmt.Println(i)
    }
}

你可以使用以下代码进行测试:

func main() {
    c := IterDepth(2)

    for i := range c {
        fmt.Println(i)
    }
}
英文:

I don't know if it is possible to avoid nested loops, but one solution is to use a pipeline of channels. For example:

const ITER_N = 60

// ----------------

func _goFunc1(out chan string) {
    for i := 1; i &lt; ITER_N; i++ {
        out &lt;- fmt.Sprintf(&quot;%d&quot;, i)
    }
    close(out)
}

func _goFuncN(in chan string, out chan string) {
    for j := range in {
        for i := 1; i &lt; ITER_N; i++ {
            out &lt;- fmt.Sprintf(&quot;%s,%d&quot;, j, i)
        }
    }
    close(out)
}

// ----------------

// create the pipeline
func IterDepth(d int) chan string {
    c1 := make(chan string)
    go _goFunc1(c1)

    var c2 chan string
    for ; d &gt; 1; d-- {
        c2 = make(chan string)
        go _goFuncN(c1, c2)
        c1 = c2

    }
    return c1
}

You can test it with:

func main() {
    c := IterDepth(2)

    for i := range c {
        fmt.Println(i)
    }
}

答案2

得分: 1

我通常使用闭包来实现迭代器。多个维度并不会使问题变得更加困难。以下是一个示例,展示如何实现迭代器:

package main

import "fmt"

func iter(min, max, depth int) func() ([]int, bool) {
    s := make([]int, depth)
    for i := range s {
        s[i] = min
    }
    s[0] = min - 1
    return func() ([]int, bool) {
        s[0]++
        for i := 0; i < depth-1; i++ {
            if s[i] >= max {
                s[i] = min
                s[i+1]++
            }
        }
        if s[depth-1] >= max {
            return nil, false
        }
        return s, true
    }
}

func main() {
    // 三个维度,范围在[1,4)
    i := iter(1, 4, 3)
    for s, ok := i(); ok; s, ok = i() {
        fmt.Println(s)
    }
}

你可以在Playground上尝试运行它。

例如,如果需要的话,可以简单地将参数作为一个整数切片传递,这样你就可以为每个维度设置不同的限制。

英文:

I usually implement iterators using closures. Multiple dimensions don't make the problem much harder. Here's one example of how to do this:

package main
 
import &quot;fmt&quot;
 
func iter(min, max, depth int) func() ([]int, bool) {
    s := make([]int, depth)
    for i := range s { 
        s[i] = min 
    }   
    s[0] = min - 1 
    return func() ([]int, bool) {
        s[0]++
        for i := 0; i &lt; depth-1; i++ {
            if s[i] &gt;= max {
                s[i] = min 
                s[i+1]++
            }   
        }   
        if s[depth-1] &gt;= max {
            return nil, false
        }   
        return s, true
    }   
}   
 
func main() {
    // Three dimensions, ranging between [1,4)
    i := iter(1, 4, 3)
    for s, ok := i(); ok; s, ok = i() {
        fmt.Println(s)
    }   
 
}

Try it out on the Playground.

It'd be a simple change for example to give arguments as a single int slice instead, so that you could have per-dimension limits, if such a thing were necessary.

huangapple
  • 本文由 发表于 2016年2月22日 15:27:41
  • 转载请务必保留本文链接:https://go.coder-hub.com/35547964.html
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