英文:
How to remove the last character of a string in Golang?
问题
我想要移除字符串的最后一个字符，但在这之前，我想要检查最后一个字符是否为“+”。这该如何实现？
英文:
I want to remove the very last character of a string, but before I do so I want to check if the last character is a "+". How can this be done?
答案1
得分: 72
以下是翻译好的部分：
这里有几种去除尾部加号的方法。
package main
import (
"fmt"
"strings"
)
func TrimSuffix(s, suffix string) string {
if strings.HasSuffix(s, suffix) {
s = s[:len(s)-len(suffix)]
}
return s
}
func main() {
s := "a string ++"
fmt.Println("s: ", s)
// 去除一个尾部的 '+'
s1 := s
if last := len(s1) - 1; last >= 0 && s1[last] == '+' {
s1 = s1[:last]
}
fmt.Println("s1:", s1)
// 去除所有尾部的 '+'
s2 := s
s2 = strings.TrimRight(s2, "+")
fmt.Println("s2:", s2)
// 去除后缀 '+'
s3 := s
s3 = TrimSuffix(s3, "+")
fmt.Println("s3:", s3)
}
输出：
s: a string ++
s1: a string +
s2: a string
s3: a string +
英文:
Here are several ways to remove trailing plus sign(s).
package main
import (
"fmt"
"strings"
)
func TrimSuffix(s, suffix string) string {
if strings.HasSuffix(s, suffix) {
s = s[:len(s)-len(suffix)]
}
return s
}
func main() {
s := "a string ++"
fmt.Println("s: ", s)
// Trim one trailing '+'.
s1 := s
if last := len(s1) - 1; last >= 0 && s1[last] == '+' {
s1 = s1[:last]
}
fmt.Println("s1:", s1)
// Trim all trailing '+'.
s2 := s
s2 = strings.TrimRight(s2, "+")
fmt.Println("s2:", s2)
// Trim suffix "+".
s3 := s
s3 = TrimSuffix(s3, "+")
fmt.Println("s3:", s3)
}
Output:
s: a string ++
s1: a string +
s2: a string
s3: a string +
答案2
得分: 40
根据@KarthikGR的评论，添加了以下示例：
https://play.golang.org/p/ekDeT02ZXoq
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.TrimSuffix("Foo++", "+"))
}
返回：
Foo+
英文:
Based on the comment of @KarthikGR the following example was added:
https://play.golang.org/p/ekDeT02ZXoq
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.TrimSuffix("Foo++", "+"))
}
returns:
Foo+
答案3
得分: 21
没有内置的方法。但是手动操作很简单。
s := "mystring+"
sz := len(s)
if sz > 0 && s[sz-1] == '+' {
s = s[:sz-1]
}
英文:
No builtin way. But it's trivial to do manually.
s := "mystring+"
sz := len(s)
if sz > 0 && s[sz-1] == '+' {
s = s[:sz-1]
}
答案4
得分: 1
package main
import (
"fmt"
)
func main() {
s := "venga|ese|sabor|"
newString := ""
if len(s) > 0 {
newString = s[:len(s)-1]
}
fmt.Println(newString)
}
output: venga|ese|sabor
go playground:
https://go.dev/play/p/o9ExIEuU0SF
英文:
package main
import (
"fmt"
)
func main() {
s := "venga|ese|sabor|"
newString := ""
if len(s) > 0 {
newString = s[:len(s)-1]
}
fmt.Println(newString)
}
output: venga|ese|sabor
go playground:
https://go.dev/play/p/o9ExIEuU0SF
答案5
得分: -1
一个简单的符合UTF规范的字符串修剪器是
string([]rune(foo)[:len(foo)-1]))
所以我会选择
f2 := []rune(foo)
for f2[len(f2)-1] == '+' {
f2 = f2[:len(f2)-1]
}
foo = string(f2)
https://go.dev/play/p/anOwXlfQWaF
我不确定为什么其他答案会以它们的方式修剪，因为它们是按字节修剪的。
英文:
@llazzaro
A simple UTF compliant string trimmer is
string([]rune(foo)[:len(foo)-1]))
So I'd go with
f2 := []rune(foo)
for f2[len(f2)-1] == '+'{
f2 = f2[:len(f2)-1]
}
foo = string(f2)
https://go.dev/play/p/anOwXlfQWaF
I'm not sure why the other answers trimmed the way that they do, because they're trimming bytes.
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