英文:
Define one prop as optional if another one is of specific enum type
问题
组件属性类型：
interface IRequireUserPermits {
minimalRequiredRole: UserRoles;
allowedPermissions?: UserPermissions[];
}
UserRoles 是一个枚举类型：
export enum UserRoles {
SUPERADMIN = "SUPERADMIN",
ADMIN = "ADMIN",
AGENT = "AGENT",
}
如何定义 allowedPermissions 属性仅在 minimalRequiredRole 属性为 UserRoles.AGENT 时为必需？或者反过来，如何使属性可选，仅当 minimalRequiredRole 属性为 UserRoles.SUPERADMIN 或 UserRoles.ADMIN 时？
谢谢。
英文:
Component prop type:
interface IRequireUserPermits {
minimalRequiredRole: UserRoles;
allowedPermissions: UserPermissions[];
}
UserRoles is an enum:
export enum UserRoles {
SUPERADMIN = "SUPERADMIN",
ADMIN = "ADMIN",
AGENT = "AGENT",
}
How can I define allowedPermissions prop required only if the minimalRequiredRole prop is UserRoles.AGENT? Or the other way around - how to make prop optional only if the minimalRequiredRole prop is either UserRoles.SUPERADMIN or UserRoles.ADMIN?
Thanks
答案1
得分: 1
你正在寻找区分联合类型。我们可以使用type而不是interface来定义IRequireUserPermits：
type IRequireUserPermits =
| {
minimalRequiredRole: UserRoles.AGENT;
allowedPermissions: UserPermissions[];
}
| {
minimalRequiredRole: UserRoles.SUPERADMIN | UserRoles.ADMIN;
};
测试代码如下：
const case1: IRequireUserPermits = {
minimalRequiredRole: UserRoles.AGENT,
allowedPermissions: [], // 没有错误
};
const case2: IRequireUserPermits = {
minimalRequiredRole: UserRoles.ADMIN,
allowedPermissions: [], // 报错
};
英文:
You are looking for discriminated unions. Instead of interface let's use type for IRequireUserPermits:
type IRequireUserPermits =
| {
minimalRequiredRole: UserRoles.AGENT;
allowedPermissions: UserPermissions[];
}
| {
minimalRequiredRole: UserRoles.SUPERADMIN | UserRoles.ADMIN;
};
Testing:
const case1: IRequireUserPermits = {
minimalRequiredRole: UserRoles.AGENT,
allowedPermissions: [], // no error
};
const case2: IRequireUserPermits = {
minimalRequiredRole: UserRoles.ADMIN,
allowedPermissions: [], // error
};
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