英文:
Flatten pandas dataframe multiindex
问题
我有一个使用以下数据创建的数据框：
data = {'Date': ['2021-06-15T00:10:00', '2021-06-15T00:10:00', '2021-06-15T00:10:00', '2021-06-15T00:20:00', '2021-06-15T00:20:00', '2021-06-15T00:20:00'],'Distance': ['50', '100', '150', '50', '100', '150'],'WS': [10, 20, 30, 40, 50, 60],'DIR': [11, 21, 31, 41, 51, 61]}df = pd.DataFrame(data)print(df)
我想将它展开，使其看起来像这样：
WS_50 DIR_50 WS_100 DIR_100 WS_150 DIR_50Date2021-06-15 00:10:00 10 11 20 21 30 312021-06-15 00:20:00 40 41 50 51 60 61
我尝试使用pivot函数，但是它产生了以下结果：
df['Date'] = pd.to_datetime(df['Date'])pivot_df = df.pivot(index='Date', columns='Distance', values=['WS', 'DIR'])WS DIRDistance 100 150 50 100 150 50Date2021-06-15 00:10:00 20 30 10 21 31 112021-06-15 00:20:00 50 60 40 51 61 41
正如您所看到的，它是按WS和DIR组织的，而我希望它按Distance（50、100、150）组织。
英文:
I have a dataframe created with the following:
data = {'Date': ['2021-06-15T00:10:00', '2021-06-15T00:10:00', '2021-06-15T00:10:00', '2021-06-15T00:20:00', '2021-06-15T00:20:00', '2021-06-15T00:20:00'],'Distance': ['50', '100', '150', '50', '100', '150'],'WS': [10, 20, 30, 40, 50, 60],'DIR': [11, 21, 31, 41, 51, 61]}df = pd.DataFrame(data)print(df)Date Distance WS DIR0 2021-06-15T00:10:00 50 10 111 2021-06-15T00:10:00 100 20 212 2021-06-15T00:10:00 150 30 313 2021-06-15T00:20:00 50 40 414 2021-06-15T00:20:00 100 50 515 2021-06-15T00:20:00 150 60 61
And I want to flatten it so it looks like this:
WS_50 DIR_50 WS_100 DIR_100 WS_150 DIR_50Date2021-06-15 00:10:00 10 11 20 21 30 312021-06-15 00:20:00 40 41 50 51 60 61
I have tried using the pivot function but that produces the following:
df['Date'] = pd.to_datetime(df['Date'])pivot_df = df.pivot(index='Date', columns='Distance', values=['WS', 'DIR'])WS DIRDistance 100 150 50 100 150 50Date2021-06-15 00:10:00 20 30 10 21 31 112021-06-15 00:20:00 50 60 40 51 61 41
As you can see, it's organized by WS and DIR, and I want it organized by Distance (50, 100, 150).
Thanks
答案1
得分: 2
请尝试以下代码：
df_out = df.set_index(['Date', 'Distance'], append=True).unstack()df_out.columns = [f'{i}_{j}' for i, j in df_out.columns]df_out = df_out.groupby('Date').first()df_out = df_out.sort_index(key=lambda x: df_out.columns.str.split('_').str[1].astype(int), axis=1)df_out
输出结果：
WS_50 DIR_50 WS_100 DIR_100 WS_150 DIR_150Date2021-06-15T00:10:00 10.0 11.0 20.0 21.0 30.0 31.02021-06-15T00:20:00 40.0 41.0 50.0 51.0 60.0 61.0
英文:
Try this:
df_out = df.set_index(['Date','Distance'], append=True).unstack()df_out.columns = [f'{i}_{j}' for i, j in df_out.columns]df_out = df_out.groupby('Date').first()df_out = df_out.sort_index(key=lambda x: df_out.columns.str.split('_').str[1].astype(int), axis=1)df_out
Output:
WS_50 DIR_50 WS_100 DIR_100 WS_150 DIR_150Date2021-06-15T00:10:00 10.0 11.0 20.0 21.0 30.0 31.02021-06-15T00:20:00 40.0 41.0 50.0 51.0 60.0 61.0
答案2
得分: 1
你可以使用整数类型，对索引进行排序，然后展开：
df['Date'] = pd.to_datetime(df['Date'])pivot_df = (df.astype({'Distance': int}).pivot(index='Date', columns='Distance', values=['WS', 'DIR']).sort_index(level='Distance', sort_remaining=False, axis=1))pivot_df.columns = pivot_df.columns.map(lambda x: f'{x[0]}_{x[1]}')
输出结果：
WS_50 DIR_50 WS_100 DIR_100 WS_150 DIR_150Date2021-06-15 00:10:00 10 11 20 21 30 312021-06-15 00:20:00 40 41 50 51 60 61
注意：这段代码是用来处理数据的，具体操作需要在合适的上下文中使用。
英文:
You can use an integer type, sort the index, then flatten:
df['Date'] = pd.to_datetime(df['Date'])pivot_df = (df.astype({'Distance': int}).pivot(index='Date', columns='Distance', values=['WS', 'DIR']).sort_index(level='Distance', sort_remaining=False, axis=1))pivot_df.columns = pivot_df.columns.map(lambda x: f'{x[0]}_{x[1]}')
Output:
WS_50 DIR_50 WS_100 DIR_100 WS_150 DIR_150Date2021-06-15 00:10:00 10 11 20 21 30 312021-06-15 00:20:00 40 41 50 51 60 61
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