英文:
How to compare a value in a map with a set of known values
问题
我有一些代码，可以从URL中提取URL参数，并将其放入一个映射中。我可以成功地打印出我想要检查的映射项的值。
values := r.URL.Query()a := values["a"]fmt.Println(a)
我注意到当值打印时，它们被包围在"[]"中。
我想要比较每个a、b、c的值，并检查它是否包含在逗号分隔的字符串中。
allowedA := "value1,value2,value3"if strings.Contains(allowedA, a) {// 返回true}
意思是，如果'a'中的值包含在变量'allowedA'中，则返回true。
有什么建议吗？
英文:
I have some code that pulls out the URL parameters from a URL and places it into a map. I can successfully print out the values of the map items that I want to examine.
values := r.URL.Query()a := values["a"]fmt.Println(a)
I notice when the values print they print with "[]" surrounding them.
I'd like to value the value of each a,b,c and check to see if it is contained in a comma-delimited string.
allowedA = "value1,value2,value3"
i.e. something similar to:
if(contains(allowedA,a)
Meaning "if the value in 'a' is contained in the variable 'allowedA' then return true.
Any suggestions?
答案1
得分: 1
我注意到当值打印时，它们会用"[]"括起来。
这是因为url.Values是map[string][]string，而不是map[string]string。使用url.Values.Get直接访问参数。
我建议将字符串拆分，并将结果用作映射键，这样您可以将映射用作集合。例如：
allowedAMap := map[string]struct{}{}allowedAStrs := strings.Split(allowedA, ",")for _, s := range allowedAStrs {allowedAMap[s] = struct{}{}}//...if _, ok := allowedAMap[a]; !ok {fmt.Println("wrong a")return}fmt.Println("correct a")
英文:
>I notice when the values print they print with "[]" surrounding them.
That's because url.Values is map[string][]string, not map[string]string. Use url.Values.Get to access the parameter directly.
>I'd like to value the value of each a,b,c and check to see if it is contained in a comma-delimited string.
I'd suggest splitting the string and using the result as map keys, so that you could use the map as a set. I.e.
allowedAMap := map[string]struct{}{}allowedAStrs := strings.Split(allowedA, ",")for _, s := range allowedAStrs {allowedAMap展开收缩= struct{}{}}//...if _, ok := allowedAMap[a]; !ok {fmt.Println("wrong a")return}fmt.Println("correct a")
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