英文:
How to access struct's instance fields from a function?
问题
假设我有一个名为Graph的结构体，如下所示：
type Graph struct {nodes []intadjList map[int][]int}// 结构体的一些方法// 构造函数func New() *Graph {g := new(Graph)g.adjList = make(map[int][]int)return g}
现在，我使用aGraph := New()创建了一个该结构体的新实例。
如何访问这个特定实例的Graph结构体的字段（aGraph）？
换句话说，如何从另一个顶层函数中访问aGraph的nodes数组（例如）？
非常感谢您的帮助！
英文:
Assuming, that I have a Graph struct, like so:
type Graph struct {nodes []intadjList map[int][]int}// some methods on the struct// constructorfunc New() *Graph {g := new(Graph)g.adjList = make(map[int][]int)return g}
Now, I create a new instance of that struct, with: aGraph := New().
How do I access the fields of this particular instance of the Graph struct (aGraph)?
In other words, how do I access aGraph's version of the nodes array, (from within another top-level function for example)?
Any help is extremely appreciated!
答案1
得分: 1
这是一个示例：
package mainimport ("fmt")// 示例结构体type Graph struct {nodes []intadjList map[int][]int}func New() *Graph {g := new(Graph)g.adjList = make(map[int][]int)return g}func main() {aGraph := New()aGraph.nodes = []int{1, 2, 3}aGraph.adjList[0] = []int{1990, 1991, 1992}aGraph.adjList[1] = []int{1890, 1891, 1892}aGraph.adjList[2] = []int{1890, 1891, 1892}fmt.Println(aGraph)}
输出：&{[1 2 3] map[0:[1990 1991 1992] 1:[1890 1891 1892] 2:[1890 1891 1892]]}
英文:
Here is one example:
package mainimport ("fmt")// example structtype Graph struct {nodes []intadjList map[int][]int}func New() *Graph {g := new(Graph)g.adjList = make(map[int][]int)return g}func main() {aGraph := New()aGraph.nodes = []int {1,2,3}aGraph.adjList[0] = []int{1990,1991,1992}aGraph.adjList[1] = []int{1890,1891,1892}aGraph.adjList[2] = []int{1890,1891,1892}fmt.Println(aGraph)}
Output:&{[1 2 3 4 5] map[0:[1990 1991 1992] 1:[1890 1891 1892] 2:[1790 1791 1792]]}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论