我的变量在一个for循环中重置,不确定为什么。

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英文:

my variable resetting after one loop in a for loop, not sure why

问题

我一直在尝试创建一个for循环,其中i < j。变量J获取字符串的长度,以决定将发生多少次循环。这对于第一个循环有效,我已经进行了调试,如果我输入一个包含3个字符的字符串,J确实会获取值3。问题在于,在第一个循环之后,J被重置为0,我似乎无法弄清楚为什么会这样。有人可以帮助我吗?我仍然认为自己是一个初学者,所以关于代码的任何建议都会受到欢迎,即使不是关于我的具体问题。

#include <ctype.h>
#include <cs50.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(void)
{
    string prompt = get_string("给我一个单词: ");
    int j = strlen(prompt);
    char word[] = "";

    for (int i = 0; i < j; i++)
    {
        strcat(word, "p");
    }

    printf("%s\n", word);
}
英文:

i have been trying to make a for loop where at i &lt; j. Variable J takes the length of a string to decide how many loops will happen. This works for the first loop, i have debugged and J does get the value of 3 if i put in a string of 3 characters. The problem is that after the first loop J is reset to the value of 0 and i cant seem to figure out why that is. Can anyone help me? Id still call myself a beginner so any advice on code would be appreciated even if its not about my specific question.

#include &lt;ctype.h&gt;
#include &lt;cs50.h&gt;
#include &lt;stdio.h&gt;
#include &lt;string.h&gt;
#include &lt;stdlib.h&gt;

int main(void)
{
string prompt = get_string(&quot;Give me a word: &quot; );
int j = strlen(prompt);
char word[] = &quot;&quot;;

    for (int i = 0; i &lt; j; i++)
    {
        strcat(word, &quot;p&quot;);
    }
    
    printf(&quot;%s\n&quot;, word);

}

答案1

得分: 3

char word[] = &quot;&quot;; // 这里我认为是拼写错误,应该是

char word[] = &quot;&quot;;

You define a `char` array having one element (null terminating character).
When you `strcat(word, &quot;p&quot;);` you invoke **undefined behaviour** as you write outside the array bounds. Your array has to be big enough to accommodate all the characters and null terminating character.

int main(void)
{
string prompt = get_string("Give me a word: " );
size_t j = strlen(prompt);
char word[j + 1];

word[0] = &#39;
word[0] = &#39;\0&#39;;
for (int i = 0; j != 0 &amp;&amp; i &lt; j; i++)
{
strcat(word, &quot;p&quot;);
}
printf(&quot;%s\n&quot;, word);
&#39;; for (int i = 0; j != 0 &amp;&amp; i &lt; j; i++) { strcat(word, &quot;p&quot;); } printf(&quot;%s\n&quot;, word);

}

https://godbolt.org/z/5GPPse96K
英文:

char word\[\] = &quot;&quot;; I belive that it is typo and it should be

char word[] = &quot;&quot;;

You define a char array having one element (null terminating character).
When you strcat(word, &quot;p&quot;); you invoke undefined behaviour as you write outside the array bounds. Your array has to be big enough to accommodate all the characters and null terminating character.

int main(void)
{
    string prompt = get_string(&quot;Give me a word: &quot; );
    size_t j = strlen(prompt);
    char word[j + 1];

    word[0] = &#39;
int main(void)
{
string prompt = get_string(&quot;Give me a word: &quot; );
size_t j = strlen(prompt);
char word[j + 1];
word[0] = &#39;\0&#39;;
for (int i = 0; j != 0 &amp;&amp; i &lt; j; i++)
{
strcat(word, &quot;p&quot;);
}
printf(&quot;%s\n&quot;, word);
}
&#39;; for (int i = 0; j != 0 &amp;&amp; i &lt; j; i++) { strcat(word, &quot;p&quot;); } printf(&quot;%s\n&quot;, word); }

https://godbolt.org/z/5GPPse96K

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  • 本文由 发表于 2023年7月31日 20:21:23
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