问题

以下是您要翻译的代码部分：

我是C语言新手，要求我创建一个4D数组来完成一个简单的任务。

我首先创建了一个常规数组，可以根据您提供的项数进行打印。

然后我尝试将其扩展为由两个数组组成，但似乎没有成功。

它给了我这个错误，我该如何创建一个数组内嵌另一个数组？

```c
#include <stdio.h>

int main(){

    int arrayprint;
    int a = 10;
    int b = 20;
    int c = 30;
    int d = 40;
    int* array1[] = {a, b};
    int* array2[] = {c, d};
    int** topArray[] = {array1, array2};
    int i;
    
    printf("要打印的矩阵项数是多少？（最多2项）：\n");
    scanf("%d", &arrayprint);
    printf("\n您选择了%d项。\n", arrayprint);
    
    for (i = 0; i < arrayprint; i++) {
        printf("\n%d", topArray[i]);
    }

}

我之前使用普通数组编写了这段代码，它运行得很好。

但现在它似乎不喜欢它的当前状态，它给了我错误，但也能够打印出看起来像内存值的内容？

<details>
<summary>英文:</summary>

I&#39;m new to C, and for a simple task I was asked to make a 4d array.

I started by making a regular array, which would print the amount of items you tell it to.

I tried to then expand it to be composed of 2 arrays, which I haven&#39;t gotten to work.

It gives me this error, what can I do to make an array within an array?

#include <stdio.h>

int main(){

int arrayprint;
int a = 10;
int b = 20;
int c = 30;
int d = 40;
int* array1[] = {a, b};
int* array2[] = {c, d};
int** topArray[] = {array1, array2};
int i;

printf("Amount of matrix items to print? (Maximum 2):\n");
scanf("%d", &arrayprint);
printf("\nYou chose %d items.", arrayprint);

for (i = 0; i < arrayprint; i++) {
printf("\n%d", topArray[i]);
}

}

I had this code before with just a regular array, and it worked great.

But it doesn't seem to like how it is now, it gives me errors, but also works and prints what looks like memory values?

</details>


# 答案1
**得分**: 1

当声明数组时，你不使用指针，只使用指针引用整个数组。

```c
int nums[2][2] = {{1, 2}, {1, 2}};

基本上，从任何地方减去一个 * 符号。以下是一个可以复制粘贴的版本（假设两个数组具有相同的宽度）：

#include <stdio.h>

int main() {

  int arrayprint;
  int a = 10;
  int b = 20;
  int c = 30;
  int d = 40;
  int array1[] = {a, b};
  int array2[] = {c, d};
  int* topArray[] = {array1, array2};

  printf("要打印的矩阵项数是多少？（最多 2 项）：\n");
  scanf("%d", &arrayprint);
  printf("\n你选择了 %d 项。\n");

  for (int i = 0; i < arrayprint; i++) {
    for (int j = 0; j < arrayprint; j++) {
      printf("\n%d", topArray[i][j]);
      // 处理方形多维数组时，i 和 j 的顺序不重要。
    }
  }
}

另外，最佳实践是使用 #include <stdio.h> 而不是 #include \<stdio.h\>。

希望这有所帮助！

int nums[2][2] = {{1, 2}, {1,2};

#include <stdio.h>

int main(){

  int arrayprint;
  int a = 10;
  int b = 20;
  int c = 30;
  int d = 40;
  int array1[] = {a, b};
  int array2[] = {c, d};
  int* topArray[] = {array1, array2};

  printf("Amount of matrix items to print? (Maximum 2):\n");
  scanf("%d", &arrayprint);
  printf("\nYou chose %d items.", arrayprint);
  
  for (int i = 0; i < arrayprint; i++) {
    for (int j = 0; j < arrayprint; j++) {
      printf("\n%d", topArray[i][j]);
      //when dealing with square multidimensional arrays, the order of i and j don't matter.
    }
  }
}