计算上一个余额使用当前余额 – Oracle

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英文:

Oracle - Calculate Previous balance using Current Balance

问题

You can make the following changes to your query to obtain the desired output:

WITH CTE AS (
  SELECT 
    A.ACCOUNT_NO, 
    A.TRANSACTION_DATE, 
    A.TRANSACTION_AMOUNT, 
    B.CURRENT_BALANCE - SUM(A.TRANSACTION_AMOUNT) OVER (ORDER BY A.TRANSACTION_DATE) AS RUNNING_BALANCE 
  FROM TRAN A 
  INNER JOIN BAL B ON A.ACCOUNT_NO = B.ACCOUNT_NO
  WHERE A.ACCOUNT_NO = '11111111'
)
SELECT 
  ACCOUNT_NO,
  TRANSACTION_DATE,
  TRANSACTION_AMOUNT,
  RUNNING_BALANCE
FROM CTE;

This query uses a Common Table Expression (CTE) to calculate the running balance for each row, summing the transaction amounts in chronological order. Then, it selects the desired columns from the CTE to produce the output you desire.

英文:

I have 2 tables.

  1. Table TRAN has Account_no, Transaction_date and Transaction_Amount
  2. Table BAL has Account_no and Current_balance

I want to populate results from table TRAN for an account number along with a running balance using the current_balance from BAL table. (the last row should have the current_balance and the previous row should have the previous balance that is current_balance minus the transaction amount)

Here is how the data looks like in both the tables:

Table TRAN (1) and BAL (2)

Here is how i want the output to look like:

The Output I Desire

Here is the code i tried using:

SELECT 
A.ACCOUNT_NO, 
A.TRANSACTION_DATE, 
A.TRANSACTION_AMOUNT, 
B.CURRENT_BALANCE - LAG(A.TRANSACTION_AMOUNT) OVER (ORDER BY A.TRANSACTION_DATE) RUNNING_BALANCE 
FROM TRAN A 
INNER JOIN BAL B ON A.ACCOUNT_NO=B.ACCOUNT_NO
WHERE A.ACCOUNT_NO='11111111';

I get the below output:

Query Result

What changes do I make to the query to obtain "the output I desire"?

答案1

得分: 1

以下是要翻译的内容:

经过多次尝试,我终于弄清楚了如何通过从当前余额中减去交易金额来填充以前的余额。

查询显示了来自A表的历史记录,连接了B表,并使用当前余额计算了运行余额。

SUM函数用于通过从当前余额中减去交易金额来计算以前的余额。

OVER子句用于指定行的分区和排序,以计算运行余额。

ORDER BY子句用于按交易日期降序排列行,以使最新的交易具有当前余额。

查询的最后部分+ A.TRANSACTION_AMOUNT将交易金额添加回以获取以前的余额。

英文:

After many attempts I finally figured out how to populate the previous balance by subtracting the transaction_amount from the current_balance.

SELECT 
A.ACCOUNT_NO, 
A.TRANSACTION_DATE, 
A.TRANSACTION_AMOUNT, 
B.CURRENT_BALANCE - (SUM(A.TRANSACTION_AMOUNT) OVER (PARTITION BY A.ACCOUNT_NO ORDER BY A.TRANSACTION_DATE DESC)) +  A.TRANSACTION_AMOUNT RUNNING_BALANCE
FROM TRAN A 
INNER JOIN BAL B ON A.ACCOUNT_NO=B.ACCOUNT_NO
WHERE A.ACCOUNT_NO='11111111'
ORDER BY A.ACCOUNT_NO, A.TRANSACTION_DATE;

Please upvote this answer if you find it helpful.

The query displays the history from Table A, joins Table B and calculates the running_balance using the current_balance.

The SUM function is used to calculate the previous balance by subtracting the transaction_amount from the current_balance.

The OVER clause is used to specify the partitioning and ordering of the rows for the calculation of the running_balance.

The ORDER BY clause is used to order the rows in descending order by transaction_date so that the latest transaction has the current_balance.

The + A.TRANSACTION_AMOUNT part of the query adds back in the transaction_amount to get the previous balance.

答案2

得分: 0

Sure, here's the translated code:

为什么要保留两个表格,而不从一个表格中保留运行余额?

