How to use ofstream as a part of struct - arg of function

I am trying to use ofstream, opened in function getlog() in function WriteLine(). I have a structure named LOG:

struct LOG {
	wchar_t logfile[PARM_MAX_SIZE];
	std::ofstream* stream;
};

which is an argument of function WriteLine(). When I am trying to use this stream, there is an error of reading.

I am trying to use a reference on a LOG variable. I tried to convert ofstream* stream to ofstream& but I don't know how to do it properly, because initialization of a LOG is:

static const LOG INITLOG {L"", NULL};

and I don't know how to change it to use a reference on a stream.

Functions:

LOG getlog(wchar_t logfile[]) {
	ofstream logf(logfile, ios::app);
	if (!logf.is_open()) {
		throw ERROR_THROW(112)
	}
	LOG log{};
	wcscpy_s(log.logfile, logfile);
	log.stream = &logf;
	return log;
}

void WriteLine(LOG log, char* c, ...) {
	char str[80]{};
	char** p = &c;
	while (*p[0]) {
		strcat_s(str, *p);
		p++;
	}
	str[strlen(str)] = '
LOG getlog(wchar_t logfile[]) {
ofstream logf(logfile, ios::app);
if (!logf.is_open()) {
throw ERROR_THROW(112)
}
LOG log{};
wcscpy_s(log.logfile, logfile);
log.stream = &logf;
return log;
}
void WriteLine(LOG log, char* c, ...) {
char str[80]{};
char** p = &c;
while (*p[0]) {
strcat_s(str, *p);
p++;
}
str[strlen(str)] = '\0';
ofstream* logf = log.stream;
*logf << "str";
}
';
	ofstream* logf = log.stream;
	*logf << "str";
}

main function

int _tmain(int argc, wchar_t* argv[]) {
	setlocale(LC_ALL, "rus");
	Log::LOG log = Log::INITLOG;
	try {
		Parm::PARM parms = Parm::getparm(argc, argv);
		log = Log::getlog(parms.log);
		Log::WriteLine(log, (char*)"Тест:", (char*)" без ошибок \n", "");
		/*Log::WriteLine(log, (wchar_t*)L"Тест:", (wchar_t*)L" без ошибок \n", L"");
		Log::WriteLog(log);*/
	}
	catch (Error::ERROR e) {
		cout << "Ошибка " << e.id << ": " << e.message << ", строка " << e.inext.line << ", позиция " << e.inext.col << endl << endl;
	}

	system("pause");
	return 0;
}

Your getlog() function is creating a new stream and returning it, but is doing so by returning a pointer to a local variable that goes out of scope when the function exits. To avoid that, you will need to create the stream dynamically instead, eg:

struct LOG {
    std::wstring logfile;
    std::unique_ptr<std::ofstream> stream;
};

LOG getlog(const wchar_t* logfile) {
    LOG log;
    log.logfile = logfile;
    log.stream = std::make_unique<std::ofstream>(logfile, std::ios::app);
    if (!log.stream->is_open()) {
        throw ERROR_THROW(112)
    }
    return log;
}

template<typename... Args>
void WriteLine(LOG& log, Args&&... args) {
    (*(log.stream) << ... << args) << '\n';
}

int _tmain(int argc, wchar_t* argv[]) {
    setlocale(LC_ALL, "rus");
    try {
        Parm::PARM parms = Parm::getparm(argc, argv);
        Log::LOG log = Log::getlog(parms.log);
        Log::WriteLine(log, "Тест:", " без ошибок ");
        /*Log::WriteLine(log, L"Тест:", L" без ошибок ");
        Log::WriteLog(log);*/
    }
    catch (Error::ERROR e) {
        cout << "Ошибка " << e.id << ": " << e.message << ", строка " << e.inext.line << ", позиция " << e.inext.col << endl << endl;
    }

    std::system("pause");
    return 0;
}