英文:
Js puppteer page goto does not go to next link
问题
如果使用 browser.pages()[0] 访问 Puppeteer 浏览器页面对象，连续访问多个 URL 时，使用 goto 方法会失败。
但是，如果使用 browser.newPage() 来创建第二个但是活跃的页面，那么连续访问多个 URL 就可以正常工作。
上述代码片段中的第一个示例是有效的，而第二个示例会导致 TypeError 错误。
希望这有所帮助！
英文:
If puppeteer browser page object is accessed with browser.pages()[0], going to multiple urls consecutively fail with goto method.
Where if puppeteer browser page object is accessed with browser.newPage() which will now create a second but active page, going to multiple urls consecutively works.
const puppeteer = require('puppeteer-core');
(async () => {
const browser = await puppeteer.launch({
executablePath: 'C:\\Program Files\\Google\\Chrome\\Application\\chrome.exe',
headless: false
})
const page = await browser.newPage()
const urls = ['https://www.google.com/', 'https://www.yahoo.com/']
for (let i = 0; i < urls.length; i++) {
const url = urls[i];
await page.goto(`${url}`)
}
await browser.close()
})()
Above works
const puppeteer = require('puppeteer-core');
(async () => {
const browser = await puppeteer.launch({
executablePath: 'C:\\Program Files\\Google\\Chrome\\Application\\chrome.exe',
headless: false
})
const page = await browser.pages()[0]
const urls = ['https://www.google.com/', 'https://www.yahoo.com/']
for (let i = 0; i < urls.length; i++) {
const url = urls[i];
await page.goto(`${url}`)
}
await browser.close()
})()
TypeError: Cannot read properties of undefined (reading 'goto')
Any help will be appreciated!
答案1
得分: 0
你遇到这个错误是因为你试图从处于挂起状态的Promise<Page[]>中获取索引为0的页面。
要解决这个问题，你应该在Promise被解析后按索引获取页面，比如：
const page = (await browser.pages())[0];
或者
const [page] = await browser.pages();
或者
const page = await browser.pages().then(p => p[0]);
英文:
You got this error, because you are trying to get page with index 0 from Promise<Page[]> in pending status.
To solve this issue, you should get page by index, when Promise is resolved, like
const page = (await browser.pages())[0];
or
const [page] = await browser.pages();
or
const page = await browser.pages().then(p => p[0]);
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