我做了类似的事情。您可以查看我的解决方案。

ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH24:MI:SS';

CREATE TABLE CUSTOMERS (
CUSTOMER_ID, FIRST_NAME, LAST_NAME,IS_ACTIVE) AS 
SELECT 'E379466', 'Bonnie', 'Winterbottom','Y' FROM DUAL  UNION ALL 
SELECT 'Z098555', 'Peter', 'Clemenza','Y' FROM DUAL;


CREATE TABLE CUSTOMER_ACCOUNTS (
ACCOUNT_NUMBER,
CUSTOMER_ID, VENDOR_ID,
IS_ACTIVE) AS 
SELECT 'THVQD6M9LR7AVK', 'E379466', 1, 'Y' FROM DUAL  UNION ALL 
SELECT '0Z76WT5NTLRZPTW',
'Z098555', 1, 'Y' FROM DUAL;

create table transactions (
     transaction_id NUMBER GENERATED BY DEFAULT AS IDENTITY,
    account_number VARCHAR2(15),
    transaction_type varchar2(1) DEFAULT 'C',
    transaction_amount NUMBER(10,2),
     transaction_date DATE DEFAULT SYSDATE 
);

insert  into transactions(
account_number, transaction_type, transaction_amount, transaction_date)
SELECT '0Z76WT5NTLRZPTW', 'D', (LEVEL * 100.57), date '2023-04-02' + level * interval '1 4' day to hour from dual
          connect by level <= 5
union all
SELECT '0Z76WT5NTLRZPTW', 'C', (LEVEL * 25.26), date '2023-04-04' + level * interval '1 4' day to hour from dual
          connect by level <= 5
union all
SELECT 'THVQD6M9LR7AVK', 'D', (LEVEL * 50.10), date '2023-05-10' + level * interval '1 7' day to hour from dual
          connect by level <= 13
union all
SELECT 'THVQD6M9LR7AVK', 'D', (LEVEL * 33.11), date '2023-05-10' + level * interval '1 7' day to hour from dual
          connect by level <= 9;

CREATE OR REPLACE FUNCTION   get_customer_balance
(  i_customer_id   IN   customers.customer_id%TYPE
)
RETURN  transactions.transaction_amount%TYPE
IS
  v_balance   transactions.transaction_amount%TYPE;
BEGIN
  SELECT SUM (
                 CASE  t.transaction_type
		     WHEN  'C'
		     THEN  -t.transaction_amount
		     ELSE  t.transaction_amount
	 	 END 
             )
  INTO   v_balance
  FROM	 customer_accounts  ca
  JOIN	 transactions  	    t  ON  t.account_number  = ca.account_number
  WHERE  ca.customer_id  = i_customer_id  -- one customer
  OR     ca.customer_id  IS NULL;         -- all customers

  RETURN v_balance;
END  get_customer_balance;
/


CREATE OR REPLACE FUNCTION get_account_balance(
  i_account_number IN TRANSACTIONS.ACCOUNT_NUMBER%TYPE
) RETURN TRANSACTIONS.TRANSACTION_AMOUNT%TYPE
IS
  v_balance TRANSACTIONS.TRANSACTION_AMOUNT%TYPE;
BEGIN
  SELECT SUM(
           CASE transaction_type WHEN 'C' THEN -1 ELSE 1 END 
           * transaction_amount
         )
  INTO   v_balance
  FROM   transactions
  WHERE  account_number = i_account_number -- one account
  OR     i_account_number IS NULL;         -- all accounts
  RETURN v_balance;
END;
/


SELECT CA.ACCOUNT_NUMBER,
       C.FIRST_NAME,
       C.LAST_NAME, 
       CA.IS_ACTIVE,
       get_account_balance(ca.account_number) AS balance
FROM   CUSTOMER_ACCOUNTS CA
       INNER JOIN customers c
       ON ca.customer_id = c.customer_id;

/* 账户的交易历史记录 */

WITH  daily_summary  AS
(
	SELECT	
account_number,
 transaction_date
	,	 SUM (DECODE (transaction_type, 'C', transaction_amount, 0))	AS credit_total
	,	 SUM (DECODE (transaction_type, 'D', transaction_amount , 0))	AS debit_total
	FROM	 transactions
	GROUP BY  account_number, transaction_date 
)
SELECT   d.*
,	 SUM (debit_total - credit_total)
	   OVER (ORDER BY transaction_date) AS balance_to_date
FROM    daily_summary d
WHERE account_number = 
'0Z76WT5NTLRZPTW'
ORDER BY transaction_date;

Please note that the code has been translated, and I've removed the parts that weren't code-related from your original text. If you have any specific questions or need further assistance, feel free to ask.

英文:

Why are you keeping two tables when you can keep a running balance from one table?

I did something similar. You may want to look at my solution.


