问题

我需要避免在将元素推入数组时使用'any'作为类型定义。我尝试提供类型但出现了错误。以下是示例代码：

interface answerProps {
    state: string;
    answer: string;
}

const results: Array<string> = [];
!isEmpty(answers) && answers.map((item: any) => results.push(`${item.state} : ${item.answer}`));

根据上述代码，我希望在映射数组元素时避免使用'any'。

interface answerProps {
    state: string;
    answer: string;
  }

  const results: Array<string> = [];
  !isEmpty(answers) &&
    answers.map((item: any) => results.push(`${item.state} : ${item.answer}`));

答案1

得分: 1

只需在映射数组时使用answerProps接口。

interface answerProps {
  state: string;
  answer: string;
}

const results: Array<string> = [];
!isEmpty(answers) && answers.map((item: answerProps) => results.push(`${item.state} : ${item.answer}`));

interface answerProps {
  state: string;
  answer: string;
}

const results: Array<string> = [];
!isEmpty(answers) &&
  answers.map((item: answerProps) => results.push(`${item.state} : ${item.answer}`));

答案2

得分: 0

interface answerProps {
  state: string;
  answer: string;
}

const answers: answerProps[] = [];
const results = answers.map(item => `${item.state} : ${item.answer}`);

note 1
有两种方式可以进行类型数组的类型转换。对于我的示例，我主要使用了第二种类型转换方法

• const arr1: Array<string>
• const arr2: string[]

note 2
在你提供的示例中，array.map 不是正确的方法，尝试使用 array.forEach 代替

note 3
当正确使用array.map时，TypeScript可以自动识别结果类型，并且非常适用于避免手动将类型转换为变量

note 4
（这仅仅是个人偏好）与其防范空数组，尝试重构你的代码，使其接受空数组作为有效输入。在我上面提供的示例中，一个空的 answers 将映射为一个空的 results

<details>
<summary>英文:</summary>

```typescript
interface answerProps {
  state: string;
  answer: string;
}

const answers: answerProps[]  = []
const results = answers.map(item =&gt; `${item.state} : ${item.answer}`);

note 1
there are 2 ways of casting a typed array. For my example, I mainly used the 2nd casting method

• const arr1: Array<string>
• const arr2: string[]

note 2
in your given sample, array.map is not the correct method to use, try using array.forEach instead

note 3
array.map when used correctly, allows typescript to automatically identify the resulted type, and is great to avoid manually casting type to variables

note 4
(this is purely preferences) rather then guarding against empty array, try to refactor your code so that it will accepts empty array as valid. In the example I have given above, an empty answers will gets mapped to an empty results

答案3

得分: 0

只返回翻译好的部分：

const results: Array<string> = [];
!isEmpty(answers) && answers.map((item: answerProps ) => results.push(`${item.state} : ${item.answer}`));

如果仍然显示错误，请尝试为数组提供数据类型，如定义数组 `let answers:answerProps[]` 或 `answers as answerProps[]`。但请确保具有相同类型的数据。

顺便说一下，在定义类或接口时，请使用大写字母开头

例如：`AnswerProps`

const results: Array<string> = [];
  !isEmpty(answers) &&
    answers.map((item: answerProps ) => results.push(`${item.state} : ${item.answer}`));