显示多列而不需要逐个设置它们。

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英文:

Show many columns without setting them individually

问题

我们有一个具有许多列的SQL表,在网站(asp.net)的不同选项卡中显示它们。目前我们为每一列设置一个标签,这需要很多时间。

有没有一种更高效的方法来做这个?

我们尝试自动遍历所有列,并为每一列创建一个标签,但这并没有达到预期效果,因为列的顺序与需要显示的顺序不同。

英文:

We have a SQL table with many columns, and we show them in different tabs in a web site (asp.net). Right now we set a lable for each column, and it takes a lot of time.

Is there way to do this more efficiently somehow?

We tried to go automatically through all the column and create a label for each one, but it didn't do the job because a order of the columns is not as the order that need to be shown.

显示多列而不需要逐个设置它们。

答案1

得分: 1

以下是翻译好的部分:

在大多数情况下,通常取决于您在想要显示此类代码之前是否“知道”列名,或者不知道?

但是,即使在这种情况下(您不会真的提前知道列名),GridView 控件也可以很好地工作。

所以,比如要显示一些酒店?

我们有以下标记:

<asp:GridView ID="GridView1" runat="server" Width="50%" CssClass="table">
</asp:GridView>

有了上面的标记,我们现在可以发送任何我们希望的表格数据。

列将自动为我们生成。

加载 GridView 的代码 - 页面加载事件如下:

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load

    If Not IsPostBack Then
        LoadGrid
    End If

End Sub

Sub LoadGrid()

    GridView1.DataSource =
        MyRst("SELECT * FROM VhotelsA ORDER BY HotelName")
    GridView1.DataBind()

End Sub

结果如下:

显示多列而不需要逐个设置它们。

然而,通常(希望如此!),您确实提前知道列名。

因此,我们可以这样创建 GridView:

<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" 
    DataKeyNames="ID" CssClass="table" width="50%">
    <Columns>
        <asp:BoundField DataField="Fighter" HeaderText="Fighter"  />
        <asp:BoundField DataField="Engine" HeaderText="Engine"  />
        <asp:BoundField DataField="Thrust" HeaderText="Thrust"  />
        <asp:BoundField DataField="Description" HeaderText="Description" />
        <asp:TemplateField HeaderText="Preview">
            <ItemTemplate>
                <asp:Image ID="Image1" runat="server" ImageUrl='<%# Eval("ImagePath") %>'
                    Height="68px" Width="149px"/> 
            </ItemTemplate>
        </asp:TemplateField>
    </Columns>
</asp:GridView>

以上的优点是我们可以定义列标题,并且实际的数据库列可以与我们定义的列标题不同。

加载它的代码如下:

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
    If Not IsPostBack Then
        LoadGrid()
    End If
End Sub

Sub LoadGrid()

    Dim strSQL As String =
            "SELECT * FROM Fighters"

    GridView1.DataSource = MyRst(strSQL)
    GridView1.DataBind()

End Sub

请注意,在上面的标记中,我们向 GridView 添加了一个图像控件。

所以,现在的结果如下:

显示多列而不需要逐个设置它们。

因此,使用 GridView 允许您提供数据,并且它可以“即时”为您生成列。

或者,如第二个示例所示?

您可以定义要显示的列,即使您将许多列传递给 GridView,包括不显示的列。

如果您不是在寻找表格视图,而是在寻找数据旁边的“许多”标签?

那么您可以尝试使用 DetailsView。

比如这个标记:

<asp:DetailsView ID="DetailsView" runat="server"  width="25%" CssClass="table">
</asp:DetailsView>

加载此数据的代码与上述相同(该控件一次只呈现一条记录)。

因此,以上的结果如下:

显示多列而不需要逐个设置它们。

因此,以上生成了每列的标签。

请注意,在上面的示例中,我使用了一个“辅助”例程,根据给定的 SQL 返回数据表。

这个非常有用的例程是这样的:

Public Function MyRst(strSQL As String) As DataTable

    Dim rstData As New DataTable
    Using conn As New SqlConnection(My.Settings.TEST4)
        Using cmdSQL As New SqlCommand(strSQL, conn)
            conn.Open()
            rstData.Load(cmdSQL.ExecuteReader)
            rstData.TableName = strSQL
        End Using
    End Using
    Return rstData
End Function

编辑:基于选项卡或 RB 选择隐藏或显示列

因此,根据选项卡控件选择来隐藏或显示列?

