英文:
Exiting loop in Arduino after doing an operation for specific number of times
问题
我可以帮你修改Arduino中的void loop函数，使其在打开和关闭灯/电磁阀30次后退出循环。修改后的代码如下：
int relay = 8;int count = 0;void setup() {// put your setup code here, to run once:pinMode(relay, OUTPUT);}void loop() {// put your main code here, to run repeatedly:if (count < 30) {digitalWrite(relay, HIGH);delay(5000);digitalWrite(relay, LOW);delay(200);count++;} else {// Exit the loopwhile (true) {// Do nothing or add your desired code here}}}
这样修改后，当循环执行了30次后，程序将进入一个无限循环，你可以在其中添加你想要的代码，或者保持空白。这样就实现了在打开和关闭灯/电磁阀30次后退出循环的功能。希望对你有帮助！
英文:
I want to turn on light/solenoid valve on and off 30 times only, and after that I want to exit the loop. How can I modify the void loop in Arduino? My program is given below. Thanks for your help.
int relay = 8;void setup() {// put your setup code here, to run once:pinMode(relay, OUTPUT);}void loop() {// put your main code here, to run repeatedly:digitalWrite(relay, HIGH);delay(5000);digitalWrite(relay, LOW);delay(200);}
答案1
得分: 1
只需使用一个for循环。我不会帮你做作业，但你可以查看这个网站：https://www.geeksforgeeks.org/python-for-loops/
英文:
Just use a for loop. I won't do your homework for you, but check this site. https://www.geeksforgeeks.org/python-for-loops/
答案2
得分: 0
这个想法是将你的代码从loop函数中移出（该函数在循环中被无限调用），而是在setup函数中调用你的代码一次（该函数只被调用一次）。
然后，你可以使用一个for循环来重复执行你的代码n次（在这个例子中是30次）。
这里有一个示例（显然可以进行重构），但应该能够演示你想要实现的目标：
int relay = 8;void setup() {// 在这里放置你的设置代码，只运行一次：pinMode(relay, OUTPUT);// 切换30次for (int i = 0; i < 30; i++) {digitalWrite(relay, HIGH);delay(5000);digitalWrite(relay, LOW);delay(200);}}void loop() {// 在这里放置你的主要代码，重复运行：}
英文:
The idea is to move your code out of the loop function (which is called forever in a loop), and instead to call your code once in the setup function (which is called once).
You then can wrap your code in a for loop to have it repeat n times (in this case 30).
Here is an example (which obviously can be refactored), but should demonstrate what you are trying to accomplish:
int relay = 8;void setup() {// put your setup code here, to run once:pinMode(relay, OUTPUT);// toggle 30 timesfor (int i = 0; i < 30; i++) {digitalWrite(relay, HIGH);delay(5000);digitalWrite(relay, LOW);delay(200);}}void loop() {// put your main code here, to run repeatedly:}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论