如何使用最后一个非NULL值填充PostgreSQL列中的NULL值

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英文:

How to fill NULL values in a PostgreSQL column using the last non-NULL value

问题

我有一个具有以下结构的PostgreSQL表:

CREATE TABLE cte1 (
    entity_id INT,
    assignedtogroup INT,
    time BIGINT
);

INSERT INTO cte1 (entity_id, assignedtogroup, time)
VALUES
    (1, 435198, 1687863949740),
    (1, 435198, 1687863949741),
    (1, NULL, 1687863949742),
    (1, NULL, 1687863949743),
    (1, 435224, 1687863949744),
    (1, 435224, 1687863949745),
    (1, 435143, 1687863949746),
    (1, 435143, 1687863949747),
    (1, 435191, 1687863949748),
    (1, NULL, 1687863949749),
    (2, 435143, 1690452125291),
    (2, 435143, 1690452125292),
    (2, 435191, 1690452125293),
    (2, NULL, 1690452125294);

我想使用前一行(当前行之前的时间和相同的entity_id)的非空值来填充assignedtogroup列中的空值。预期结果应为:

entity_id assignedtogroup time
1 435198 1687863949740
1 435198 1687863949741
1 435198 1687863949742
1 435198 1687863949743
1 435224 1687863949744
1 435224 1687863949745
1 435143 1687863949746
1 435143 1687863949747
1 435191 1687863949748
1 435191 1687863949749
2 435143 1690452125291
2 435143 1690452125292
2 435191 1690452125293
2 435191 1690452125294

是否有办法仅使用SELECT语句实现这一点?

我尝试使用LAG函数:

SELECT
    entity_id,
    COALESCE(
        assignedtogroup,
        LAG(assignedtogroup) OVER (PARTITION BY entity_id ORDER BY time)
    ) AS filled_assignedtogroup
FROM cte1;

然而,我仍然有一个NULL值,并且对于entity_id为2的情况,值完全混合。

你可以在DB Fiddle中找到示例:https://www.db-fiddle.com/f/m52Rgq8jtK85g9yvaDMJqz/3

英文:

I have a PostgreSQL table with the following structure:

CREATE TABLE cte1 (
    entity_id INT,
    assignedtogroup INT,
    time BIGINT
);

INSERT INTO cte1 (entity_id, assignedtogroup, time)
VALUES
    (1, 435198, 1687863949740),
    (1, 435198, 1687863949741),
    (1, NULL, 1687863949742),
    (1, NULL, 1687863949743),
    (1, 435224, 1687863949744),
    (1, 435224, 1687863949745),
    (1, 435143, 1687863949746),
    (1, 435143, 1687863949747),
    (1, 435191, 1687863949748),
    (1, NULL, 1687863949749),
    (2, 435143, 1690452125291),
    (2, 435143, 1690452125292),
    (2, 435191, 1690452125293),
    (2, NULL, 1690452125294);

I would like to fill the empty values in the assignedtogroup column using the previous row's (time just before the current row and same entity_id) non-null value. The expected result should be:

entity_id assignedtogroup time
1 435198 1687863949740
1 435198 1687863949741
1 435198 1687863949742
1 435198 1687863949743
1 435224 1687863949744
1 435224 1687863949745
1 435143 1687863949746
1 435143 1687863949747
1 435191 1687863949748
1 435191 1687863949749
2 435143 1690452125291
2 435143 1690452125292
2 435191 1690452125293
2 435191 1690452125294

Is there a way to achieve this using only a SELECT statement?

I tried using the LAG function:

SELECT
    entity_id,
    COALESCE(
        assignedtogroup,
        LAG(assignedtogroup) OVER (PARTITION BY entity_id ORDER BY time)
    ) AS filled_assignedtogroup
FROM cte1;

However, I still have a NULL value and for the entity_id 2, the values are completely mixed.

You can find the DB Fiddle : https://www.db-fiddle.com/f/m52Rgq8jtK85g9yvaDMJqz/3

答案1

得分: 1

你可以在这里使用简单的相关性来改进:

select Entity_Id, Coalesce(assignedtogroup, (
  select assignedtogroup 
	from cte1 cte2 where cte2.entity_id = cte1.entity_id 
	  and cte2.time < cte1.time 
	  and cte2.assignedtogroup is not null 
	  order by time desc
    limit 1
  )), time
from cte1;

更新的DB fiddle链接:https://www.db-fiddle.com/f/m52Rgq8jtK85g9yvaDMJqz/3

英文:

You would be better-off imo using a simple correlation here:

select Entity_Id, Coalesce(assignedtogroup, (
  select assignedtogroup 
	from cte1 cte2 where cte2.entity_id = cte1.entity_id 
	  and cte2.time &lt; cte1.time 
	  and cte2.assignedtogroup is not null 
	  order by time desc
    limit 1
  )), time
from cte1;

Updated DB fiddle https://www.db-fiddle.com/f/m52Rgq8jtK85g9yvaDMJqz/3

答案2

得分: 1

你可以使用MAXCOUNT窗口函数。

查询 #1

WITH CTE AS (
    SELECT *,
           COUNT(CASE WHEN assignedtogroup IS NOT NULL THEN 1 END) OVER(
               PARTITION BY entity_id 
               ORDER     BY time
           ) AS rn
    FROM cte1
)
SELECT entity_id, MAX(assignedtogroup) OVER(PARTITION BY entity_id, rn) AS value_ , time
FROM CTE
ORDER BY 1,3;
entity_id value_ time
1 435198 1687863949740
1 435198 1687863949741
1 435198 1687863949742
1 435198 1687863949743
1 435224 1687863949744
1 435224 1687863949745
1 435143 1687863949746
1 435143 1687863949747
1 435191 1687863949748
1 435191 1687863949749
2 435143 1690452125291
2 435143 1690452125292
2 435191 1690452125293
2 435191 1690452125294

在 DB Fiddle 上查看

英文:

you can use a MAX and COUNT window function

Query #1

WITH CTE AS (
    SELECT *,
           COUNT(CASE WHEN assignedtogroup IS NOT NULL THEN 1 END) OVER(
               PARTITION BY entity_id 
               ORDER     BY time
           ) AS rn
    FROM cte1
)
SELECT entity_id, MAX(assignedtogroup) OVER(PARTITION BY entity_id, rn) AS value_ , time
FROM CTE
ORDER BY 1,3;
entity_id value_ time
1 435198 1687863949740
1 435198 1687863949741
1 435198 1687863949742
1 435198 1687863949743
1 435224 1687863949744
1 435224 1687863949745
1 435143 1687863949746
1 435143 1687863949747
1 435191 1687863949748
1 435191 1687863949749
2 435143 1690452125291
2 435143 1690452125292
2 435191 1690452125293
2 435191 1690452125294

View on DB Fiddle

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  • 本文由 发表于 2023年8月8日 20:18:10
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