嗯,我不知道您正在使用哪个选项卡控件(它看起来像 jQuery 的一个)。

但是,现在,让我们只使用一个 RadioButtonList 控件。

对于 GridView 标记,我们将具有一些模板列和一些数据绑定列。

所以,这里的思路是根据每个选项卡选择“定义”一列列表。

因此,具有我们的“伪”选项卡控件(我经常使用 RadioButtonList)的标记如下:

<div style="width:60%">

    <asp:RadioButtonList ID="MyTabs" runat="server" CssClass="rMyChoice"
        Style="float: right"
        RepeatDirection="Horizontal" AutoPostBack="true"
        OnSelectedIndexChanged="MyTabs_SelectedIndexChanged">

            <asp:ListItem Value="0" Selected="True">Tab1</asp:ListItem>
            <asp:ListItem Value="1">Tab 2</asp:ListItem>
            <asp:ListItem Value="2">Tab 3</asp:ListItem>

    </asp:RadioButtonList>
    <br />

    <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False"
        DataKeyNames="ID" CssClass="table">
        <Columns>
            <asp:BoundField DataField="Fighter" HeaderText="Fighter" />
            <asp:BoundField DataField="Engine" HeaderText="Engine" />
            <asp:BoundField DataField="Thrust" HeaderText="Thrust" />
            <asp:BoundField DataField="Description" HeaderText="Description" />
            <asp:TemplateField HeaderText="Preview">
                <ItemTemplate>
                    <asp:Image ID="Image2" runat="server" ImageUrl='<%# Eval("ImagePath") %>' Width="140" />
                </ItemTemplate>
            </asp:TemplateField>
            <asp:BoundField DataField="FirstFlight" HeaderText="First Flight"
                DataFormatString="{0:MMM-dd-yyyy}" ItemStyle-Width="110px" />
        </Columns>
    </asp:GridView>
</div>

现在我们的

英文:

Well, in most cases, it often depends if you "know" the column name(s) before wanting to display such code, or not?

However, even in such cases (that you not really going to know ahead of time the column names)?

A GridView control works rather well.

So, say to display some hotels?

We have this markup:

&lt;asp:GridView ID=&quot;GridView1&quot; runat=&quot;server&quot; Width=&quot;50%&quot; CssClass=&quot;table&quot;&gt;
&lt;/asp:GridView&gt;

With above markup, we can now send the above any table data we wish.

The columns will automatic be generated for us.

Code to load the GridView - page load event is thus this:

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load

    If Not IsPostBack Then
        LoadGrid
    End If

End Sub

Sub LoadGrid()

    GridView1.DataSource =
        MyRst(&quot;SELECT * FROM VhotelsA ORDER BY HotelName&quot;)
    GridView1.DataBind()


End Sub

And the result is now this:

显示多列而不需要逐个设置它们。

However, often (hopefully!!!), you do know the columns ahead of time.

