英文:
In Go Lang Set the Tag for a Whole Struct
问题
我正在使用Go和GoRestful来编写一个RESTful前端，用于访问存储在Google App Engine Datastore中的实体。
数据被转换为JSON/XML，并通过标签控制每种格式的样式来呈现给用户。我如何将标签应用于结构体名称本身，以便以正确的样式输出？
我的结构体示例如下：
type Shallow struct {
Key string `datastore:"-" json:"key" xml:"key"`
LastModified time.Time `json:"last_modified" xml:"last-modified"`
Version int `json:"version" xml:"version"`
Status int `json:"status" xml:"status"`
Link Link `datastore:"-" json:"link" xml:"link"`
Name string `json:"name" xml:"name"`
}
type ProbabilityEntry struct {
ItemId int64 `datastore:"ItemId" json:"item_id" xml:"item-id"`
Probability float32 `datastore:"Probability" json:"probability" xml:"probability"`
Quantity int16 `datastore:"Quantity" json:"quantity" xml:"quantity"`
}
type LootTable struct {
Shallow
AllowPreload bool `json:"allow_preload" xml:"allow-preload"`
Probabilities []ProbabilityEntry `json:"probabilities" xml:"probabilities"`
}
当LootTable结构体转换为JSON/XML时，它应该以'loot_table'或'loot-table'的形式表示自己，而不是'LootTable'。
英文:
I'm using Go and GoRestful to program a RESTFUL front end to some entities stored on Google App Engine Datastore.
The data is turned into JSON/XML and presented to the user with tags controlling the style for each format. How can I also apply tags to the name of the struct itself so it is output using the correct style?
An example of my structs would be:
type Shallow struct {
Key string `datastore:"-" json:"key" xml:"key"`
LastModified time.Time `json:"last_modified" xml:"last-modified"`
Version int `json:"version" xml:"version"`
Status int `json:"status" xml:"status"`
Link Link `datastore:"-" json:"link" xml:"link"`
Name string `json:"name" xml:"name"`
}
type ProbabilityEntry struct {
ItemId int64 `datastore:"ItemId" json:"item_id" xml:"item-id"`
Probability float32 `datastore:"Probability" json:"probability" xml:"probability"`
Quantity int16 `datastore:"Quantity" json:"quantity" xml:"quantity"`
}
type LootTable struct {
Shallow
AllowPreload bool `json:"allow_preload" xml:"allow-preload"`
Probabilities []ProbabilityEntry `json:"probabilities" xml:"probabilities"`
}
When the LootTable struct emits to JSON/XML it should represent itself as 'loot_table' or 'loot-table' rather than 'LootTable'.
答案1
得分: 4
简单回答：
将其包装在外部结构体中：
type Payload struct {
Loot LootTable `json:"loot_table"`
}
更详细的回答：
如果JSON的接收方知道他们将要接收的内容，那么这并不是必需的。然而，在构建JSON API时，我经常创建一个Response结构体，其中包含有关请求的额外细节，其中可能包括响应的类型。以下是一个示例：
type JSONResponse struct {
Obj interface{} `json:"obj"` // 未包装的JSON
Type string `json:"type"` // 例如："loot_table"
Ok bool `json:"ok"` // 此响应是否需要错误处理？
Errors []string `json:"errors"` // 任何错误，您可以省略Ok字段，只需检查此字段即可
}
同样，对于API调用，通常您知道您期望的内容，但如果响应可能是多种类型之一，这种方法可以帮助。
英文:
Simple answer:
Wrap it in an outer struct:
type Payload struct {
Loot LootTable `json:"loot_table"`
}
Longer answer:
If the receiver of the JSON knows what they're getting then this is not really necessary. However, when building a JSON API I often create a Response struct that contains extra details regarding the request, that could include the type of the response. Here is an example:
type JSONResponse struct {
Obj interface{} `json:"obj"` // Marshall'ed JSON (not wrapped)
Type string `json:"type"` // "loot_table" for example
Ok bool `json:"ok"` // Does this response require error handling?
Errors []string `json:"errors"` // Any errors, you could leave out Ok and just check this
}
Again, with API calls you usually know what you're expecting, but if the response could be one of a number of types this approach can help.
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