Dart – 创建新对象会改变旧对象

huangapple go评论82阅读模式
英文:

Dart - Creating new objects changes old objects

问题

在DartPad中运行这段代码,为什么对象a会被后续的声明和实例化相同对象类型的操作更新?如何防止第一个对象被更新?

void main() {
  SampleClass a = SampleClass(publicParam: 'A');
  print('1. a: ${a.getPrivateProperty}');

  SampleClass b = SampleClass(publicParam: 'B');
  print('2. a: ${a.getPrivateProperty}');
  print('3. b: ${b.getPrivateProperty}');

  SampleClass(publicParam: 'C');
  print('4. a: ${a.getPrivateProperty}');
  print('5. b: ${b.getPrivateProperty}');
}

class SampleClass {
  final String publicParam;
  static late String _privateProperty;

  SampleClass({
    required this.publicParam,
  }) {
    _privateProperty = publicParam;
  }

  // Getter
  String get getPrivateProperty => _privateProperty;
}

输出结果:

1. a: A
2. a: B
3. b: B
4. a: C
5. b: C

有人可以详细帮助我吗?非常感谢。我认为这与构造函数有关,但我不太确定。

答:这个问题的原因在于 _privateProperty 是一个 static 静态变量,它属于整个类而不是类的实例。因此,每次你创建一个新的 SampleClass 实例时,都会更新 _privateProperty 的值,因为构造函数中将它设置为了 publicParam 的值。

要解决这个问题,你可以将 _privateProperty 改为实例变量而不是静态变量,这样每个对象都会有自己的 _privateProperty 值,而不会相互影响。代码如下所示:

class SampleClass {
  final String publicParam;
  late String _privateProperty;

  SampleClass({
    required this.publicParam,
  }) {
    _privateProperty = publicParam;
  }

  // Getter
  String get getPrivateProperty => _privateProperty;
}

通过这样的修改,你将能够防止第一个对象被后续对象更新,并且每个对象都会保持其独立的 _privateProperty 值。

英文:

Running this in DartPad, why does object a get updated by succeeding declarations and instantiations of the same object type? How do I prevent the first objects from being updated?

void main() {
  SampleClass a = SampleClass(publicParam: 'A');
  print('1. a: ${a.getPrivateProperty}');

  SampleClass b = SampleClass(publicParam: 'B');
  print('2. a: ${a.getPrivateProperty}');
  print('3. b: ${b.getPrivateProperty}');

  SampleClass(publicParam: 'C');
  print('4. a: ${a.getPrivateProperty}');
  print('5. b: ${b.getPrivateProperty}');
}

class SampleClass {
  final String publicParam;
  static late String _privateProperty;

  SampleClass({
    required this.publicParam,
  }) {
    _privateProperty = publicParam;
  }

  // Getter
  String get getPrivateProperty => _privateProperty;
}

Output:

1. a: A
2. a: B
3. b: B
4. a: C
5. b: C

Can someone please help me as detailed as possible? Thank you so much. I think it's got to do with the constructor but I'm not really sure.

答案1

得分: 1

原因是您的_privateProperty属性是静态的,这意味着它在类的所有实例之间共享。

我不知道您为什么要另外添加一个私有属性,但假设您需要它,我会像这样重写您的类:

class SampleClass {
  final String publicParam;

  final String _privateProperty;

  SampleClass({
    required this.publicParam,
  }) : _privateProperty = publicParam;

  // Getter
  String get getPrivateProperty => _privateProperty;
}
英文:

The cause is that your _privateProperty property is static, which means it is shared across all instances of the class.

I do not know your motivation of having another private property, but assuming you need it I would rewrite your class like this:

class SampleClass {
  final String publicParam;

  final String _privateProperty;

  SampleClass({
    required this.publicParam,
  }) : _privateProperty = publicParam;

  // Getter
  String get getPrivateProperty => _privateProperty;
}

huangapple
  • 本文由 发表于 2023年7月23日 17:59:46
  • 转载请务必保留本文链接:https://go.coder-hub.com/76747635.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定