英文:
Change numpy ndarray shape from 1d to multidimensi in python
问题
| df || --- || \[0,1,2\] || \[3,4,5\] |我想将它变成这样的表格：| df1 | df2 | df3 || --- | --- | --- || \[0\] | \[1\] | \[2\] || \[3\] | \[4\] | \[5\] |我尝试过仅针对一个数据，但在尝试对df中的所有数据进行操作时多次失败。这是我针对一个数据的代码：```pythondf1, df2, df3 = np.split(df.iloc[0], 3)
结果是：df1 = array([0], dtype=float32)，这是正确的，但没有涵盖所有的数据。
<details><summary>英文:</summary>| df || --- || \[0,1,2\] || \[3,4,5\] |and i want to make it as this table| df1 | df2 | df3 || --- | --- | --- || \[0\] | \[1\] | \[2\] || \[3\] | \[4\] | \[5\] |i have tried just for one data and failed several times while i tried for all data in dfthis my code for one datadf1,df2,df3 = np.split(df.iloc\[0\].3) the result was df1 = array(\[0\], dtype=float32)it was right but didnt cover all the data</details># 答案1**得分**: 1如果您的列表中的项目数量是固定的，例如根据您上面的示例为3个，您可以使用以下代码：```pythondf[['df1', 'df2', 'df3']] = pd.DataFrame(df.df.tolist(), index=df.index)
然后删除原始列：
df.drop(columns=['df'], inplace=True)
df1 df2 df30 0 1 21 3 4 5
英文:
If your number of items in the list is fixed, i.e. 3 as per your example above, you can use:
df[['df1','df2', 'df3']] = pd.DataFrame(df.df.tolist(), index= df.index)
Then drop the original column:
df.drop(columns=['df'], inplace = True)df1 df2 df30 0 1 21 3 4 5
答案2
得分: 0
你可以通过Pandas（Python数据分析库）来实现这个，以下是代码：
import pandas as pddata = [[0, 1, 2], [3, 4, 5]]df = pd.DataFrame(data)df.columns = [f"df{i+1}" for i in range(len(df.columns))]print(df)
英文:
You can do this via Pandas (Python Data Analysis Library), here is the code below:
import pandas as pddata = [[0, 1, 2], [3, 4, 5]]df = pd.DataFrame(data)df.columns = [f"df{i+1}" for i in range(len(df.columns))]print(df)
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