C# List<> 属性到 XML

huangapple
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英文:

C# List<> property to XML

问题

这是您提供的代码片段的翻译：

  1. 获得了这段代码...
  3. public class CardLogos
  4. {
  5.     [XmlElement("Card")]
  6.     public string Card { get; set; }
  7. }
  9. public class P_M
  10. {
  11.     [XmlElement("Cards")]
  12.     public List<CardLogos> Cards { get; set; }
  13. }
  15. 尝试构建Cards属性:
  17. pm = new P_M();
  18. ...其他属性设置发生在这里
  19. pm.Cards = new List<CardLogos>();
  20. pm.Cards.Add(new CardLogos() {Card="VISA"});
  21. pm.Cards.Add(new CardLogos() {Card="AMEX"});
  22. pm.Cards.Add(new CardLogos() {Card="DISCOVER"});
  24. 但序列化的XML输出如下:
  26. <P_M>
  27.     <Other Properties>
  28.     <Cards>
  29.         <Card>VISA</Card>
  30.     </Cards>
  31.     <Cards>
  32.         <Card>AMEX</Card>
  33.     </Cards>
  34.     <Cards>
  35.         <Card>DISCOVER</Card>
  36.     </Cards>
  37. </P_M>
  39. 如何使其输出如下:
  41. <P_M>
  42.     <Other Properties>
  43.     <Cards>
  44.         <Card>VISA</Card>
  45.         <Card>AMEX</Card>
  46.         <Card>DISCOVER</Card>
  47.     </Cards>
  48. </P_M>
英文:

Got this code...

  1. public class CardLogos
  2. {
  3.     [XmlElement(&quot;Card&quot;)]
  4.     public string Card { get; set; }
  5. }
  7. public class P_M
  8. {
  9.     [XmlElement(&quot;Cards&quot;)]
  10.     public List&lt;CardLogos&gt; Cards { get; set; }
  11. }

Trying to build the Cards property:

  1. pm = new P_M();
  2. ...Other property setting happens here
  3. pm.Cards = new List&lt;CardLogos&gt;();
  4. pm.Cards.Add(new CardLogos() {Card=&quot;VISA&quot;});
  5. pm.Cards.Add(new CardLogos() {Card=&quot;AMEX&quot;});
  6. pm.Cards.Add(new CardLogos() {Card=&quot;DISCOVER&quot;});

But the serialized XML comes out like this:

  1. &lt;P_M&gt;
  2.     &lt;Other Properties&gt;
  3.     &lt;Cards&gt;
  4.         &lt;Card&gt;VISA&lt;/Card&gt;
  5.     &lt;/Cards&gt;
  6.     &lt;Cards&gt;
  7.         &lt;Card&gt;AMEX&lt;/Card&gt;
  8.     &lt;/Cards&gt;
  9.     &lt;Cards&gt;
  10.         &lt;Card&gt;DISCOVER&lt;/Card&gt;
  11.     &lt;/Cards&gt;
  12. &lt;/P_M&gt;

How can I make it come out like this:

  1. &lt;P_M&gt;
  2.     &lt;Other Properties&gt;
  3.     &lt;Cards&gt;
  4.         &lt;Card&gt;VISA&lt;/Card&gt;
  5.         &lt;Card&gt;AMEX&lt;/Card&gt;
  6.         &lt;Card&gt;DISCOVER&lt;/Card&gt;
  7.     &lt;/Cards&gt;
  8. &lt;/P_M&gt;

答案1

得分: 1

  1. 试试这个：
  3. ```csharp
  4. public class P_M
  5. {
  6.     [XmlArray("Cards")]
  7. 	[XmlArrayItem(ElementName= "Card")]
  8.     public List<CardLogos> Cards { get; set; }
  9. }
  11. public class CardLogos
  12. {
  13.     [XmlText]
  14.     public string Card { get; set; }
  15. }

它保留了所有原始类型，而不需要将其简化为 List<string>。CardLogos 中可能有的其他属性可以使用 XmlIgnore 属性跳过。

  2. <details>
  3. <summary>英文:</summary>
  5. Try this:

public class P_M
{
[XmlArray("Cards")]
[XmlArrayItem(ElementName= "Card")]
public List<CardLogos> Cards { get; set; }
}

public class CardLogos
{
[XmlText]
public string Card { get; set; }
}

  2. It preserves all of the original types, without needing to reduce down to a `List&lt;string&gt;`.  Any other properties you may have in `CardLogos` can be skipped over with `XmlIngore` attributes.
  4. </details>
  8. # 答案2
  9. **得分**: 0
  11. 你可以使用 [`XmlArray`][1] 和 [`XmlArrayItem`][2] 属性，并将 `Cards` 改为字符串列表：
  13. ```csharp
  14. public class P_M
  15. {
  16.     [XmlArray("Cards")]
  17. 	[XmlArrayItem(ElementName = "Card")]
  18.     public List<string> Cards { get; set; }
  19. }

结果如下：

  1. <?xml version="1.0" encoding="utf-8"?>
  2. <P_M xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  3.   <Cards>
  4.     <Card>VISA</Card>
  5.     <Card>AMEX</Card>
  6.     <Card>DISCOVER</Card>
  7.   </Cards>
  8. </P_M>

查看示例。

英文:

You can use the XmlArray and XmlArrayItem attributes and change Cards to a list of strings:

  1. public class P_M
  2. {
  3.     [XmlArray(&quot;Cards&quot;)]
  4. 	[XmlArrayItem(ElementName= &quot;Card&quot;)]
  5.     public List&lt;string&gt; Cards { get; set; }
  6. }

This results in:

  1. &lt;?xml version=&quot;1.0&quot; encoding=&quot;utf-8&quot;?&gt;
  2. &lt;P_M xmlns:xsi=&quot;http://www.w3.org/2001/XMLSchema-instance&quot; xmlns:xsd=&quot;http://www.w3.org/2001/XMLSchema&quot;&gt;
  3.   &lt;Cards&gt;
  4.     &lt;Card&gt;VISA&lt;/Card&gt;
  5.     &lt;Card&gt;AMEX&lt;/Card&gt;
  6.     &lt;Card&gt;DISCOVER&lt;/Card&gt;
  7.   &lt;/Cards&gt;
  8. &lt;/P_M&gt;

See this example.

huangapple
  • 本文由 发表于 2023年8月11日 02:34:05
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