英文:
How to remove the last character of a string in Golang?
问题
我想要移除字符串的最后一个字符，但在这之前，我想要检查最后一个字符是否为“+”。这该如何实现？
英文:
I want to remove the very last character of a string, but before I do so I want to check if the last character is a "+". How can this be done?
答案1
得分: 72
以下是翻译好的部分：
这里有几种去除尾部加号的方法。
package mainimport ("fmt""strings")func TrimSuffix(s, suffix string) string {if strings.HasSuffix(s, suffix) {s = s[:len(s)-len(suffix)]}return s}func main() {s := "a string ++"fmt.Println("s: ", s)// 去除一个尾部的 '+'s1 := sif last := len(s1) - 1; last >= 0 && s1[last] == '+' {s1 = s1[:last]}fmt.Println("s1:", s1)// 去除所有尾部的 '+'s2 := ss2 = strings.TrimRight(s2, "+")fmt.Println("s2:", s2)// 去除后缀 '+'s3 := ss3 = TrimSuffix(s3, "+")fmt.Println("s3:", s3)}
输出：
s: a string ++s1: a string +s2: a strings3: a string +
英文:
Here are several ways to remove trailing plus sign(s).
package mainimport ("fmt""strings")func TrimSuffix(s, suffix string) string {if strings.HasSuffix(s, suffix) {s = s[:len(s)-len(suffix)]}return s}func main() {s := "a string ++"fmt.Println("s: ", s)// Trim one trailing '+'.s1 := sif last := len(s1) - 1; last >= 0 && s1[last] == '+' {s1 = s1[:last]}fmt.Println("s1:", s1)// Trim all trailing '+'.s2 := ss2 = strings.TrimRight(s2, "+")fmt.Println("s2:", s2)// Trim suffix "+".s3 := ss3 = TrimSuffix(s3, "+")fmt.Println("s3:", s3)}
Output:
s: a string ++s1: a string +s2: a strings3: a string +
答案2
得分: 40
根据@KarthikGR的评论，添加了以下示例：
https://play.golang.org/p/ekDeT02ZXoq
package mainimport ("fmt""strings")func main() {fmt.Println(strings.TrimSuffix("Foo++", "+"))}
返回：
Foo+
英文:
Based on the comment of @KarthikGR the following example was added:
https://play.golang.org/p/ekDeT02ZXoq
package mainimport ("fmt""strings")func main() {fmt.Println(strings.TrimSuffix("Foo++", "+"))}
returns:
Foo+
答案3
得分: 21
没有内置的方法。但是手动操作很简单。
s := "mystring+"sz := len(s)if sz > 0 && s[sz-1] == '+' {s = s[:sz-1]}
英文:
No builtin way. But it's trivial to do manually.
s := "mystring+"sz := len(s)if sz > 0 && s[sz-1] == '+' {s = s[:sz-1]}
答案4
得分: 1
package main
import (
"fmt"
)
func main() {
s := "venga|ese|sabor|"newString := ""if len(s) > 0 {newString = s[:len(s)-1]}fmt.Println(newString)
}
output: venga|ese|sabor
go playground:
https://go.dev/play/p/o9ExIEuU0SF
英文:
package mainimport ("fmt")func main() {s := "venga|ese|sabor|"newString := ""if len(s) > 0 {newString = s[:len(s)-1]}fmt.Println(newString)}
output: venga|ese|sabor
go playground:
https://go.dev/play/p/o9ExIEuU0SF
答案5
得分: -1
一个简单的符合UTF规范的字符串修剪器是
string([]rune(foo)[:len(foo)-1]))
所以我会选择
f2 := []rune(foo)for f2[len(f2)-1] == '+' {f2 = f2[:len(f2)-1]}foo = string(f2)
https://go.dev/play/p/anOwXlfQWaF
我不确定为什么其他答案会以它们的方式修剪，因为它们是按字节修剪的。
英文:
@llazzaro
A simple UTF compliant string trimmer is
string([]rune(foo)[:len(foo)-1]))
So I'd go with
f2 := []rune(foo)for f2[len(f2)-1] == '+'{f2 = f2[:len(f2)-1]}foo = string(f2)
https://go.dev/play/p/anOwXlfQWaF
I'm not sure why the other answers trimmed the way that they do, because they're trimming bytes.
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