如何从同一张表中选择和更新父子记录?

huangapple go评论75阅读模式
英文:

postgresql How to SELECT and UPDATE parent and child records from the same table?

问题

你好,我理解你的问题。你遇到的问题似乎是在更新所有具有子记录的父记录时,更新操作未能按预期进行。这里有一些可能导致此问题的原因:

  1. 数据完整性问题:首先,请确保你的数据表中没有任何外键或约束,它们可能会妨碍更新操作。如果有外键关系,你需要考虑解除它们,然后再次尝试更新。

  2. 索引问题:检查数据库表是否有适当的索引。确保parent_load_record_id列和id列都有索引,这将提高查询性能。如果没有索引,更新操作可能会变得非常慢。

  3. 事务问题:如果你的数据库在一个事务中执行这些更新操作,确保事务正确提交。如果没有正确提交,更新操作将不会生效。

  4. 缓存问题:有时数据库系统可能会缓存查询结果,这可能导致在数据库中进行的更改不会立即反映在查询中。你可以尝试刷新数据库缓存或等待一段时间,然后再次运行查询。

如果在检查了上述问题后,问题仍然存在,你可以考虑使用数据库日志来跟踪更新操作,以便更好地理解问题发生的原因。此外,确保数据库系统本身没有任何限制,可能会限制大规模更新操作的执行。

最后,确保你在执行更新操作之前备份了数据,以防发生意外情况。如果问题仍然存在,并且你需要更具体的帮助,建议咨询你的数据库管理员或数据库开发人员以获取进一步的支持。

英文:

Hello I have the following records parents and children, you can tell by the parent_load_record_id column.

The thing is I need those records who have children and their children to have false in the is_unique field, since they are not unique anymore.

The parents who have no children have to stay as is_unique = true

id document_number document_status is_unique parent_load_record_id
276983 49515 INFORMED true
1060396 251013 INFORMED true
177836 0000221 INFORMED true
207775 0000221 APPROVED true 177836
19342 0000221 RESULTANT true 177836
19721 000456 INFORMED true
19786 000456 EDITED true 19721

The problem I'm having is. I'm trying to get all the parents with this query and I always get zero results (this query I use to check if my update actually worked)

SELECT 
l.id,
l.document_number,
l.document_status,
l.is_unique,
l.parent_load_record_id
FROM load_record l
WHERE l.parent_load_record_id IS NULL
AND l.id NOT IN(SELECT DISTINCT lr.parent_load_record_id FROM load_record lr);

I use this query to update all children

UPDATE load_record SET is_unique = false WHERE parent_load_record_id IS NOT NULL

The problem comes when I have to UPDATE all parents with children

UPDATE load_record SET 
is_unique = false 
WHERE parent_load_record_id IS NULL 
AND id IN(SELECT DISTINCT lr.parent_load_record_id FROM load_record lr)

The Update is not really doing what it needs to do, just like the SELECT is there a reason for it? or is there a better way to do it?

答案1

得分: 0

以下是翻译好的部分:

问题在于SELECT DISTINCT lr.parent_load_record_id FROM load_record lr返回了一个NULL行,导致id NOT IN (…)也返回了NULL示例)。您可以进行过滤:

... AND l.id NOT IN (SELECT DISTINCT lr.parent_load_record_id FROM load_record lr WHERE lr.parent_load_record_id IS NOT NULL);

或者只是使用WHERE NOT EXISTS子句:

... AND NOT EXISTS (
  SELECT *
  FROM load_record lr
  WHERE lr.parent_load_record_id = l.id
)

更新示例

英文:

The problem is that SELECT DISTINCT lr.parent_load_record_id FROM load_record lr returns a NULL row, which leads to id NOT IN (…) returning NULL as well (demo). You can either filter them:

… AND l.id NOT IN (SELECT DISTINCT lr.parent_load_record_id FROM load_record lr WHERE lr.parent_load_record_id IS NOT NULL);

<sup>(updated demo)</sup>

or just use a WHERE NOT EXISTS clause:

… AND NOT EXISTS (
  SELECT *
  FROM load_record lr
  WHERE lr.parent_load_record_id = l.id
)

<sup>(updated demo)</sup>

huangapple
  • 本文由 发表于 2023年8月4日 21:38:59
  • 转载请务必保留本文链接:https://go.coder-hub.com/76836478.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定