英文:
What do I need to import to do bitwise operations?
问题
以下是代码的翻译部分：
我尝试使用位运算符，但我无法弄清楚我需要导入什么。
import Data.Word
import Data.Bits
mask = 0xff :: Word64
v = 98213 :: Word64
lsb = mask .&. v
这是我看到的内容：
ghci tmp.hs
GHCi，版本9.2.8：https://www.haskell.org/ghc/ :? 获取帮助
[1 of 1] Compiling Main ( tmp.hs, interpreted )
tmp.hs:7:12: 错误：
变量不在范围内：(&) :: Word64 -> Word64 -> t
|
7 | lsb = mask & v
| ^
失败，未加载任何模块。
ghci>
请注意，我已将原始代码中的&改为了正常的.&.以修复错误。
英文:
I'm trying to use bitwise operators and I can't figure out what I need to import.
$ cat tmp.hs
import Data.Word
import Data.Bits
mask = 0xff :: Word64
v = 98213 :: Word64
lsb = mask & v
And this is what I see:
$ ghci tmp.hs
GHCi, version 9.2.8: https://www.haskell.org/ghc/ :? for help
[1 of 1] Compiling Main ( tmp.hs, interpreted )
tmp.hs:7:12: error:
Variable not in scope: (&) :: Word64 -> Word64 -> t
|
7 | lsb = mask & v
| ^
Failed, no modules loaded.
ghci>
答案1
得分: 4
已经导入了这个。但是在Haskell中，位运算操作符是(.&.) :: Bits a => a -> a -> a, (.|.) :: Bits a => a -> a -> a和(.^.) :: Bits a => a -> a -> a，所以：
lsb = mask .&. v
英文:
You already imported this. But in Haskell, the bitwise operators are (.&.) :: Bits a => a -> a -> a, (.|.) :: Bits a => a -> a -> a, and (.^.) :: Bits a => a -> a -> a, so:
<pre><code>lsb = mask <b>.&.</b> v</code></pre>
答案2
得分: 1
I think you meant to use [.&.] from Data.Bits. The & operand is the reverse of $ in Haskell from base
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