在T-SQL(SQL Server)中,我可以在函数内部使用OPTION子句吗?

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英文:

Can I use an OPTION clause inside a function in T-SQL (SQL Server)?

问题

我想编写一个类似于以下的函数:

CREATE OR ALTER FUNCTION TestFunction()
RETURNS TABLE
AS RETURN
WITH NumberList AS (
    SELECT  1 AS Number
    UNION ALL
    SELECT  Number + 1
    FROM    NumberList
    WHERE   Number < 1000
)
SELECT  Number
FROM    NumberList
OPTION (MAXRECURSION 0)

然而,当运行此查询时,SQL Server 返回以下错误:

Msg 156, Level 15, State 1, Procedure TestFunction, Line 13 [Batch Start Line 0]
Incorrect syntax near the keyword 'OPTION'.

如果我从函数中删除行 OPTION (MAXRECURSION 0),它可以正常工作:

CREATE OR ALTER FUNCTION TestFunction()
RETURNS TABLE
AS RETURN
WITH NumberList AS (
    SELECT  1 AS Number
    UNION ALL
    SELECT  Number + 1
    FROM    NumberList
    WHERE   Number < 1000
)
SELECT  Number
FROM    NumberList

但是,当执行此函数时:

SELECT  *
FROM    TestFunction()

然后它返回以下错误:

Msg 530, Level 16, State 1, Line 1
The statement terminated. The maximum recursion 100 has been exhausted before statement completion.

是否可能在函数内部添加子句 OPTION (MAXRECURSION 0)?我认为这对于函数的用户来说很方便,不必在执行函数时记住添加选项子句。

英文:

I want to write a function like this:

CREATE OR ALTER FUNCTION TestFunction()
RETURNS TABLE
AS RETURN
WITH NumberList AS (
    SELECT  1 AS Number
    UNION ALL
    SELECT  Number + 1
    FROM    NumberList
    WHERE   Number < 1000
)
SELECT  Number
FROM    NumberList
OPTION (MAXRECURSION 0)

However, when running this query, SQL Server returns the following error:

Msg 156, Level 15, State 1, Procedure TestFunction, Line 13 [Batch Start Line 0]
Incorrect syntax near the keyword 'OPTION'.

If I remove the row OPTION (MAXRECURSION 0) from the function it works:

CREATE OR ALTER FUNCTION TestFunction()
RETURNS TABLE
AS RETURN
WITH NumberList AS (
    SELECT  1 AS Number
    UNION ALL
    SELECT  Number + 1
    FROM    NumberList
    WHERE   Number < 1000
)
SELECT  Number
FROM    NumberList

But when executing this function:

SELECT  *
FROM    TestFunction()

Then it returns the following error:

Msg 530, Level 16, State 1, Line 1
The statement terminated. The maximum recursion 100 has been exhausted before statement completion.

Is it possible to add the clause OPTION (MAXRECURSION 0) inside the function? I think it would be convenient for the user of the function not having to remember to add the option clause when executing the function.

答案1

得分: 3

使用递归生成数字系列会有相当大的开销,可能是其中最慢的方式之一。

在 SQL Server 2022 之前,生成数字系列的绝对最快方式是使用派生值表的交叉连接。这甚至比从物理表中选择整数更快,也是一种常见的选项。

以下将为您提供确切的 1000 行。如果您想要更少的行,您可以在从中选择时使用 top,或者在调用它时传入一个用于 top 的参数。

create function dbo.GenerateSeries()
returns table
as return
with 
	t1(n) as (select n from(values(0),(0),(0),(0),(0),(0),(0),(0),(0),(0))n(n)), 
	t2(n) as (select 0 from t1 x cross join t1 y),
	t3(n) as (select 0 from t2 x cross join t1 y), 
	t(n) as (select Row_Number() over (order by (select null)) from t3)
select n
from t;
英文:

Using recursion to generate a number series has considerable overhead and is probably one of the slowest possible ways to do it.

The absolute fastest way, prior to SQL Server 2022, to generate a number series would be to use a cross join using a derived table of values. This is faster than even select integers from a physical table, also a common option.

The following will give you exactly 1000 rows. If you wanted fewer rows you could use top when you select from it, or pass in a parameter to use for top when you invoke it.

create function dbo.GenerateSeries()
returns table
as return
with 
	t1(n) as (select n from(values(0),(0),(0),(0),(0),(0),(0),(0),(0),(0))n(n)), 
	t2(n) as (select 0 from t1 x cross join t1 y),
	t3(n) as (select 0 from t2 x cross join t1 y), 
	t(n) as (select Row_Number() over (order by (select null)) from t3)
select n
from t;

答案2

得分: 1

以下是翻译好的部分:

我认为生成从1到1000的更好方法是使用master..spt_values如下:

CREATE OR ALTER FUNCTION TestFunction()
RETURNS TABLE
AS RETURN

WITH NumberList AS (
  SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS Number
  FROM master..spt_values
)
SELECT Number
FROM NumberList
WHERE Number <= 1000;
select * from  TestFunction()
+------------------------------------+
|               Number               |
+------------------------------------+
| 1                                  |
| 2                                  |
| 3                                  |
| ... --4 到 995 被省略以缩短长度 |
| 996                                |
| 997                                |
| 998                                |
| 1000                               |
+------------------------------------+

fiddle

英文:

I think the better approach to generate numbers from 1 to 1000 will be using master..spt_values as below:

CREATE OR ALTER FUNCTION TestFunction()
RETURNS TABLE
AS RETURN
  
WITH NumberList AS (
  SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS Number
  FROM master..spt_values
)
SELECT Number
FROM NumberList
WHERE Number <= 1000;

select * from  TestFunction()

+------------------------------------+
|               Number               |
+------------------------------------+
| 1                                  |
| 2                                  |
| 3                                  |
| ... --4 to 995 omitted for brevity |
| 996                                |
| 997                                |
| 998                                |
| 1000                               |
+------------------------------------+

fiddle

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  • 本文由 发表于 2023年8月5日 14:15:38
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