如何在编译到JAR文件和不编译到JAR文件时以相同的方式指定资源位置。

huangapple go评论69阅读模式
英文:

How to specify resource location in the same way when compiling TO and NOT TO a JAR file

问题

我有一个正在使用 javac 编译的项目。我希望能够在不首先将我的项目构建为 JAR 文件的情况下获取资源,但与此同时,我也不想硬编码资源的位置(C://Users/name/etc)。

我知道如果我有一个 JAR 文件,我可以使用 ClassLoader 并从中调用其中的一个资源方法。或者,如果我的资源包含在另一个 JAR 文件中,并且该 JAR 文件位于我的类路径上,那么我可以以类似的格式从该 JAR 文件中提取它。

但是当我只使用 javac 编译时,我该如何做呢?我不想在最终将其制作成 JAR 文件时不得不重新调整所有我的资源获取逻辑,但我也不想每次编译并想要测试更改时都必须制作一个 JAR 文件。我只想能够告诉 Java 这是在哪里找到我的资源,而当我最终决定制作一个 JAR 文件时,我不想改变这个策略。

英文:

I have a project that I am compiling using javac. I want to be able to fetch resources without having to first build my project into a JAR file, but at the same time, I don't want to hard code the location either (C://Users/name/etc).

I know that if I had a JAR file, I could use a ClassLoader and call one of the resource methods from there. Alternatively, if my resources were contained within another JAR file, and that JAR file was on my class path, then I could fetch it from the JAR file in a similar format.

But how do I do so when I am only compiling in javac? I don't want to have to rework all of my resource fetching logic when I eventually turn this into a JAR file, but I also don't want to have to make a jar file every time I compile and want to test a change. I just want to be able to specify to Java that this is where to find my resources, and I don't want to change that strategy when I finally decide to making a JAR file.

答案1

得分: 1

你可以像在jar文件中一样在文件夹中找到资源。只需确保在运行java时通过 -cp 列出包含资源的文件夹,并且你的代码中的相对路径与之对应。

以下是一个示例。

java -cp ".;first/path/to/resource/folder;second/path;third/path" PackageName.NameOfClassContainingMainMethod

也就是说,资源可能位于与编译后的代码相同的文件夹中。在这种情况下,无需通过 -cp 显式提供它。

无论何时在你的代码中使用 ClassLoader.getResource / getResourceAsStream 加载资源,Java都会在类路径中查找它。提供 .jar(本质上只是一个压缩的文件夹)和原始文件夹只是指定要加载到类路径中的内容的替代方式。

英文:

You can locate resources in the folder same way as in a jar. Just make sure your folder with resources is listed via -cp when running java and relative paths in your code corresponds to it.

Here is an example.

java -cp ".;first/path/to/resource/folder;second/path;third/path" PackageName.NameOfClassContainingMainMethod

That said, the resource might be inside of the same folder that your compiled code is in. In that case, there is no need to provide it explicitly via -cp.

Whenever you are loading a resource in your code by ClassLoader.getResource / getResourceAsStream java looks for it in the classpath. Providing .jar (which is essentially just a zipped folder) and raw folder is just an alternative ways to specify a content to be loaded into classpath.

huangapple
  • 本文由 发表于 2023年8月4日 01:29:09
  • 转载请务必保留本文链接:https://go.coder-hub.com/76830357.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定