英文:
How to redirect URL in Go main method?
问题
我在Go语言中设置了一个GorrilaMux,如果在浏览器中输入特定的URL,它将进行API调用。如果URL作为命令行参数给出,我希望在我的主方法中进行相同的API调用。然而,似乎可以做到这一点的http.redirect()方法需要一个HTTP ResponseWriter和一个*HTTPRequest变量作为函数参数。我不知道如何在主方法中生成这些变量。我该如何做,或者在Golang中有更好的方法从URL进行API调用?
设置路由的代码如下:
func main(){
router := mux.NewRouter().StrictSlash(true)
for _, route := range routes { //设置预定义路由
router.
Path(route.Path).
Name(route.Name).
Handler(route.HandlerFunc)
}
URL := "localhost:8080/whatever" //我想要重定向的URL,路由将是"/whatever"
http.redirect(????)
}
请注意,我只会翻译代码部分,不会回答关于翻译的问题。
英文:
I have a GorrilaMux set up in Go that will make an API call if type in a specific URL in a browser. I want to make the same API call in my main method in go if the URL is given as a command line argument. However, the http.redirect() method which seems to be able to do this, requires a HTTP ResponseWriter and a *HTTPRequest variables as function parameters. I do not know how to produce these variables within a main method. How do I do this, OR, is there a better way to make the API call from the URL in Golang?
Code to set up Router
func main(){
router := mux.NewRouter().StrictSlash(true)
for _, route := range routes { //Sets up predefined routes
router.
Path(route.Path).
Name(route.Name).
Handler(route.HandlerFunc)
}
URL:="localhost:8080/whatever" //URL I want to redirect, route would be "/whatever"
http.redirect(????)
}
答案1
得分: 2
HTTP重定向是对客户端的响应,应该从处理程序的调用中调用。在主函数的上下文中,http.redirect(w http.ResponseWriter, r *http.Request)
函数没有意义。
您可以像这样为给定的路由注册处理程序:
router.Path("/whatever").Handler(func(writer http.ResponseWriter, req *http.Request) {
http.Redirect(writer, req, "localhost:8080/whatever", http.StatusMovedPermanently)
}))
这将向路由器添加一个路径,并调用简单的http.Handlerfunc
,其中包含对http.Redirect(...)
的调用。在这里,这是有意义的,因为我们正在处理对客户端连接的响应。返回301状态代码和重定向目标的URL是合乎逻辑的。
英文:
An HTTP redirect is a response to a client and should be called from an invocation of a handler. The http.redirect(w http.ResponseWriter, r *http.Request)
function has no meaning in the context of the main function.
You can register a handler for the given route like so:
router.Path("/whatever").Handler(func(writer http.ResponseWriter, req *http.Request) {
http.Redirect(writer, req, "localhost:8080/whatever", http.StatusMovedPermanently)
))
This adds a path to the router and invokes the simple http.Handlerfunc
which contains a call to http.Redirect(...)
. Here this makes sense because we are handling a response to a client connection. It is logical to return a 301 status code and the URL for the target of the redirect.
答案2
得分: 0
我们使用一个辅助函数来使代码更清晰。
// Redirect函数将执行HTTP重定向到给定的重定向路径。
func Redirect(redirectPath string) func(http.ResponseWriter, *http.Request) {
return func(w http.ResponseWriter, r *http.Request) {
http.Redirect(w, r, redirectPath, http.StatusFound)
}
}
router.Path("/whatever").Handler(Redirect("/test_path"))
router.Path("/whatever2").Handler(Redirect("/test_path2"))
英文:
We use a helper function to make the code cleaner.
// Redirect will peform an HTTP redirect to the given redirect Path.
func Redirect(redirectPath string) func(http.ResponseWriter, *http.Request) {
return func(w http.ResponseWriter, r *http.Request) {
http.Redirect(w, r, redirectPath, http.StatusFound)
}
}
router.Path("/whatever").Handler(Redirect("/test_path"))
router.Path("/whatever2").Handler(Redirect("/test_path2"))
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