GoLang:内部结构的泛型和动态类型

huangapple go评论105阅读模式
英文:

GoLang: Generic In Inner Struct and Dynamic Type

问题

我想创建一个子结构体,使用泛型类型作为变量,根据情况可以是两种类型之一。我有以下解决方案:

type Resource interface {
    Phone | Computer
}

type MetricData[R Resource] struct {
    ResourceName string      `json:"resourceName"`
    Metrics      []Metric[R] `json:"metrics"`
}

type Metric[R Resource] struct {
    Resource    R   `json:"resource"`
    Occurrences int `json:"occurrences"`
    Change      int `json:"change"`
}

然而,我在运行时不知道Resource的类型。当我创建一个新的结构体实例时,我需要提供R的类型:

model.MetricData[model.Phone]{ResourceName: resource, Metrics: tm}

有没有办法在运行时给MetricData指定类型,并通过if/else语句根据某些条件确定类型?

英文:

I want to make a child struct use a generic type as variable can be one of two types depending on the situation. I have the following solution

type Resource interface {
	Phone | Computer
}

type MetricData[R Resource] struct {
	ResourceName string      `json:"resourceName"`
	Metrics      []Metric[R] `json:"metrics"`
}

type Metric[R Resource] struct {
	Resource    R   `json:"resource"`
	Occurrences int `json:"occurrences"`
	Change      int `json:"change"`
}

However, I won't know the type of Resource at runtime. When I create a new struct instance I need to provide the type of R

model.MetricData[model.Phone]{ResourceName: resource, Metrics: tm}

Is there a way to give MetricData the type at runtime and determine it via if/else statement depending on some condition?

答案1

得分: 2

也许这会有所帮助(playground):

func resourceType[T Resource](r T) string {
    switch any(r).(type) {
    case Phone:
        return "phone"
    case Computer:
        return "computer"
    default:
        return ""
    }
}
英文:

May be this will help (playground):

func resourceType[T Resource](r T) string {
	switch any(r).(type) {
	case Phone:
		return "phone"
	case Computer:
		return "computer"
	default:
		return ""
	}
}

答案2

得分: 0

你可以像这样修改你的结构:

type Resource interface {}

type MetricData struct {
    ResourceName string      `json:"resourceName"`
    Metrics      []Metric    `json:"metrics"`
}

type Metric struct {
    Resource    Resource   `json:"resource"`
    Occurrences int        `json:"occurrences"`
    Change      int        `json:"change"`
}

现在,要知道Resource的确切类型,你可以这样做:

dummyMetric := {Resource: models.Phone{}, Occurrence: 1, Change: 1}
resourceType := ""

switch dummyMetric.Resource.(type) {
case models.Phone:
    resourceType = "phone"
case models.Computer:
    resourceType = "computer"
}

希望对你有所帮助!

英文:

You can modify your structures like this:

type Resource interface {}

type MetricData struct {
    ResourceName string      `json:"resourceName"`
    Metrics      []Metric    `json:"metrics"`
}

type Metric struct {
    Resource    Resource   `json:"resource"`
    Occurrences int        `json:"occurrences"`
    Change      int        `json:"change"`
}

Now, to know the exact type of Resource, you can do something like this:

dummyMetric := {Resource: models.Phone{}, Occurrence: 1, Change: 1}
resourceType := ""

switch dummyMetric.Resource.(type) {
case models.Phone:
    resourceType = "phone"
case models.Computer:
    resourceType = "computer"
}

Hope it helps!

huangapple
  • 本文由 发表于 2023年7月25日 07:54:38
  • 转载请务必保留本文链接:https://go.coder-hub.com/76758667.html
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