英文:
How to listen on a server-side websocket non-blocking in Go
问题
我使用https://pkg.go.dev/golang.org/x/net/websocket来创建一个服务器端的websocket。所有的通信都是通过JSON进行的。因此，我的代码包含以下内容：
func wsHandler(ws *websocket.Conn) {var evnt eventwebsocket.JSON.Receive(ws, &evnt)…}
然而，这个代码会一直阻塞，直到客户端关闭连接。我知道这个websocket包是在context出现之前发布的（我也知道有更新的websocket包），但是，难道真的没有一种非阻塞的方式来等待传入的帧吗？
英文:
I use https://pkg.go.dev/golang.org/x/net/websocket for creating a server-side websocket. All communication through it is in JSON. Thus, my code contains:
func wsHandler(ws *websocket.Conn) {var evnt eventwebsocket.JSON.Receive(ws, &evnt)…
However, this blocks until the connection is closed by the client. I know that this websocket package pre-dates context (and I know that there are newer websocket packages), still – is there really no way to wait for incoming frames in a non-blocking way?
答案1
得分: 1
这个代码块会阻塞，直到客户端关闭连接。
处理并发阻塞操作的最简单方法是使用goroutine。与进程或线程不同，goroutine基本上是“免费的”。
func wsHandler(ws *websocket.Conn) {go func() {var evnt eventwebsocket.JSON.Receive(ws, &evnt)....}()}
英文:
> this blocks until the connection is closed by the client.
The easiest way to handle concurrent blocking operations is to give them a goroutine. Goroutines, unlike processes or threads, are essentially "free".
func wsHandler(ws *websocket.Conn) {go func() {var evnt eventwebsocket.JSON.Receive(ws, &evnt)....}()}
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