英文:
How to "ignore" arguments
问题
我正在用Python制作一个任务管理器，它使用一个JSON文件作为存档，并保存用户提供给程序的信息。我创建了一个包含不同函数的Python文件来管理这些输入。
当收集到信息后，我创建了一个函数将这些信息添加到JSON文件中。
import json
def setTitle():
# 收集用户输入
appendJson(task=userInput)
def setDescription():
# 收集用户输入
appendJson(description=userInput)
def appendJson(task, description):
# 生成JSON项
当我运行代码时，会出现错误，因为我没有提及其他参数。
所以基本上我应该写成appendJson(task=userInput, description=bla bla)，问题是如果我这样写，代码就无法工作。
那么有没有办法在函数调用中省略第二个参数？
如果你对某些地方不理解，请在评论中告诉我。
谢谢 <3
英文:
I'm making a task manager in python that uses a json file as an archive and to save the informations that the user gives to the program i made a python file with different functions that manages those inputs.
And then when the infos are collected I made a function that adds those infos to the json file
import json
def setTitle():
#collects user's input
appendJson(task=userInput)
def setDescription():
#collects user's input
appendJson(description=userInput)
def appendJson (task, description):
#generate the json item
When I run the code it gives me an error because I didn't mention the other arguments.
So basically I should've wrote appendJson(task=userInput, description=bla bla) and the problem is that the code doesn't work if I wrote that.
So is there a way to omit the second argument in the function call?
If you did not understand something tell me in the comments
Thanks <3
答案1
得分: 1
如果你想在调用函数时不必每次都提供每个参数，你可以使用关键字参数：
def appendJson(task, description=None):
# 生成json项
在这种情况下，第一个参数将始终被解释为task，你可以选择通过appendJson(task, description="randomdescription")来提供description。
如果你想让两个参数都是可选的，你可以将两个参数都设置为关键字参数：
def appendJson(task=None, description=None):
# 生成json项
英文:
If you want to be able to call the function without having to provide every argument each time, you can use a keyword argument instead:
def appendJson(task, description=None):
#generate the json item
In that case, the first argument will always be interpreted as task and you can optionally supply description via appendJson(task, description="randomdescription").
If you want to have both optional, you can make both arguments a keyword argument:
def appendJson(task=None, description=None):
#generate the json item
答案2
得分: 1
修复了，
给参数分配一个默认值，像这样：
def appendJson(task="默认值", description="默认值"):
你也可以使用
def appendJson(task="Hello World", description=None):
英文:
Fixed it,
Assing a default value to the arguments like this:
def appendJson(task="default value", descripiton="defaultvalue"):
You can also use
def appendJson(task="Hello World", descripiton=None):
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