在MySQL中将内连接查询结果与选择查询结果合并。

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英文:

Combining inner join query result with select query result in Mysql

问题

我正在使用MySQL。我需要将一个连接查询结果与另一个选择查询结果合并。详细信息如下:

表一 "TaskCategory" 具有以下列:

cat_id
parent_id
name
type

我将类别任务和子类别任务都存储在同一张表中。类别任务的 parent_id 为 0,而子类别任务的 parent_id 为其类别 id。

我有另一张表 TaskCategoryMeta。该表具有以下列:

cat_id
meta_name
meta_value

只有子类别会在 TaskCategoryMeta 表中有行/条目。

在结果中,我需要具有 TaskCategoryMeta 表中特定 meta 名称和 meta 值的子类别,以及 TaskCategory 表中父 id 为 0 的所有类别。

我尝试了下面的查询,但出现了查询中断错误,请帮助我实现我的结果。

SELECT * 
FROM TaskCategory
INNER JOIN TaskCategoryMeta
ON TaskCategory.cat_id = TaskCategoryMeta.cat_id
WHERE TaskCategoryMeta.meta_name = 'HR_DEPT_SUPPORT'
AND TaskCategoryMeta.meta_value = 1 
UNION
SELECT * FROM TaskCategory WHERE TaskCategory.parent_id = 0 AND type = 1
英文:

I am using MySQl.I need to combine one join query result with another select query result. The details are,

Table one "TaskCategory" has below columns

cat_id
parent_id
name
type

I am storing both category task and subcategory tasks in same table. The category task would have parent_id as 0 and subcategory task would parent_id as the id of it's category id

I have another table TaskCategoryMeta. This table has below columns

cat_id,
meta_name.
meta_value

Only subcategories would have rows/entries in the TaskCategoryMeta table.

In the result I need the subcategories with certain meta name and meta value in TaskCategoryMeta table and all categories with parent id of 0 from TaskCategory table.

I tried below query but I got query interrupted error, please help me to achieve my result.

SELECT * 
FROM TaskCategory
INNER JOIN TaskCategoryMeta
ON TaskCategory.cat_id = TaskCategoryMeta.cat_id where TaskCategoryMeta.cat_meta_name='HR_DEPT_SUPPORT'
and TaskCategoryMeta.cat_meta_value=1 
UNION
select * from TaskCategory where TaskCategory.cat_parent_id=0 and cat_type=1

答案1

得分: 1

不需要2个查询,但我认为你需要在where子句内有2个“部分”。要做到这一点,你需要使用括号将条件“绑定”在一起,然后在这2个部分之间引入一个“OR”。请注意,缩进总是有助于更容易理解括号包含的内容,例如:

SELECT *
FROM TaskCategory
LEFT JOIN TaskCategoryMeta ON TaskCategory.cat_id = TaskCategoryMeta.cat_id
WHERE (
        TaskCategoryMeta.cat_meta_name = 'HR_DEPT_SUPPORT'
        AND TaskCategoryMeta.cat_meta_value = 1
        )
    OR (
        TaskCategory.cat_parent_id = 0
        AND cat_type = 1 -- 你没有告诉我们这个字段来自哪个表
        )

正如Swifty在下面的评论中指出的那样,你不能使用内连接,因为元数据表中只有子类别任务(对我来说这似乎是一个奇怪的设计特点)。因此,改为使用左(外)连接允许类别任务出现在结果中。

请注意,cat_type 应该由源表名称前缀。

英文:

You don't need 2 queries, but I believe you need 2 "sections" within the where clause. To do that you need to "bind" conditions together using parentheses, and, then introduce an OR between the 2 sections. Note it is always helpful to indent so it is easier to understand what the parentheses contain e.g:

SELECT *
FROM TaskCategory
LEFT JOIN TaskCategoryMeta ON TaskCategory.cat_id = TaskCategoryMeta.cat_id
WHERE (
        TaskCategoryMeta.cat_meta_name = 'HR_DEPT_SUPPORT'
        AND TaskCategoryMeta.cat_meta_value = 1
        )
    OR (
        TaskCategory.cat_parent_id = 0
        AND cat_type = 1 -- you haven't told us which table this comes from
        )

As Swifty points out in a comment below, you can't use an inner join as only subcategory tasks are present in the meta table (which to me seems an odd design feature). So, instead, a left (outer) join allows for category tasks to be present in the results.

Please note cat_type should be prefixed by the source table name

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  • 本文由 发表于 2023年7月23日 20:22:26
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