英文:
Why can't typescript use string literals directly to compose an object type?
问题
以下是要翻译的内容：
我有一个文字类型，我想用它来组合一个对象的类型，而这个文字类型被用作对象的键，但是上面的写法不起作用。为什么上面会出错？
英文:
I have a literal type that I want to use to compose an object's type, and this literal type is used as a key for the object, but the following writing does not work correctly.
type k = "name";
type v = string;
type obj = {
[k]: v
}
Why does the above get an error?
答案1
得分: 1
要将字面量用作键，您应该使用[映射类型](https://www.typescriptlang.org/docs/handbook/2/mapped-types.html)：
type obj = {
[K in k]: v;
};
结果：
type obj = {
name: string;
}
英文:
To use literals as keys you should use mapped types:
type obj = {
[K in k]: v;
};
Result:
type obj = {
name: string;
}
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