英文:
Missing 3 required positional argument with sys.argv[]
问题
我有一个关于我从Jenkins流水线中调用的Python脚本的问题。
在主脚本中，我有以下内容：
import sys
authentication = sys.argv[1]
style = sys.argv[2]
ip = sys.argv[3]
accounting = sys.argv[4]
PrintTestCases([str(authentication), str(style), str(ip), str(accounting)])
函数PrintTestCases在另一个文件中，并使用匹配-情况结构：
def PrintTestCases(authentication, style, ip, accounting):
match accounting:
case "NOACC":
match [authentication, style, ip]:
case ['NONE', 'NONE', 'NONE']:
print("测试用例编号1")
case _:
print("错误的测试用例")
case "ACC":
match [authentication, style, ip]:
case ['PRIVATE', 'NONE', 'NONE']:
print("测试用例编号2")
case _:
print("错误的测试用例")
然后我从Jenkins流水线中这样调用主脚本：
python3 -u main NONE NONE NONE ACC
但我总是得到这个错误：
PrintTestCases()缺少3个必需的位置参数：'style'、'ip'和'accounting'
根据我的理解，我是通过sys.argv将参数传递给函数的。为什么函数看不到所需的参数？
英文:
I have a problem with a python script I call from a Jenkins pipeline.
In the main script I have this:
import sys
authentication = sys.argv[1]
style = sys.argv[2]
ip = sys.argv[3]
accounting = sys.argv[4]
PrintTestCases([str(authentication), str(style), str(ip), str(accounting)])
The function PrintTestCases is in another file and use a match-case structure
def PrintTestCases(authentication, style, ip, accounting):
match accounting:
case "NOACC":
match [authentication, style, ip]:
case ['NONE', 'NONE', 'NONE']:
print("Test Case Number 1")
case _:
print("Wrong Test Case")
case "ACC":
match [authentication, style, ip]:
case ['PRIVATE', 'NONE', 'NONE']:
print( "Test Case Number 2")
case _:
print("Wrong Test Case")
Then I call the main script from a Jenkins pipeline like this
python3 -u main NONE NONE NONE ACC
But I always get this error
PrintTestCases() missing 3 required positional arguments: 'style', 'ip', and 'accounting'
Based on my understanding, I am passing the argument to the function via the sys.argv
Why the function does not see the required arguments?
答案1
得分: 3
您正在传递一个包含所有参数的列表。
注意这两者之间的区别。
PrintTestCases([str(authentication), str(style), str(ip), str(accounting)])
和
PrintTestCases(str(authentication), str(style), str(ip), str(accounting))
在第一种情况下，您正在传递一个单一的对象。请使用第二种方式。
PrintTestCases 需要 4 个不同的参数，但通过传递 [str(authentication), str(style), str(ip), str(accounting)]，实际上您只将此列表作为 authentication 参数传递，其他参数未填充。
英文:
You are passing a list that contains all the arguments.
Note how these two differ.
PrintTestCases([str(authentication), str(style), str(ip), str(accounting)])
and
PrintTestCases(str(authentication), str(style), str(ip), str(accounting))
In the first case, you're passing a single object. Use the second.
PrintTestCases is expecting 4 distincts arguments, but by passing [str(authentication), str(style), str(ip), str(accounting)] you're actually giving this list as the authentication argument alone, with the others unfilled.
答案2
得分: 1
你正在将一个列表作为输入传递，这被视为仅为第一个输入。您应该改为将它们作为参数传递给函数。将PrintTestCases([str(authentication), str(style), str(ip), str(accounting)])替换为PrintTestCases(str(authentication), str(style), str(ip), str(accounting))，它应该可以工作。
英文:
You are passing a list as the input, which is counted as only first input. You should instead pass them as arguments to the function. Replace the PrintTestCases([str(authentication), str(style), str(ip), str(accounting)]) with PrintTestCases(str(authentication), str(style), str(ip), str(accounting)) and it should work.
答案3
得分: 1
只是因为你将一个单一的列表传递给PrintTestCases函数。移除括号，问题就会解决。
英文:
It's just because you are passing a single list to the PrintTestCases function. Remove the brackets and it will be fixed.
答案4
得分: 0
为什么不使用 argparse 处理这些参数？你可以轻松地定义所需的参数，并将其中一些设置为可选。
import argparse
if __name__ == "__main__":
parser = argparse.ArgumentParser()
parser.add_argument("authentication", help="认证方法")
parser.add_argument("style", help="样式")
parser.add_argument("ip", help="IP 地址")
parser.add_argument("accounting", help="记账方法")
args = parser.parse_args()
PrintTestCases([str(args.authentication), str(args.style), str(args.ip), str(args.accounting)])
英文:
Why don't you use argparse for those args? You can define the args you need so easy and set some of them as optional if you need.
import argparse
if __name__ == "__main__":
parser = argparse.ArgumentParser()
parser.add_argument("authentication", help="The authentication method")
parser.add_argument("style", help="The style")
parser.add_argument("ip", help="The IP address")
parser.add_argument("accounting", help="The accounting method")
args = parser.parse_args()
PrintTestCases([str(args.authentication), str(args.style), str(args.ip), str(args.accounting)])
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