英文:
How to define current year as a variable in proc fedsql
问题
如何在proc fedsql中定义当前年份？我尝试过
%let td=%sysfunc(today(),date9.);
%put &td;
%let current_year = year(&td);
%put ¤t_year;
但它不会计算并且
%let td=%sysfunc(today(),date9.);
%put &td;
%let current_year = %eval(year(&td));
%put ¤t_year;
会给我一个错误ERROR: Required operator not found in expression: year(24JUL2023)
英文:
How can I define the current year in proc fedsql?
I tried
%let td=%sysfunc(today(),date9.);%put &td;%let current_year = year(&td);%put &current_year;
which doesn't evaluate and
%let td=%sysfunc(today(),date9.);%put &td;%let current_year = %eval(year(&td));%put &current_year;
which gives me the error
ERROR: Required operator not found in expression: year(24JUL2023)
答案1
得分: 1
使用 year(current_date)
proc fedsql;select year(current_date) as "年份", *from have;quit;
英文:
Use year(current_date)
proc fedsql;select year(current_date) as "year", *from have;quit;
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