问题

I have a script which calls make like this (simplified)

#!/bin/bash

if [[ -f one.source ]]
then
    make one CPPFLAGS='-DONE -DTWO -DTHREE'
fi

if [[ -f two.source ]]
then
    make two CPPFLAGS='-DONE -DTWO -DTHREE'
fi

The list of defines is getting long, and I'd like to avoid having to keep the two command lines in sync. I'd like to define a variable and use it in both commands. I tried

DEFINES='-DONE -DTWO -DTHREE'

DD="CPPFLAGS='"
DD+=$DEFINES
DD+="'"

With this,

echo $DD
CPPFLAGS='-DONE -DTWO -DTHREE'

seems to do what I want, but

make one $DD

fails with

make one 'CPPFLAGS='\''-DONE -DTWO -DTHREE'\'''
make: invalid option -- 'D'
make: invalid option -- 'T'
make: invalid option -- 'D'
make: invalid option -- 'T'
make: invalid option -- 'H'
Usage: make [options] [target] ...

<details>
<summary>英文:</summary>

I have a script which calls make like this (simplified)

#!/bin/bash

if [[ -f one.source ]]
then
make one CPPFLAGS='-DONE -DTWO -DTHREE'
fi

if [[ -f two.source ]]
then
make two CPPFLAGS='-DONE -DTWO -DTHREE'
fi

The list of defines is getting long, and I'd like to avoid having to keep the two command lines in sync. I'd like to define a variable and use it in both commands. I tried

DEFINES='-DONE -DTWO -DTHREE'

DD="CPPFLAGS='"
DD+=$DEFINES
DD+="'"

With this,

echo $DD
CPPFLAGS='-DONE -DTWO -DTHREE'

seems to do what I want, but

make one $DD

fails with

make one 'CPPFLAGS='''-DONE' -DTWO '-DTHREE''''
make: invalid option -- 'D'
make: invalid option -- 'T'
make: invalid option -- 'D'
make: invalid option -- 'T'
make: invalid option -- 'H'
Usage: make [options] [target] ...

答案1

得分: 2

不要引用自己。使用 printf "%q" 或 @Q 扩展。

使用 bash 数组。

defines=(
   -DONE
   -DTWO
   -DTHREE
)
make_args=(
   "CPPFLAGS=${defines[*]@Q}"
)
make one "${make_args[@]}"

但是

$DD 没有被引用，因此它会进行单词分割扩展，将其分割成空格。

使用 shellcheck 检查你的脚本。

Make 是一个老掌门。考虑使用更新的构建系统，如 CMake。

defines=(
   -DONE
   -DTWO
   -DTHREE
)
make_args=(
   "CPPFLAGS=${defines[*]@Q}"
)
make one "${make_args[@]}"