英文:
In Golang, how do I define a specific sort of map as a unique type?
问题
所以我现在处于一个尴尬的境地，我正在尝试将上下文数据传递给模板，但是没有太多真正好的例子，这些例子不涉及传递预先存在的结构。我能想到的最好的方法是像下面这样：
templ.Execute(writer, map[string]interface{}{
"thingyA": ThingyA,
"thingyB": ThingyB,
})
使用上述方法，我可以通过{{ .thingyA.[PROPERTY] }}在模板中引用ThingyA及其所有属性和方法。这本身就很好，因为它允许我以简单的Django风格定义上下文，而不使用匿名结构，这会有点笨拙。
但是我想知道是否有一种方法可以定义一个新类型Context，这样我就可以简化上述代码，如下所示：
templ.Execute(writer, Context{
"thingyA": ThingyA,
"thingyB": ThingyB,
})
也就是说，我想定义一个特定类型的Context，它始终具有map[string]interface{}的形式，并且可以像初始化映射一样进行初始化。有关如何实现这一点的任何想法吗？
英文:
So I'm at that awkward place where I'm trying to pass context data over to a template, and there's not a whole lot of really great examples out there that don't involve passing a preexisting structure. The best I have come up with is something like the following:
templ.Execute(writer, map[string]interface{}{
"thingyA": ThingyA,
"thingyB": ThingyB,
})
Using the above, I can reference ThingyA and all of its properties and methods in my template by using {{ .thingyA.[PROPERTY] }}. So that's pretty good in itself, in that it allows me to define a context in a simple Django-ish fashion, without using an anonymous struct, which would be a bit clunky.
But I'm wondering if there is some way to define a new type Context, so that I could simplify the above to the following:
templ.Execute(writer, Context{
"thingyA": ThingyA,
"thingyB": ThingyB,
})
That is, I would like to define a specific type Context that always has the form map[string]interface{}, and can be initialized in the same manner as a map. Any ideas on how to go about this?
答案1
得分: 4
type Context map[string]interface{}
c := Context{"foo": 1, "bar": 2}
英文:
type Context map[string]interface{}
c := Context{"foo": 1, "bar": 2}
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