Thus, we can create the GridView like this:

&lt;asp:GridView ID=&quot;GridView1&quot; runat=&quot;server&quot; AutoGenerateColumns=&quot;False&quot; 
    DataKeyNames=&quot;ID&quot; CssClass=&quot;table&quot; width=&quot;50%&quot;&gt;
    &lt;Columns&gt;
        &lt;asp:BoundField DataField=&quot;Fighter&quot; HeaderText=&quot;Fighter&quot;  /&gt;
        &lt;asp:BoundField DataField=&quot;Engine&quot; HeaderText=&quot;Engine&quot;  /&gt;
        &lt;asp:BoundField DataField=&quot;Thrust&quot; HeaderText=&quot;Thrust&quot;  /&gt;
        &lt;asp:BoundField DataField=&quot;Description&quot; HeaderText=&quot;Description&quot; /&gt;
        &lt;asp:TemplateField HeaderText=&quot;Preview&quot;&gt;
            &lt;ItemTemplate&gt;
            &lt;asp:Image ID=&quot;Image1&quot; runat=&quot;server&quot; ImageUrl = &#39;&lt;%# Eval(&quot;ImagePath&quot;) %&gt;&#39;
                Height=&quot;68px&quot; Width=&quot;149px&quot;/&gt; 
            &lt;/ItemTemplate&gt;
        &lt;/asp:TemplateField&gt;
    &lt;/Columns&gt;
&lt;/asp:GridView&gt;

The advantages of above, is we can define a column heading, and the actual database columns can be different then the column headings we define.

The code to load above is this:

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
    If Not IsPostBack Then
        LoadGrid()
    End If
End Sub

Sub LoadGrid()


    Dim strSQL As String =
            &quot;SELECT * FROM Fighters&quot;

    GridView1.DataSource = MyRst(strSQL)
    GridView1.DataBind()


End Sub

And note close in the above markup, we added an image control to the GridView.

So, the results are now this:

显示多列而不需要逐个设置它们。

So, using a GridView allows you to feed it data, and it can "on the fly" generate the columns for you.

Or, as the 2nd example shows?

You can define the columns that will display, and this works EVEN when you pass many columns to the GridView, including columns that will not be displayed.

If you not looking for a table view, but looking for "many" labels on the side of the data?

Then you can try a DetailsView.

Say this markup:

        &lt;asp:DetailsView ID=&quot;DetailsView&quot; runat=&quot;server&quot;  width=&quot;25%&quot; 
            CssClass=&quot;table&quot;&gt;
        &lt;/asp:DetailsView&gt;

Code to load this data is same as above (that control only renders one reocrd at a time).

The result of above is thus this:

显示多列而不需要逐个设置它们。

So, above generated the label for each column.

Note that in the above examples, I used a "helper" routine to return a data table based on the given SQL.

That rather useful routine was this:

Public Function MyRst(strSQL As String) As DataTable


    Dim rstData As New DataTable
    Using conn As New SqlConnection(My.Settings.TEST4)
        Using cmdSQL As New SqlCommand(strSQL, conn)
            conn.Open()
            rstData.Load(cmdSQL.ExecuteReader)
            rstData.TableName = strSQL
        End Using
    End Using
    Return rstData
End Function

Edit: Hide or show columns based on tab or RB selection

So, to hide, or show columns based on that tab control selection?

Well, I don't know which tab control you are using (it looks like the jQuery one).

However, for now, let's just use a RadioButtonList control.

And for the GridView markup, we will have both templated columns, and some data bound columns.

So, the idea here is to "define" a list of columns for each tab selected.

So, the markup with our "fake" tab control (I often use a Radio Button list) is this:

&lt;div style=&quot;width:60%&quot;&gt;

    &lt;asp:RadioButtonList ID=&quot;MyTabs&quot; runat=&quot;server&quot; CssClass=&quot;rMyChoice&quot;
        Style=&quot;float: right&quot;
        RepeatDirection=&quot;Horizontal&quot; AutoPostBack=&quot;true&quot;
        OnSelectedIndexChanged=&quot;MyTabs_SelectedIndexChanged&quot;&gt;

            &lt;asp:ListItem Value=&quot;0&quot; Selected=&quot;True&quot;&gt;Tab1&lt;/asp:ListItem&gt;
            &lt;asp:ListItem Value=&quot;1&quot;&gt;Tab 2&lt;/asp:ListItem&gt;
            &lt;asp:ListItem Value=&quot;2&quot;&gt;Tab 3&lt;/asp:ListItem&gt;

