英文:
Repeat a matrix in Matlab
问题
如果A是一个4x3的矩阵：
A =
0.5991 0.2336 0.03230.3799 0.8422 0.55690.8399 0.2050 0.62130.1740 0.2895 0.0185
如何重复每一行n次，使得A成为一个3D矩阵，即第三个维度为4，如下所示：
A_new =
A(:,:,1) =
0.5991 0.2336 0.0323
0.5991 0.2336 0.0323
A(:,:,2) =
0.3799 0.8422 0.5569
0.3799 0.8422 0.5569
A(:,:,3) =
0.8399 0.2050 0.6213
0.8399 0.2050 0.6213
A(:,:,4) =
0.1740 0.2895 0.0185
0.1740 0.2895 0.0185
期望得到一个3D矩阵。
英文:
IF A is 4*3 matrix:
A =
0.5991 0.2336 0.03230.3799 0.8422 0.55690.8399 0.2050 0.62130.1740 0.2895 0.0185
How to repeat each row n time such that A to be a 3D matrix i.e, the third dimension is 4 as it is to be like this
A_new =
A(:,:,1) =
0.5991 0.2336 0.0323
0.5991 0.2336 0.0323
A(:,:,2) =
0.3799 0.8422 0.5569
0.3799 0.8422 0.5569
A(:,:,3) =
0.8399 0.2050 0.6213
0.8399 0.2050 0.6213
A(:,:,4) =
0.1740 0.2895 0.0185
0.1740 0.2895 0.0185
expecting a 3d matrix
答案1
得分: 3
你可以将A重塑为一个1*3*4的矩阵，然后根据需要重复多行，例如你的例子中是两行。
需要注意的是，MATLAB是列优先的，所以在重塑之前需要进行转置（.'）以获得正确的元素顺序。
A = [0.5991 0.2336 0.03230.3799 0.8422 0.55690.8399 0.2050 0.62130.1740 0.2895 0.0185];A = reshape(A.',1,size(A,2),[]); % 将其“展平”为1*3*4n = 2; % 行重复的次数A = repmat( A, n, 1, 1 ); % 复制为n*3*4
输出结果：
>> AA(:,:,1) =0.5991 0.2336 0.03230.5991 0.2336 0.0323A(:,:,2) =0.3799 0.8422 0.55690.3799 0.8422 0.5569A(:,:,3) =0.8399 0.2050 0.62130.8399 0.2050 0.6213A(:,:,4) =0.1740 0.2895 0.01850.1740 0.2895 0.0185
英文:
You can reshape A to be a 1*3*4 matrix, then simply repeat for as many rows as you want - two in your example.
Be wary because MATLAB is column-major, you have to do a transpose (.') before the reshape to get the correct element ordering.
A = [0.5991 0.2336 0.03230.3799 0.8422 0.55690.8399 0.2050 0.62130.1740 0.2895 0.0185];A = reshape(A.',1,size(A,2),[]); % "flatten" into 1*3*4n = 2; % number of row repeatsA = repmat( A, n, 1, 1 ); % replicate into n*3*4
Output:
>> AA(:,:,1) =0.5991 0.2336 0.03230.5991 0.2336 0.0323A(:,:,2) =0.3799 0.8422 0.55690.3799 0.8422 0.5569A(:,:,3) =0.8399 0.2050 0.62130.8399 0.2050 0.6213A(:,:,4) =0.1740 0.2895 0.01850.1740 0.2895 0.0185
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