How to fix file access when using a sub-directory?

Which way Go does handle read access to directories and files?

I want to read a folder, search for csv files and save the content per csv file in order to send the content via http request.

Here's my code:

func GetFileContent(fileName string) ([][]string, error) {
file, err := os.Open(fileName)
if err != nil {
log.Println("There was an error:", err)
return nil, err
}
defer file.Close()
reader := csv.NewReader(file)
reader.FieldsPerRecord = -1
csvFileContent, err := reader.ReadAll()
if err != nil {
log.Println("There was an error:", err)
return nil, err
}
return csvFileContent, nil
}
func GetFiles(importPath string, fileExtension string) ([]string, error) {
var result []string
directory, err := os.Open(importPath)
if err != nil {
return result, err
}
defer directory.Close()
files, err := directory.Readdir(-1)
if err != nil {
return result, err
}
for _, file := range files {
if file.Mode().IsRegular() {
if filepath.Ext(file.Name()) == "." + fileExtension {
log.Println("Import Files: ", file.Name())
result = append(result, file.Name())
}
}
}
if len(result) == 0 {
log.Println("No import files of type " + fileExtension + " found.")
log.Println("Import skipped.")
}
return result, nil
}

> Error: open : no such file or directory

appears when I do not use the root folder / working directory of my application but another (parent) folder? It works as long as I use ./ as source folder.

FileInfo.Name returns the base name of the file. You need to join the directory name with the base name to get a file path.

Change this line in GetFiles

result = append(result, file.Name())

to

result = append(result, filepath.Join(importPath, file.Name()))

In this case, you might consider using the higher-level filepath.Glob() instead:

files, err := filepath.Glob(filepath.Join(importPath, "*.csv"))