英文:
How to store go channel value into some other data type(string,byte[]) and reassign it other go channel
问题
//目标-->将字符串（或某些字节数组）转换为通道变量newpipe。
我必须通过创建XML将我的数据从一个进程传输到另一个进程。
XML编组不支持chan类型，也不支持interface{}类型。
然后，在从其他进程接收响应XML后，将值分配给newpipe，并使用newpipe进行通道通信。
func main() {mypipe := make(chan int)fmt.Printf("我的管道地址 %p \n", mypipe)str := fmt.Sprintf("%p", mypipe) //将mypipe转换为字节数组的方法var newpipe chan int}
我已经寻找了各种类型转换方法一整天，但没有一种方法适用于chan类型。
英文:
//Target --> convert str(or some byte[])into channel variable newpipe.
I have to transfer my data from one process to another my making xml.
Xml marshall does not support chan type does not work with interface{} also
then after receveing response xml from other process assign value to newpipe and use newpipe for channel communication
func main() {mypipe := make(chan int)fmt.Printf("My pipe addr %p \n", mypipe)str := fmt.Sprintf("%p", mypipe) //way to convert mypipe to byte[]var newpipe chan int}
I am looking for various type conversion for one day but none of them works with chan type
答案1
得分: 2
下面的代码将把输入的字符串转换为输出的字节切片。希望这正是你想要的：
package mainimport "fmt"func stringToByteSlice(sc chan string, bc chan []byte) {defer close(bc)for s := range sc {bc <- []byte(s)}}func main() {strings := []string{"foo", "bar", "baz", "bat"}byteSlices := [][]byte{}sc := make(chan string)bc := make(chan []byte)go func() {defer close(sc)for _, s := range strings {sc <- s}}()go stringToByteSlice(sc, bc)for b := range bc {byteSlices = append(byteSlices, b)}fmt.Printf("%v\n", byteSlices)}
输出结果：
[[102 111 111] [98 97 114] [98 97 122] [98 97 116]]
英文:
The code below will convert an incoming string into an outgoing byte-slice. Hopefully that's what you're after:
package mainimport "fmt"func stringToByteSlice(sc chan string, bc chan []byte) {defer close(bc)for s := range sc {bc <- []byte(s)}}func main() {strings := []string{"foo", "bar", "baz", "bat"}byteSlices := [][]byte{}sc := make(chan string)bc := make(chan []byte)go func() {defer close(sc)for _, s := range strings {sc <- s}}()go stringToByteSlice(sc, bc)for b := range bc {byteSlices = append(byteSlices, b)}fmt.Printf("%v\n", byteSlices)}
Outputs:
>[[102 111 111] [98 97 114] [98 97 122] [98 97 116]]
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