从Android Studio中的电话联系人列表中选择以特定字母开头的联系人。

huangapple go评论55阅读模式
英文:

Pick Contacts starting from a specific alphabet from phone contact list in android studio

问题

根据标题所述,我想从手机联系人中选择以给定字母开头的联系人列表。
例如:如果我只想选择以字母"A"开头的联系人,我尝试的当前代码如下:

val selecteContactsList: ArrayList<SelectedContactItem> = arrayListOf()
val cursor = context.contentResolver.query(
        ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
        arrayOf(
            ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
            ContactsContract.CommonDataKinds.Phone.NUMBER
        ),
        ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " LIKE ?",
        arrayOf("A%"),
        ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
    )

while (cursor!!.moveToNext()) {
    val contactName =
        cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME))
    val contactNumber =
        cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))
    val contactItem = SelectedContactItem(contactNumber, contactName)
    selecteContactsList.add(contactItem)
}
cursor.close()

但是这不会产生任何输出。总选择的联系人计数为0。
如有帮助,将不胜感激。提前谢谢。

英文:

As the title says, I want to select contacts list from the phone contacts which start from the given alphabet.
for example: if i want to select only the contacts starting with A, my current code which i tried is:

val selecteContactsList: ArrayList&lt;SelectedContactItem&gt; = arrayListOf()
val cursor = context.contentResolver.query(
        ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
        arrayOf(
            ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
            ContactsContract.CommonDataKinds.Phone.NUMBER
        ),
        ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + &quot; = ?&quot;,
        arrayOf(&quot;A&quot;),
        ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME
    )

    while (cursor!!.moveToNext()) {
        val contactName =
            cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME))
        val contactNumber =
            cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))
        val contactItem = SelectedContactItem(contactNumber, contactName)
        selecteContactsList.add(contactItem)
    }
    cursor.close()

But this does not give any output. total selected contacts count is 0.
Any help would be appreciated. Thanks in advance.

答案1

得分: 1

Phone.DISPLAY_NAME + " = ?",
arrayOf("A"),

意味着 '返回所有姓名为A的联系人'。我认为你想要询问 '返回所有姓名以字母A开头的联系人',这是一个不同的查询。

要实现这个目标,你可以将代码更改为:

Phone.DISPLAY_NAME + " LIKE 'A%'"

如果你想要不区分大小写的查询(即包括以小写字母'a'开头的姓名),可以尝试:

Phone.DISPLAY_NAME + " LIKE 'A%' COLLATE NOCASE"

但是,如果你的目标是显示所有联系人的列表,并且有一个滚动侧边栏,用户可以触摸字母"C"并跳转到以该字母开头的联系人姓名,我不建议使用这样的查询,而是应该查询设备上的所有联系人,并将它们全部显示在一个可滚动的大列表中,然后当用户触摸字母按钮时,滚动到列表中的某个位置。

这样的用户体验会更出色。


<details>
<summary>英文:</summary>

the part:

Phone.DISPLAY_NAME + " = ?",
arrayOf("A"),

means &#39;return all contacts with name A&#39;. 

I think you want to ask &#39;return all contacts with name starting with the letter A&#39; which is a different query.

To do that you can change the code to:

Phone.DISPLAY_NAME + " LIKE 'A%'"


If you want a case insensitive query (i.e. include names that begin with small &#39;a&#39;), try:

Phone.DISPLAY_NAME + " LIKE 'A%' COLLATE NOCASE"


However, if your goal is to show a list of all contacts, and have a scroller sidebar where the user can touch the letter &quot;C&quot; and jump to contact names beginning with that letter I would not suggest to have such queries, instead query for **all** contacts on the device, and show them all in one big scrollable list, and have those letters buttons scroll to a certain position in the list when touched.

The user experience would be far superior.


</details>



huangapple
  • 本文由 发表于 2023年7月31日 19:24:34
  • 转载请务必保留本文链接:https://go.coder-hub.com/76803148.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定