Deployed application at context path [/abc] but context failed to start - Maven Spring Project Issue

I have a maven spring web-app which is deployed on AWS Beanstalk and working fine. Now, I want to shift it to OCI VPS/VM and use tomcat7-maven-plugin to deploy using the maven command. Using command line args to pass DB credentials. followed the below steps but deployment is failing.

1. Installed Maven and Tomcat 9.
2. Added a user in tomcat-users.xml with role manager-script

<user username="role-user<" password="role-pwd" roles="manager-script"/>

3. Added the plugin in pom.xml

<plugin>
     <groupId>org.apache.tomcat.maven</groupId>
     <artifactId>tomcat7-maven-plugin</artifactId>
     <version>2.2</version>
     <configuration>
         <url>http://localhost:8080/manager/text</url>
		 <username>role-user</username>
		 <password>role-pwd</password>
         <path>/abc</path>
		 <update>true</update>
     </configuration>
</plugin>

4. Ran the command to deploy - mvn -Ddb.user=db-user -Ddb.pwd=db-pwd tomcat7:deploy

It uploads the WAR in /webapps then fails with this message FAIL - Deployed application at context path [/abc] but context failed to start.

I tried it on my local also, thinking maybe the setup on VM needs some additional config, didn't work.

In the logs, it says db.user property not found, so not able to read command line args for some reason.

Invalid bean definition with name 'dataSource' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Could not resolve placeholder

Before trying the above steps, I tried to upload the WAR file via the Tomcat UI and it didn't work because I don't know how to pass additional args there or if it is even possible.

If someone can help with either of those approaches it would be much appreciated.

TIA

PS - I am not a Java developer and this is a side project I work on sometimes, last time I used java/tomcat in a project was more than 7 yrs ago. So, maybe there is a silly mistake or straight forward solution and I am not aware of it.

mvn -Ddb.user=db-user -Ddb.pwd=db-pwd tomcat7:deploy

This command does not mean that war will be deployed in a tomcat VM with these system properties (db.user, db.pwd) The documentation is not good enough (https://tomcat.apache.org/maven-plugin-2.2/run-mojo-features.html) but look at the systemProperties section

<plugin>
 <groupId>org.apache.tomcat.maven</groupId>
 <artifactId>tomcat7-maven-plugin</artifactId>
 <version>2.2</version>
 <configuration>
     <url>http://localhost:8080/manager/text</url>
     <username>role-user</username>
     <password>role-pwd</password>
     <path>/abc</path>
     <update>true</update>
     <systemProperties>
       <db.user>${db.user}</db.user>
       <db.pwd>${db.pwd}</db.pwd>
    </systemProperties>
 </configuration>
</plugin>

And then run via mvn command:

mvn -Ddb.user=db-user -Ddb.pwd=db-pwd tomcat7:deploy

This should hopefully work.

I was able to make it work after some tweaks

Remove username,password and url from plugin details

<plugin>
 <groupId>org.apache.tomcat.maven</groupId>
 <artifactId>tomcat7-maven-plugin</artifactId>
 <version>2.2</version>
 <configuration>
     <path>/abc</path>
     <update>true</update>
     <systemProperties>
       <db.user>${db.user}</db.user>
       <db.pwd>${db.pwd}</db.pwd>
    </systemProperties>
 </configuration>
</plugin>

Use the below command to deploy
mvn -Ddb.user=db-user -Ddb.pwd=db-pwd tomcat7:run

It will start its own tomcat container, hence is no need to run any instance of tomcat beforehand or create any user in tomcat-users.xml

Once you see the below lines on terminal/cmd

Aug 10, 2023 11:49:25 AM org.apache.coyote.AbstractProtocol start
INFO: Starting ProtocolHandler ["http-bio-8080"]

App is deployed and can be checke on the browser at localhost:8080/abc

If need to change port(eg-8081) add <port>8081</port> under configuration tag

But now I am curious about how the previous thing works, have seen many posts/blogs about that. If anybody knows, please comment.