    &lt;/asp:RadioButtonList&gt;
    &lt;br /&gt;

    &lt;asp:GridView ID=&quot;GridView1&quot; runat=&quot;server&quot; AutoGenerateColumns=&quot;False&quot;
        DataKeyNames=&quot;ID&quot; CssClass=&quot;table&quot;&gt;
        &lt;Columns&gt;
            &lt;asp:BoundField DataField=&quot;Fighter&quot; HeaderText=&quot;Fighter&quot; /&gt;
            &lt;asp:BoundField DataField=&quot;Engine&quot; HeaderText=&quot;Engine&quot; /&gt;
            &lt;asp:BoundField DataField=&quot;Thrust&quot; HeaderText=&quot;Thrust&quot; /&gt;
            &lt;asp:BoundField DataField=&quot;Description&quot; HeaderText=&quot;Description&quot; /&gt;
            &lt;asp:TemplateField HeaderText=&quot;Preview&quot;&gt;
                &lt;ItemTemplate&gt;
                    &lt;asp:Image ID=&quot;Image2&quot; runat=&quot;server&quot; ImageUrl=&#39;&lt;%# Eval(&quot;ImagePath&quot;) %&gt;&#39; Width=&quot;140&quot; /&gt;
                &lt;/ItemTemplate&gt;
            &lt;/asp:TemplateField&gt;
            &lt;asp:BoundField DataField=&quot;FirstFlight&quot; HeaderText=&quot;First Flight&quot;
                DataFormatString=&quot;{0:MMM-dd-yyyy}&quot; ItemStyle-Width=&quot;110px&quot; /&gt;
        &lt;/Columns&gt;
    &lt;/asp:GridView&gt;

And now our code

Dim ShowColumns As New List(Of String)
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load

    ShowColumns.Add(&quot;0,1,2&quot;)    &#39; show columns for Tab1
    ShowColumns.Add(&quot;0,1,2,3&quot;)    &#39; show columns for Tab2
    ShowColumns.Add(&quot;0,1,2,3,4,5&quot;)    &#39; show columns for Tab3


    If Not IsPostBack Then
        LoadGrid
    End If

End Sub

Sub LoadGrid()

    For i = 0 To GridView1.Columns.Count - 1
        GridView1.Columns(i).Visible = True
    Next

    GridView1.DataSource = MyRst(&quot;SELECT * FROM Fighters ORDER BY Fighter&quot;)
    GridView1.DataBind()

    &#39; hide/show columns based on current tab selection
    Dim MyCols As String() = ShowColumns(MyTabs.SelectedIndex).Split(&quot;,&quot;)
    For i = 0 To GridView1.Columns.Count - 1
        GridView1.Columns(i).Visible = MyCols.Contains(i)
    Next

End Sub

Protected Sub MyTabs_SelectedIndexChanged(sender As Object, e As EventArgs)

    LoadGrid()

End Sub

And the result is this:

显示多列而不需要逐个设置它们。

Note VERY close the code to un-hide the grid before we data bind it again.

This code:

    For i = 0 To GridView1.Columns.Count - 1
        GridView1.Columns(i).Visible = True
    Next

We MUST do this each time, since if a column has been set visible=false, then the settings persist, and .net will NOT render such columns. So, if we bind the grid with the column visible = false?
Then that column is not rendered, and that is the case EVEN when we re-bind the GridView. This is certainly an unexpected behavior, and one that the above code will address. In effect, we want all columns with visible = true BEFORE the data bind, or in this case the data re-binding.

So, we have to each time turn back on the visible of all rows, and THEN hide them after the databinding is completed.

Since the columns are then to about to be hidden (perhaps again)? Then that markup is not sent to the client side anyway, so from performance point of view, this approach is just fine.

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  • 本文由 发表于 2023年7月20日 20:37:17
  • 转载请务必保留本文链接:https://go.coder-hub.com/76729964.html
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