英文:
How to replace a single character inside a string in Golang?
问题
我从用户那里得到一个物理位置地址，并尝试整理它以创建一个URL，稍后可以使用它从Google Geocode API获取JSON响应。
最终的URL字符串结果应该类似于这个，没有空格：
我不知道如何替换URL字符串中的空格，并用逗号代替。我稍微阅读了一下strings和regexp包，并创建了以下代码：
package mainimport ("fmt""bufio""os""http")func main() {// 获取物理地址r := bufio.NewReader(os.Stdin)fmt.Println("输入一个物理位置地址：")line, _, _ := r.ReadLine()// 打印输入的地址address := string(line)fmt.Println(address) // 需要看看我得到了什么// 创建URL并获取该地址的Google Geocode API JSON响应URL := "http://maps.googleapis.com/maps/api/geocode/json?address=" + address + "&sensor=true"fmt.Println(URL)result, _ := http.Get(URL)fmt.Println(result) // 看看我在这一点上得到了什么}
英文:
I am getting a physical location address from a user and trying to arrange it to create a URL that would use later to get a JSON response from Google Geocode API.
The final URL string result should be similar to this one, without spaces:
I do not know how to replace white spaces in my URL string and have commas instead. I did read a little about the strings and regexp packages and I have created the following code:
package mainimport ("fmt""bufio""os""http")func main() {// Get the physical addressr := bufio.NewReader(os.Stdin)fmt.Println("Enter a physical location address: ")line, _, _ := r.ReadLine()// Print the inputted addressaddress := string(line)fmt.Println(address) // Need to see what I'm getting// Create the URL and get Google's Geocode API JSON response for that addressURL := "http://maps.googleapis.com/maps/api/geocode/json?address=" + address + "&sensor=true"fmt.Println(URL)result, _ := http.Get(URL)fmt.Println(result) // To see what I'm getting at this point}
</pre></code>
答案1
得分: 97
你可以使用strings.Replace。
package mainimport ("fmt""strings")func main() {str := "一个以空格分隔的字符串"str = strings.Replace(str, " ", ",", -1)fmt.Println(str)}
如果你需要替换多个内容，或者需要多次进行相同的替换，最好使用strings.Replacer：
package mainimport ("fmt""strings")// replacer将空格替换为逗号，制表符替换为逗号。// 它是一个包级变量，所以我们可以轻松地重用它，但是// 这个程序没有利用这个特性。var replacer = strings.NewReplacer(" ", ",", "\t", ",")func main() {str := "一个以空格和制表符分隔的字符串"str = replacer.Replace(str)fmt.Println(str)}
当然，如果你是为了编码的目的而进行替换，比如URL编码，那么最好使用专门用于此目的的函数，比如url.QueryEscape。
英文:
You can use strings.Replace.
package mainimport ("fmt""strings")func main() {str := "a space-separated string"str = strings.Replace(str, " ", ",", -1)fmt.Println(str)}
If you need to replace more than one thing, or you'll need to do the same replacement over and over, it might be better to use a strings.Replacer:
package mainimport ("fmt""strings")// replacer replaces spaces with commas and tabs with commas.// It's a package-level variable so we can easily reuse it, but// this program doesn't take advantage of that fact.var replacer = strings.NewReplacer(" ", ",", "\t", ",")func main() {str := "a space- and\ttab-separated string"str = replacer.Replace(str)fmt.Println(str)}
And of course if you're replacing for the purpose of encoding, such as URL encoding, then it might be better to use a function specifically for that purpose, such as url.QueryEscape
答案2
得分: 10
如果您需要替换字符串中的所有字符出现，则使用strings.ReplaceAll：
package mainimport ("fmt""strings")func main() {str := "一个以空格分隔的字符串"str = strings.ReplaceAll(str, " ", ",")fmt.Println(str)}
英文:
If you need to replace all occurrences of the character in the string, then use strings.ReplaceAll:
package mainimport ("fmt""strings")func main() {str := "a space-separated string"str = strings.ReplaceAll(str, " ", ",")fmt.Println(str)}
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