ALTER SESSION SET NLS_DATE_FORMAT = &#39;DD-MON-YYYY HH24:MI:SS&#39;;
CREATE TABLE CUSTOMERS (
CUSTOMER_ID, FIRST_NAME, LAST_NAME,IS_ACTIVE) AS 
SELECT &#39;E379466&#39;, &#39;Bonnie&#39;, &#39;Winterbottom&#39;,&#39;Y&#39; FROM DUAL  UNION ALL 
SELECT &#39;Z098555&#39;, &#39;Peter&#39;, &#39;Clemenza&#39;,&#39;Y&#39; FROM DUAL;
CREATE TABLE CUSTOMER_ACCOUNTS (
ACCOUNT_NUMBER,
CUSTOMER_ID, VENDOR_ID,
IS_ACTIVE) AS 
SELECT &#39;THVQD6M9LR7AVK&#39;, &#39;E379466&#39;, 1, &#39;Y&#39; FROM DUAL  UNION ALL 
SELECT &#39;0Z76WT5NTLRZPTW&#39;,
&#39;Z098555&#39;, 1, &#39;Y&#39; FROM DUAL;
create table transactions (
transaction_id NUMBER GENERATED BY DEFAULT AS IDENTITY,
account_number VARCHAR2(15),
transaction_type varchar2(1) DEFAULT &#39;C&#39;,
transaction_amount NUMBER(10,2),
transaction_date DATE DEFAULT SYSDATE 
);
insert  into transactions(
account_number, transaction_type, transaction_amount, transaction_date)
SELECT &#39;0Z76WT5NTLRZPTW&#39;, &#39;D&#39;, (LEVEL * 100.57), date &#39;2023-04-02&#39; + level * interval &#39;1 4&#39; day to hour from dual
connect by level &lt;= 5
union all
SELECT &#39;0Z76WT5NTLRZPTW&#39;, &#39;C&#39;, (LEVEL * 25.26), date &#39;2023-04-04&#39; + level * interval &#39;1 4&#39; day to hour from dual
connect by level &lt;= 5
union all
SELECT &#39;THVQD6M9LR7AVK&#39;, &#39;D&#39;, (LEVEL * 50.10), date &#39;2023-05-10&#39; + level * interval &#39;1 7&#39; day to hour from dual
connect by level &lt;= 13
union all
SELECT &#39;THVQD6M9LR7AVK&#39;, &#39;D&#39;, (LEVEL * 33.11), date &#39;2023-05-10&#39; + level * interval &#39;1 7&#39; day to hour from dual
connect by level &lt;= 9;
CREATE OR REPLACE FUNCTION   get_customer_balance
(  i_customer_id   IN   customers.customer_id%TYPE
)
RETURN  transactions.transaction_amount%TYPE
IS
v_balance   transactions.transaction_amount%TYPE;
BEGIN
SELECT SUM (
CASE  t.transaction_type
WHEN  &#39;C&#39;
THEN  -t.transaction_amount
ELSE  t.transaction_amount
END 
)
INTO   v_balance
FROM	 customer_accounts  ca
JOIN	 transactions  	    t  ON  t.account_number  = ca.account_number
WHERE  ca.customer_id  = i_customer_id  -- one customer
OR     ca.customer_id  IS NULL;         -- all customers
RETURN v_balance;
END  get_customer_balance;
/
CREATE OR REPLACE FUNCTION get_account_balance(
i_account_number IN TRANSACTIONS.ACCOUNT_NUMBER%TYPE
) RETURN TRANSACTIONS.TRANSACTION_AMOUNT%TYPE
IS
v_balance TRANSACTIONS.TRANSACTION_AMOUNT%TYPE;
BEGIN
SELECT SUM(
CASE transaction_type WHEN &#39;C&#39; THEN -1 ELSE 1 END 
* transaction_amount
)
INTO   v_balance
FROM   transactions
WHERE  account_number = i_account_number -- one account
OR     i_account_number IS NULL;         -- all accounts
RETURN v_balance;
END;
/
SELECT CA.ACCOUNT_NUMBER,
C.FIRST_NAME,
C.LAST_NAME, 
CA.IS_ACTIVE,
get_account_balance(ca.account_number) AS balance
FROM   CUSTOMER_ACCOUNTS CA
INNER JOIN customers c
ON ca.customer_id = c.customer_id;
/* transaction history for an account */
WITH  daily_summary  AS
(
SELECT	
account_number,
transaction_date
,	 SUM (DECODE (transaction_type, &#39;C&#39;, transaction_amount, 0))	AS credit_total
,	 SUM (DECODE (transaction_type, &#39;D&#39;, transaction_amount , 0))	AS debit_total
FROM	 transactions
GROUP BY  account_number, transaction_date 
)
SELECT   d.*
,	 SUM (debit_total - credit_total)
OVER (ORDER BY transaction_date) AS balance_to_date
FROM    daily_summary d
WHERE account_number = 
&#39;0Z76WT5NTLRZPTW&#39;
ORDER BY transaction_date;

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  • 本文由 发表于 2023年8月11日 02:21:17
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