英文:
Go: Not able to write to a file
问题
文件的权限：-rw-r--r--
我将权限更改为-rw-rw--rw--，但它仍然无法工作。我想了解为什么这段代码不起作用：
该函数创建一个文件，但函数没有向文件中写入任何内容。我也没有收到任何错误信息。
newfileCreate, err := os.Create("brainnew.txt")
newfile, err := os.Open(newfileCreate.Name())
if err != nil {
log.Fatal(err)
}
defer newfile.Close()
newfile.WriteString("sdsds sds")
// 我尝试写入字节，但也不起作用！
但是，如果我尝试这段代码，它可以工作！
str := "example-text"
data := []byte(str)
ioutil.WriteFile("data.txt", data, 0644)
英文:
Permission of file: -rw-r--r--
I changed the permissions to -rw-rw--rw-- but it still doesn't work. I want to understand why this code is not working:
The function creates a file. But the function does not write anything to the file. I also don't get any error.
newfileCreate, err := os.Create("brainnew.txt")
newfile, err := os.Open(newfileCreate.Name())
if err != nil {
log.Fatal(err)
}
defer newfile.Close()
newfile.WriteString("sdsds sds")
// I tried writing bytes but it that also doesn't work!
But, if I try this code, it works!
str := "example-text"
data := []byte(str)
ioutil.WriteFile("data.txt", data, 0644)
答案1
得分: 0
问题出在os.Open函数上。如果你查看该函数的文档，会发现以下内容：
// Open打开指定的文件以进行读取。如果成功，返回的文件可以用于读取；关联的文件描述符的模式为O_RDONLY。
// 如果出现错误，错误类型将为*PathError。
这意味着它以只读模式打开文件。如果你检查newfile.WriteString()的错误，你会知道由于只读模式，没有写入任何内容。
英文:
The problem is in os.Open. If you check the documentation for this functions it says:
// Open opens the named file for reading. If successful, methods on
// the returned file can be used for reading; the associated file
// descriptor has mode O_RDONLY.
// If there is an error, it will be of type *PathError.
This means it opens file in read-only mode. If you would check the error of newfile.WriteString(). Then you would know, that nothing was written due to read-only mode.
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