英文:
Iterating through a golang map
问题
我有一个类型为map[string]interface{}的地图。
最后，我得到了创建类似以下内容的东西（在使用goyaml从yml文件反序列化之后）：
mymap = map[foo:map[first: 1] boo: map[second: 2]]
我该如何遍历这个地图？我尝试了以下方法：
for k, v := range mymap{
...
}
但是我得到了一个错误：
无法遍历mymap
循环类型检查涉及for循环
请帮忙。
英文:
I have a map of type: map[string]interface{}
And finally, I get to create something like (after deserializing from a yml file using goyaml)
mymap = map[foo:map[first: 1] boo: map[second: 2]]
How can I iterate through this map? I tried the following:
for k, v := range mymap{
...
}
But I get an error:
cannot range over mymap
typechecking loop involving for loop
Please help.
答案1
得分: 131
例如，
package main
import "fmt"
func main() {
type Map1 map[string]interface{}
type Map2 map[string]int
m := Map1{"foo": Map2{"first": 1}, "boo": Map2{"second": 2}}
//m = map[foo:map[first: 1] boo: map[second: 2]]
fmt.Println("m:", m)
for k, v := range m {
fmt.Println("k:", k, "v:", v)
}
}
输出：
m: map[boo:map[second:2] foo:map[first:1]]
k: boo v: map[second:2]
k: foo v: map[first:1]
英文:
For example,
package main
import "fmt"
func main() {
type Map1 map[string]interface{}
type Map2 map[string]int
m := Map1{"foo": Map2{"first": 1}, "boo": Map2{"second": 2}}
//m = map[foo:map[first: 1] boo: map[second: 2]]
fmt.Println("m:", m)
for k, v := range m {
fmt.Println("k:", k, "v:", v)
}
}
Output:
m: map[boo:map[second:2] foo:map[first:1]]
k: boo v: map[second:2]
k: foo v: map[first:1]
答案2
得分: 5
你可以像这样将其写成多行形式，
$ cat dict.go
package main
import "fmt"
func main() {
items := map[string]interface{}{
"foo": map[string]int{
"strength": 10,
"age": 2000,
},
"bar": map[string]int{
"strength": 20,
"age": 1000,
},
}
for key, value := range items {
fmt.Println("[", key, "] has items:")
for k,v := range value.(map[string]int) {
fmt.Println("\t-->", k, ":", v)
}
}
}
输出结果为：
$ go run dict.go
[ foo ] has items:
--> strength : 10
--> age : 2000
[ bar ] has items:
--> strength : 20
--> age : 1000
英文:
You could just write it out in multiline like this,
$ cat dict.go
package main
import "fmt"
func main() {
items := map[string]interface{}{
"foo": map[string]int{
"strength": 10,
"age": 2000,
},
"bar": map[string]int{
"strength": 20,
"age": 1000,
},
}
for key, value := range items {
fmt.Println("[", key, "] has items:")
for k,v := range value.(map[string]int) {
fmt.Println("\t-->", k, ":", v)
}
}
}
And the output:
$ go run dict.go
[ foo ] has items:
--> strength : 10
--> age : 2000
[ bar ] has items:
--> strength : 20
--> age : 1000
答案3
得分: 3
mymap := map[string]interface{}{"foo": map[string]interface{}{"first": 1}, "boo": map[string]interface{}{"second": 2}}
for k, v := range mymap {
fmt.Println("k:", k, "v:", v)
}
英文:
You can make it by one line:
mymap := map[string]interface{}{"foo": map[string]interface{}{"first": 1}, "boo": map[string]interface{}{"second": 2}}
for k, v := range mymap {
fmt.Println("k:", k, "v:", v)
}
Output is:
k: foo v: map[first:1]
k: boo v: map[second:2]
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论