Why is my second variable (x2,y2) not defined while my first variable (x1,y1) is?

huangapple
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英文:

Why is my second variable (x2,y2) not defined while my first variable (x1,y1) is?

问题

  1. class Line():
  2.     
  3.     def __init__(self, coor1 , coor2):
  4.         
  5.         self.coor1 = coor1 
  6.         self.coor2 = coor2 
  7.       
  8.     
  9.     def distance(self):
  10.         
  11.         for (x1, y1), (x2, y2) in zip(self.coor1, self.coor2):
  12.                 
  13.                 distance = ((x2-x1)**2 + (y2-y1)**2)**0.5
  14.         
  15.         return distance
  17. coordinate1 = (3,2)
  18. coordinate2 = (8,10)
  20. li = Line(coordinate1,coordinate2)
  22. li.distance()

嗨，我不太确定为什么第一个变量(x1,y1)能够被定义，而第二个变量(x2,y2)不能。我不太确定如何在for循环中包含两个元组，但是应该是两个都被定义或者两个都未定义的。谢谢！

英文: 
  1. class Line():
  2.     
  3.     def __init__(self, coor1 , coor2):
  4.         
  5.         self.coor1 = coor1 
  6.         self.coor2 = coor2 
  7.       
  8.     
  9.     def distance(self):
  10.         
  11.         for x1,y1 in self.coor1, x2,y2 in self.coor2:
  12.                 
  13.                 distance = ((x2-x1)**2 + (y2-y1)**2)**0.5
  14.         
  15.         return distance
  1. coordinate1 = (3,2)
  2. coordinate2 = (8,10)
  4. li = Line(coordinate1,coordinate2)
  6. li.distance()

Hi, I am not too sure why (x2,y2) wasn't able to be defined while the first variable (x1,y1) was. I am not too sure how to include both tuples in the for loop, but shouldn't both be defined or none of them are defined? Thanks!

答案1

得分: 3

你没有正确使用for循环。你不需要使用循环一次性分配多个值。只需这样做：

  1. class Line():
  2.     
  3.     def __init__(self, coor1 , coor2):
  4.         self.coor1 = coor1 
  5.         self.coor2 = coor2 
  6.     
  7.     def distance(self):
  8.         x1,y1 = self.coor1 
  9.         x2,y2 = self.coor2
  10.         distance = ((x2-x1)**2 + (y2-y1)**2)**0.5
  11.         return distance
  14. coordinate1 = (3,2)
  15. coordinate2 = (8,10)
  17. li = Line(coordinate1,coordinate2)
  19. print(li.distance())

由于元组包含两个值，它们将被分配给用逗号分隔的两个变量：

  1. x,y = (1,2)

等同于：

  1. x = 1
  2. y = 2

或者你可以直接使用以下代码：

  1. return sum([(i[0] - i[1])**2 for i in zip(self.coor1, self.coor2)])**0.5

这适用于n维向量。

英文:

You are not using the for loop correctly. You don't need a loop to assign multiple values at once. Just do:

  1. class Line():
  2.     
  3.     def __init__(self, coor1 , coor2):
  4.         self.coor1 = coor1 
  5.         self.coor2 = coor2 
  6.     
  7.     def distance(self):
  8.         x1,y1 = self.coor1 
  9.         x2,y2 = self.coor2
  10.         distance = ((x2-x1)**2 + (y2-y1)**2)**0.5
  11.         return distance
  13.     
  14. coordinate1 = (3,2)
  15. coordinate2 = (8,10)
  17. li = Line(coordinate1,coordinate2)
  19. print(li.distance())

Since the tuples contain two values, they will be assigned to the 2 variables separated by the comma:

  1. x,y = (1,2)

is same as

  1. x = 1
  2. y = 2

Or you could just:

  1. return sum([(i[0] - i[1])**2 for i in zip(self.coor1, self.coor2)])**0.5

And that would work with n-dimensional vectors.

huangapple
  • 本文由 发表于 2023年7月27日 16:32:26
  • 转载请务必保留本文链接：https://go.coder-hub.com/76777892.html
  • iterable-unpacking
  • oop
  • python
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