如何获取方法参数的名称

huangapple go评论68阅读模式
英文:

How do i get the method argument names

问题

我有一个很好的函数,可以打印给定类型中给定方法的一些信息,这是一个goplay

它可以满足我的需求,只是我找不到一种方法来获取方法参数的名称,有什么办法可以实现吗?

func AnalyzeMethod(instance interface{}, methodName string) {
    m, ok := reflect.ValueOf(instance).Type().MethodByName(methodName)
    if ok {
        isVariadic := m.Type.IsVariadic()
        var VariadicIndex int
        var VariadicType reflect.Type
        var FirstPositionalIndex int
        var LastPositionalIndex int
        var ArgsLength int = m.Type.NumIn() - 1
        //var []string ArgumentNames //无法找到一种方法来获取函数接受的每个参数的有序名称切片

        if ArgsLength > 0 {
            FirstPositionalIndex = 1
        }

        if isVariadic {
            VariadicIndex = ArgsLength
            VariadicType = m.Type.In(VariadicIndex)
            LastPositionalIndex = ArgsLength - 1
        } else {
            VariadicIndex = -1
            LastPositionalIndex = ArgsLength
        }

        fmt.Println("ArgsLength:", ArgsLength)
        fmt.Println("FirstPositionalIndex:", FirstPositionalIndex)
        fmt.Println("LastPositionalIndex:", LastPositionalIndex)
        fmt.Println("Variadic:", isVariadic)
        fmt.Println("VariadicIndex:", VariadicIndex)
        fmt.Println("VariadicType:", VariadicType)
        fmt.Println("ArgumentNames", "How?")
    }
}
英文:

I have this nice function that prints some info about a given method in a given type, here is a goplay

it does all i need except i can't find a way to get the method argument names,any idea to achieve that?

    func AnalyzeMethod(instance interface {},methodName string){
        m,ok := reflect.ValueOf(instance).Type().MethodByName(methodName)
	if ok{
	   isVariadic := m.Type.IsVariadic()
	   var VariadicIndex int
	   var VariadicType reflect.Type
	   var FirstPositionalIndex int
	   var LastPositionalIndex int
	   var ArgsLength int = m.Type.NumIn()-1
	   //var []string ArgumentNames //can't find a way to get an ordered slice of names of every argument that the function takes
	   
	   if ArgsLength>0{
	     FirstPositionalIndex = 1
	   }
	   	
	
	   if isVariadic{
	     VariadicIndex = ArgsLength
	     VariadicType = m.Type.In(VariadicIndex)
	     LastPositionalIndex = ArgsLength-1
	   } else {
	     VariadicIndex = -1
	     LastPositionalIndex = ArgsLength
	   }
	
	   fmt.Println("ArgsLength:",ArgsLength)	
	   fmt.Println("FirstPositionalIndex:",FirstPositionalIndex)
	   fmt.Println("LastPositionalIndex:",LastPositionalIndex)	
	   fmt.Println("Variadic:",isVariadic)
	   fmt.Println("VariadicIndex:",VariadicIndex)
	   fmt.Println("VariadicType:",VariadicType)
	   fmt.Println("ArgumentNames","How?")
	   
        }
}

答案1

得分: 3

局部变量的名称(包括函数参数)只是为了程序员方便使用,编译器在生成代码时会丢弃它们。无法检索参数名称,因为它们在编译后的代码中不可用。

英文:

The names of local variables (including function arguments) are just for the programmer; the compiler discards them when it generates code. There is no way to retrieve argument names as they are not available in the compiled code.

huangapple
  • 本文由 发表于 2015年2月10日 21:30:28
  • 转载请务必保留本文链接:https://go.coder-hub.com/28432946.html
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